Alcohols,phenols, ethers
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Alcohols,phenols, ethers






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Alcohols,phenols, ethers Alcohols,phenols, ethers Presentation Transcript

  •  Alcohols and phenols are formed when a hydrogen atom in a hydrocarbon, aliphatic and aromatic respectively, is replaced by –OH group. An alcohol contains one or more hydroxyl (OH) group(s) directly attached to carbon atom(s), of an aliphatic system (CH3OH) while a phenol contains –OH group(s) directly attached to carbon atom(s) of an aromatic system (C6H5OH).
  •  The subsitution of a hydrogen atom in a hydrocarbon by an alkoxy or aryloxy group(R–O/Ar–O) yields another class of compounds known as ‘ethers’, for example, CH3OCH3 .
  •  Alcohols and phenols may be classified as mono–, di–, tri- or polyhydric compounds depending on whether they contain one, two, three or many hydroxyl groups respectively.
  •  Monohydric alcohols may be further classified according to the hybridisation of the carbon atom to which the hydroxyl group is attached. (i) Compounds containing C sp 3− OH bond: Primary, secondary and tertiary alcohols :
  •  Allylic alcohols: In these alcohols, the —OH group is attached to a sp3 hybridised carbon next to the carbon-carbon double bond, that is to an allylic carbon.
  •  Benzylic alcohols: In these alcohols, the —OH group is attached to a sp3—hybridised carbon atom next to an aromatic ring.
  •  (ii) Compounds containing C sp 2− OH bond: These alcohols contain —OH group bonded to a carbon-carbon double bond i.e., to a vinylic carbon or to an aryl carbon. These alcohols are also known as vinylic alcohols.
  •  Ethers are classified as simple or symmetrical, if the alkyl or aryl groups attached to the oxygen atom are the same, and mixed or unsymmetrical, if the two groups are different. Diethyl ether,C2H5OC2H5, is a symmetrical ether whereas C2H5OCH3 and C2H5OC6H5 are unsymmetrical ethers.
  •  (a) Alcohols: The common name of an alcohol is derived from the common name of the alkyl group and adding the word alcohol to it. For example, CH3OH is methyl alcohol.
  •  The name of an alcohol is derived from the name of the alkane from which the alcohol is derived, by substituting ‘e’ of alkane with the suffix ‘ol’. The position of substituents are indicated by numerals. For this, the longest carbon chain (parent chain) is numbered starting at the end nearest to the hydroxyl group.
  •  The positions of the –OH group and other substituents are indicated by using the numbers of carbon atoms to which these are attached. For naming polyhydric alcohols, the ‘e’ of alkane is retained and the ending ‘ol’ is added. The number of –OH groups is indicated by adding the multiplicative prefix, di, tri, etc., before ‘ol’. The positions of –OH groups are indicated by appropriate locants e.g., HO–CH2–CH2–OH is named as ethane–1, 2-diol.
  •  Cyclic alcohols are named using the prefix cyclo and considering the —OH group attached to C–1.
  •  The simplest hydroxy derivative of benzene is phenol. It is its common name and also an accepted IUPAC name. As structure of phenol involves a benzene ring, in its substituted compounds the terms ortho (1,2- disubstituted), meta (1,3-disubstituted) and para (1,4- disubstituted) are often used in the common names.
  •  Common names of ethers are derived from the names of alkyl/ aryl groups written as separate words in alphabetical order and adding the word ‘ether’ at the end. For example, CH3OC2H5 is ethylmethyl ether.
  •  In alcohols, the oxygen of the –OH group is attached to carbon by a sigma (σ ) bond formed by the overlap of a sp3 hybridised orbital of carbon with a sp3 hybridised orbital of oxygen.
  •  The bond angle in alcohols is slightly less than the tetrahedral angle (109°-28′). It is due to the repulsion between the unshared electron pairs of oxygen. In phenols, the –OH group is attached to sp2 hybridised carbon of an aromatic ring. The carbon– oxygen bond length (136 pm) in phenol is slightly less than that in methanol. This is due to (i) partial double bond character on account of the conjugation of unshared electron pair of oxygen with the aromatic ring (ii) sp2 hybridised state of carbon to which oxygen is attached.
  •  In ethers, the four electron pairs, i.e., the two bond pairs and two lone pairs of electrons on oxygen are arranged approximately in atetrahedral arrangement. The bond angle is slightly greater than the tetrahedral angle due to the repulsive interaction between the two bulky (–R) groups. The C–O bond length (141 pm) is almost the same as in alcohols.
  •  1. From alkenes (i) By acid catalysed hydration: Alkenes react with water in the presence of acid as catalyst to form alcohols. In case of unsymmetrical alkenes, the addition reaction takes place in accordance with Markovnikov’s rule .
  •  Diborane (BH3)2 reacts with alkenes to give trialkyl boranes as addition product. This is oxidised to alcohol by hydrogen peroxide in the presence of aqueous sodium hydroxide. The addition of borane to the double bond takes place in such a manner that the boron atom gets attached to the sp2 carbon carrying greater number of hydrogen atoms. The alcohol so formed looks as if it has been formed by the addition of water to the alkene in a way opposite to the Markovnikov’s rule. In this reaction, alcohol is obtained in excellent yield.
  •  (i) By reduction of aldehydes and ketones: Aldehydes and ketones are reduced to the corresponding alcohols by addition of hydrogen in the presence of catalysts (catalytic hydrogenation). The usual catalyst is a finely divided metal such as platinum, palladium or nickel. It is also prepared by treating aldehydes and ketones with sodium borohydride (NaBH4) or lithium aluminium hydride (LiAlH4). Aldehydes yield primary alcohols whereas ketones give secondary alcohols.
  •  (ii) By reduction of carboxylic acids and esters: Carboxylic acids are reduced to primary alcohols in excellent yields by lithium aluminium hydride, a strong reducing agent. However, LiAlH4 is an expensive reagent, and therefore, used for preparing special chemicals only. Commercially, acids are reduced to alcohols by converting them to the esters , followed by their reduction using hydrogen in the presence of catalyst (catalytic hydrogenation).
  •  Alcohols are produced by the reaction of Grignard reagents with aldehydes and ketones. The first step of the reaction is the nucleophilic addition of Grignard reagent to the carbonyl group to form an adduct. Hydrolysis of the adduct yields an alcohol.
  •  Give the structures and IUPAC names of the products expected from the following reactions: (a) Catalytic reduction of butanal. (b) Hydration of propene in the presence of dilute sulphuric acid. (c) Reaction of propanone with methyl magnesium bromide followedM by hydrolysis.
  • 1. From haloarenes Chlorobenzene is fused with NaOH at 623K and 320 atmospheric pressure. Phenol is obtained by acidification of sodium phenoxide so produced .
  • 2. From benzenesulphonic acid Benzene is sulphonated with oleum and benzene sulphonic acid so formed is converted to sodium phenoxide on heating with molten sodium hydroxide. Acidification of the sodium salt gives phenol.
  • 3. From diazonium salts A diazonium salt is formed by treating an aromatic primary amine with nitrous acid (NaNO2 + HCl) at 273-278 K. Diazonium salts are hydrolysed to phenols by warming with water.
  •  4. From cumene Phenol is manufactured from the hydrocarbon, cumene. Cumene (iso propylbenzene) is oxidised in the presence of air to cumene hydroperoxide.
  • 2.1 Boiling point of Alcohols of alcohols are much higher than hydrocarbons of similar Mr presence of intermolecular hydrogen bonds between alcohol moleculesCompound Formula Mr δ+ H δ- O R Ethanol C2H5OH 46 +78 δ+ H δ- O Hydrogen bond δ+ δ- R H OPropane C3H8 44 -42 R Much higher b. pt
  • No. of hydroxyl grps present in the molecule B. pt Alcohol Formula Mr / oC b.p. of alcohols increase with number of –OH grps present Ethanol CH3CH2OH 46 +78 the greater the no. of CH2(OH)CH2OH –OH grps Ethane-1,2-diol 62 +197 the more extensive Propanol CH3CH2CH2OH 60 +97 the H-bonds CH2(OH)CH2(OH)CH2OHPropan-1,2,3-triol 93 +290
  • No. of electrons present in the moleculeb.p. of alcohols increasewith total no. of Boilingelectrons present Alcohol Formula Mr pt / oC Larger electron cloud Methanol CH3OH 32 +65 more easily distorted Ethanol CH3CH2OH 46 +78stronger Van der Waals’ forces between the Propanol CH3CH2CH2OH 60 +97 molecules
  • Degree of branching present in molecule b. p. of alcohols decrease with in / branching of chain Isomeric Alcohols Formula oC CH3CH2CH2CH2OH Butan-1-ol increase +118 more spherical in branching (CH3)2CHCH2OHsmaller surface area of 2-methylpropan-1-ol of chain +108 contact b/w moleculesless extensive Van der Waals forces
  • Solubility of AlcoholsLower alcohols (C1 to C3) are completely soluble in water due totheir ability to form hydrogen bonds with water.Energy released by formation of H-bonds between alcohol andwater is sufficient to overcome the H-bonds between watermolecules and between alcohol molecules.
  •  Alcohols are versatile compounds. They react both as nucleophiles and electrophiles. The bond between O–H is broken when alcohols react as nucleophiles and the bond between C–O is broken when they react as electrophiles. Alcohols as nucleophiles
  • 1. Acidity of alcohols and phenols(i) Reaction with metals: Alcohols and phenols react with active metals such as sodium, potassium and aluminium to yield corresponding alkoxides/phenoxides and hydrogen.
  •  The acidic character of alcohols is due to the polar nature of O–H bond. An electron-releasing group (–CH3, –C2H5) increases electron density on oxygen tending to decrease the polarity of O-H bond. This decreases the acid strength.
  •  Alcohols are, however, weaker acids than water. This can be illustrated by the reaction of water with an alkoxide.This reaction shows that water is a better proton donor (i.e., stronger acid) than alcohol. Also, in the above reaction, we note that an alkoxide ion is a better proton acceptor than hydroxide ion, which suggests that alkoxides are stronger bases (sodium ethoxide is a stronger base than sodium hydroxide).
  •  The reactions of phenol with metals (e.g., sodium, aluminium) and sodium hydroxide indicate its acidic nature. The hydroxyl group, in phenol is directly attached to the sp2 hybridised carbon of benzene ring which acts as an electron withdrawing group. Due to this, the charge distribution in phenol molecule, as depicted in its resonance structures, causes the oxygen of –OH group to be positive.
  • The reaction of phenol with aqueous sodium hydroxide indicates that phenols are stronger acids than alcohols and water. The ionisation of an alcohol and a phenol takes place as follows:
  •  In substituted phenols, the presence of electron withdrawing groups such as nitro group, enhances the acidic strength of phenol. This effect is more pronounced when such a group is present at ortho and para positions. It is due to the effective delocalisation of negative charge in phenoxide ion. On the other hand, electron releasing groups, such as alkyl groups, in general, do not favour the formation of phenoxide ion resulting in decrease in acid strength. Cresols, for example, are less acidic than phenol.
  •  The greater the pKa value, the weaker the acid.
  •  Arrange the following compounds in increasing order of their acid strength: Propan-1-ol, 2,4,6-trinitrophenol, 3-nitrophenol, 3,5-dinitrophenol, phenol, 4-methylphenol.
  • Alcohols and phenols react with carboxylic acids, acid chlorides and acid anhydrides to form esters.
  •  The reaction with carboxylic acid and acid anhydride is carried out in the presence of a small amount of concentrated sulphuric acid. The reaction is reversible, and therefore, water is removed as soon as it is formed. The reaction with acid chloride is carried out in the presence of a base (pyridine) so as to neutralise HCl which is formed during the reaction. It shifts the equilibrium to the right hand side. The introduction of acetyl (CH3CO) group in alcohols or phenols is known as acetylation. Acetylation of salicylic acid produces aspirin.
  •  The reactions involving cleavage of C–O bond take place only in alcohols. Phenols show this type of reaction only with zinc.
  •  1. Reaction with hydrogen halides: Alcohols react with hydrogen halides to form alkyl halides. ROH + HX → R–X + H2O (Lucas test): Alcohols are soluble in Lucas reagent (conc. HCl and ZnCl2) while their halides are immiscible and produce turbidity in solution. In case of tertiary alcohols, turbidity is produced immediately as they form the halides easily. Primary alcohols do not produce turbidity at room temperature.
  •  2. Dehydration: Alcohols undergo dehydration (removal of a molecule of water) to form alkenes on treating with a protic acid e.g., Concentrated H2SO4 or H3PO4, or catalysts such as anhydrous zinc chloride or alumina . Ethanol undergoes dehydration by heating it with concentrated H2SO4 at 443 K.
  •  Step 1:Formation of protonated alcohol. Step 2:Formation of carbocation: It is the slowest step and hence, the rate determining step of the reaction.Step 3:Formation of ethene by elimination of a proton.
  •  Oxidation of alcohols involves the formation of a carbonoxygen double bond with cleavage of an O-H and C-H bonds. Such a cleavage and formation of bonds occur in oxidation reactions. These are also known as dehydrogenation reactions as these involve loss of dihydrogen from an alcohol molecule. Depending on the oxidising agent used, a primary alcohol is oxidised to an aldehyde which in turn is oxidised to a carboxylic acid.
  •  Tertiary alcohols do not undergo oxidation reaction. Under strong reaction conditions such as strong oxidising agents (KMnO4) and elevated temperatures, cleavage of various C-C bonds takes place and a mixture of carboxylic acids containing lesser number of carbon atoms is formed.
  •  When the vapours of a primary or a secondary alcohol are passed over heated copper at 573 K, dehydrogenation takes place and an aldehyde or a ketone is formed while tertiary alcohols undergo dehydration.
  •  1. Electrophilic aromatic substitution: In phenols benzene ring directs the incoming group to ortho and para positions in the ring as these positions become electron rich due to the resonance effect caused by –OH group.
  •  (i) Nitration: With dilute nitric acid at low temperature (298 K), phenol yields a mixture of ortho and para nitrophenols. The ortho and para isomers can be separated by steam distillation. o-Nitrophenol is steam volatile due to intramolecular hydrogen bonding while p- nitrophenol is less volatile due to intermolecular hydrogen bonding which causes the association of molecules.
  •  With concentrated nitric acid, phenol is converted to 2,4,6-trinitrophenol. The product is commonly known as picric acid. The yield of the reaction product is poor. Nowadays picric acid is prepared by treating phenol first with concentrated sulphuric acid which converts it to phenol-2,4-disulphonic acid, and then with concentrated nitric acid to get 2,4,6-trinitrophenol.
  •  On treating phenol with bromine, different reaction products are formed under different experimental conditions. (a) When the reaction is carried out in solvents of low polarity such as CHCl3 or CS2 and at low temperature, monobromophenols are formed. The usual halogenation of benzene takes place in the presence of a Lewis acid, such as FeBr3 which polarises the halogen molecule. In case of phenol, the polarisation of bromine molecule takes place even in the absence of Lewis acid. It is due to the highly activating effect of –OH group attached to the benzene ring.
  • (b)When phenol is treated with bromine water, 2,4,6-tribromophenol is formed as white precipitate.
  •  Phenoxide ion generated by treating phenol with sodium hydroxide is even more reactive than phenol towards electrophilic aromatic substitution. Hence, it undergoes electrophilic substitution with carbon dioxide, a weak electrophile. Ortho hydroxybenzoic acid is formed as the main reaction product.
  •  On treating phenol with chloroform in the presence of sodium hydroxide, a –CHO group is introduced at ortho position of benzenering. This reaction is known as Reimer - Tiemann reaction. The intermediate substituted benzal chloride is hydrolysed in the presence of alkali to produce salicylaldehyde.
  •  Phenol is converted to benzene on heating with zinc dust.
  •  Oxidation of phenol with chromic acid produces a conjugated diketone known as benzoquinone. In the presence of air, phenols are slowly oxidised to dark coloured mixtures containing quinones.
  • 1. Methanol Methanol, CH3OH, also known as ‘wood spirit’, was produced by destructive distillation of wood. Today, most of the methanol is produced by catalytic hydrogenation of carbon monoxide at high pressure and temperature and in the presence of ZnO – Cr2O3 catalyst.
  •  Methanol is a colourless liquid and boils at 337 K. It is highly poisonous in nature. Ingestion of even small quantities of methanol can cause blindness and large quantities causes even death. Methanol is used as a solvent in paints, varnishes and chiefly for making formaldehyde.
  • Ethanol, C2H5OH, is obtained commercially by fermentation, the oldest method is from sugars. The sugar in molasses, sugarcane or fruits such as grapes is converted to glucose and fructose, in the presence of an enzyme, invertase. Glucose and fructose undergo fermentation in the presence of another enzyme, zymase, which is found in yeast.
  •  Ethanol is a colourless liquid with boiling point 351 K. It is used as a solvent in paint industry and in the preparation of a number of carbon compounds. The commercial alcohol is made unfit for drinking by mixing in it some copper sulphate (to give it a colour) and pyridine (a foul smelling liquid). It is known as denaturation of alcohol. Nowadays, large quantities of ethanol are obtained by hydration of ethene
  • 1. By dehydration of alcohols Alcohols undergo dehydration in the presence of protic acids (H2SO4, H3PO4). The formation of the reaction product, alkene or ether depends on the reaction conditions. For example, ethanol is dehydrated to ethene in the presence of sulphuric acid at 443 K. At 413 K, ethoxyethane is the main product.
  •  The formation of ether is a nucleophilic bimolecular reaction (SN2). The method is suitable for the preparation of ethers having primary alkyl groups only. The alkyl group should be unhindered and the temperature be kept low. Otherwise the reaction favours the formation of alkene. The reaction follows SN1 pathway when the alcohol is secondary or tertiary.
  •  It is an important laboratory method for the preparation of symmetrical and unsymmetrical ethers. In this method, an alkyl halide is allowed to react with sodium alkoxide. Ethers containing substituted alkyl groups (secondary or tertiary) may also be prepared by this method. The reaction involves SN2 attack of an alkoxide ion on primary alkyl halide.
  •  Better results are obtained if the alkyl halide is primary. In case of secondary and tertiary alkyl halides, elimination competes over substitution. If a tertiary alkyl halide is used, an alkene is the only reaction product and no ether is formed. It is because alkoxides are not only nucleophiles but strong bases as well. They react with alkyl halides leading to elimination reactions.
  •  The C-O bonds in ethers are polar and thus, ethers have a net dipole moment. The weak polarity of ethers do not appreciably affect their boiling points. They are much lower than the boiling points of alcohols: CH3(CH2)3CH3----- 309.1 C2H5-O-C2H5 ----- 307.6 CH3(CH2)3-OH----- 390
  •  The large difference in boiling points of alcohols and ethers is due to the presence of hydrogen bonding in alcohols.
  • 1. Cleavage of C–O bond in ethers Ethers are the least reactive of the functional groups. The cleavage of C-O bond in ethers takes place under drastic conditions with excess of hydrogen halides. The reaction of dialkyl ether gives two alkyl halide molecules.
  •  Alkyl aryl ethers are cleaved at the alkyl-oxygen bond due to the more stable aryl-oxygen bond. The reaction yields phenol and alkyl halide. The order of reactivity of hydrogen halides is as follows: HI > HBr > HCl. The cleavage of ethers takes place with concentrated HI or HBr at high temperature.
  • The alkoxy group (-OR) isortho, para directing and activatesthearomatic ring towardselectrophilic substitution
  •  Phenylalkyl ethers undergo usual halogenation in the benzene ring. E.g., anisole undergoes bromination with bromine in ethanoic acid even in the absence of iron (III) bromide catalyst. It is due to the activation of benzene ring by the methoxy group. Para isomer is obtained in 90% yield.
  •  Anisole undergoes Friedel-Crafts reaction, i.e., the alkyl and acyl groups are introduced at ortho and para positions by reaction with alkyl halide and acyl halide in the presence of anhydrous aluminium chloride (a Lewis acid) as catalyst.
  •  Anisole reacts with a mixture of concentrated sulphuric and nitric acids to yield a mixture of ortho and para nitroanisole.
  • THANK U