Trigonometric Ratios by Amy H. This PowerPoint presentation was made by one of my 7 th  grade honors students. The assignm...
The Question <ul><li>Suppose you are standing 2 miles away from a tall building and you see the lights on top of the build...
Picture the Problem 2 miles 5    X
Choose a Trig Function <ul><li>SINE of 5    </li></ul><ul><li>COSINE of 5  </li></ul><ul><li>TANGENT of 5  </li></ul>To...
The Choice The only Trigonometric ratio that will work with the given information is the TAN of 5  . The tangent is the c...
Set-up of the Equation TAN of 5   = X 2 miles First, convert the 2 miles into feet (2 X 5,280) because the answer is need...
Function Translation Convert the TAN of 5   into a decimal using a calculator or a function chart. I choose to use Mr. Ro...
Isolate the variable Multiply both sides of the equation by 10,560. .08749 = X 10,560 ft. (10,560) (10,560) Now becomes………...
Solution 923.8944 = X The question requested that the answer be rounded to the nearest 100 feet. Therefore… 923.8944 = 900...
Conclusion The building lights are about 900 feet above the ground. 2 miles 5    ?? 900
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Trigonometric Ratios Using PowerPoint

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Trigonometric Ratios Using PowerPoint

  1. 1. Trigonometric Ratios by Amy H. This PowerPoint presentation was made by one of my 7 th grade honors students. The assignment was to demonstrate the steps in solving a trigonometry problem of her choice.
  2. 2. The Question <ul><li>Suppose you are standing 2 miles away from a tall building and you see the lights on top of the building. The angle of elevation from you to the lights is 5  . </li></ul><ul><li>To the nearest 100 feet, how far above the ground are the lights? </li></ul>
  3. 3. Picture the Problem 2 miles 5  X
  4. 4. Choose a Trig Function <ul><li>SINE of 5  </li></ul><ul><li>COSINE of 5  </li></ul><ul><li>TANGENT of 5  </li></ul>To calculate the height of the lights at the top of the building.
  5. 5. The Choice The only Trigonometric ratio that will work with the given information is the TAN of 5  . The tangent is the choice when the hypotenuse measure is missing. 2 miles 5  ?? X
  6. 6. Set-up of the Equation TAN of 5  = X 2 miles First, convert the 2 miles into feet (2 X 5,280) because the answer is needed to be to the nearest 100 feet. Now the equation becomes… TAN of 5  = X 10,560 ft.
  7. 7. Function Translation Convert the TAN of 5  into a decimal using a calculator or a function chart. I choose to use Mr. Rollo’s function chart for my conversion. TAN of 5  = X 10,560 ft. Now becomes……… .08749 = X 10,560 ft.
  8. 8. Isolate the variable Multiply both sides of the equation by 10,560. .08749 = X 10,560 ft. (10,560) (10,560) Now becomes……… 923.8944 = X
  9. 9. Solution 923.8944 = X The question requested that the answer be rounded to the nearest 100 feet. Therefore… 923.8944 = 900 feet
  10. 10. Conclusion The building lights are about 900 feet above the ground. 2 miles 5  ?? 900

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