Problem Solving (Geometry 1_6)

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Students practice problem solving for problems involving perimeter and area of rectangles and trapezoids.

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Problem Solving (Geometry 1_6)

  1. 1. A Plan for Problem Solving You will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. What You'll Learn
  2. 2. A Plan for Problem Solving You will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. What You'll Learn Perimeter is the _____________________. Perimeter is similar to ____________.
  3. 3. A Plan for Problem Solving You will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. What You'll Learn Perimeter is the _____________________. distance around an object Perimeter is similar to ____________. a line segment
  4. 4. A Plan for Problem Solving You will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. What You'll Learn Perimeter is the _____________________. distance around an object Perimeter is similar to ____________. a line segment Area is the _______________________________________________. Area is similar to ______.
  5. 5. A Plan for Problem Solving You will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. What You'll Learn Perimeter is the _____________________. distance around an object Perimeter is similar to ____________. a line segment Area is the _______________________________________________. number of square units needed to cover an object’s surface Area is similar to ______. a plane
  6. 6. A Plan for Problem Solving In this section you will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. Perimeter is the ____________________.
  7. 7. A Plan for Problem Solving In this section you will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. Perimeter is the ____________________. distance around a figure
  8. 8. A Plan for Problem Solving In this section you will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. Perimeter is the ____________________. distance around a figure The perimeter is the ____ of the lengths of the sides of the figure.
  9. 9. A Plan for Problem Solving In this section you will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. Perimeter is the ____________________. distance around a figure The perimeter is the ____ of the lengths of the sides of the figure. sum
  10. 10. A Plan for Problem Solving In this section you will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. Perimeter is the ____________________. distance around a figure The perimeter is the ____ of the lengths of the sides of the figure. sum The perimeter of the room shown here is:
  11. 11. A Plan for Problem Solving In this section you will learn to solve problems that involve the perimeters and areas of rectangles and parallelograms. Perimeter is the ____________________. distance around a figure The perimeter is the ____ of the lengths of the sides of the figure. sum The perimeter of the room shown here is: 15 ft + 12 ft + 18 ft + 6 ft + 6 ft + 9 ft = 66 ft
  12. 12. A Plan for Problem Solving Some figures have special characteristics. For example, the opposite sides of a rectangle have the same length. This allows us to use a formula to find the perimeter of a rectangle. ( A formula is an equation that shows how certain quantities are related. )
  13. 13. A Plan for Problem Solving Some figures have special characteristics. For example, the opposite sides of a rectangle have the same length. This allows us to use a formula to find the perimeter of a rectangle. ( A formula is an equation that shows how certain quantities are related. ) (of a rectangle)
  14. 14. A Plan for Problem Solving Find the perimeter of a rectangle with a length of 17 ft and a width of 8 ft. 17 ft 8 ft
  15. 15. A Plan for Problem Solving Find the perimeter of a rectangle with a length of 17 ft and a width of 8 ft. = 2(17 ft) + 2(8 ft) = 34 ft + 16 ft = 50 ft 17 ft 8 ft
  16. 16. A Plan for Problem Solving Find the perimeter of a rectangle with a length of 17 ft and a width of 8 ft. = 2(17 ft) + 2(8 ft) = 2(17 ft + 8 ft) = 34 ft + 16 ft = 50 ft = 2(25 ft) = 50 ft 17 ft 8 ft
  17. 17. A Plan for Problem Solving Another important measure is area. The area of a figure is ____________________________________________.
  18. 18. A Plan for Problem Solving Another important measure is area. The area of a figure is ____________________________________________. the number of square units needed to cover its surface
  19. 19. A Plan for Problem Solving Another important measure is area. The area of a figure is ____________________________________________. the number of square units needed to cover its surface The area of the rectangle below can be found by dividing it into 18 unit squares. 3 6
  20. 20. A Plan for Problem Solving Another important measure is area. The area of a figure is ____________________________________________. the number of square units needed to cover its surface The area of the rectangle below can be found by dividing it into 18 unit squares. 3 6
  21. 21. A Plan for Problem Solving Another important measure is area. The area of a figure is ____________________________________________. the number of square units needed to cover its surface The area of the rectangle below can be found by dividing it into 18 unit squares. The area of a rectangle can also be found by multiplying the length and the width. 3 6
  22. 22. A Plan for Problem Solving The area “A” of a rectangle is the product of the length l and the width w. Find the area of the rectangle l w 14 in. 10 in.
  23. 23. A Plan for Problem Solving The area “A” of a rectangle is the product of the length l and the width w. Find the area of the rectangle The area of the rectangle is 140 square inches . l w 14 in. 10 in.
  24. 24. A Plan for Problem Solving The area “A” of a rectangle is the product of the length l and the width w. Find the area of the rectangle The area of the rectangle is 140 square inches . l w 14 in. 10 in. NOTE: units indicate area is being calculated
  25. 25. Plan for Problem Solving Because the opposite sides of a parallelogram have the same length, the area of a parallelogram is closely related to the area of a ________.
  26. 26. Plan for Problem Solving Because the opposite sides of a parallelogram have the same length, the area of a parallelogram is closely related to the area of a ________. rectangle
  27. 27. Plan for Problem Solving Because the opposite sides of a parallelogram have the same length, the area of a parallelogram is closely related to the area of a ________. rectangle The area of a parallelogram is found by multiplying the ____ and the ______. base height
  28. 28. Plan for Problem Solving Because the opposite sides of a parallelogram have the same length, the area of a parallelogram is closely related to the area of a ________. rectangle The area of a parallelogram is found by multiplying the ____ and the ______. base height base height
  29. 29. Plan for Problem Solving Because the opposite sides of a parallelogram have the same length, the area of a parallelogram is closely related to the area of a ________. rectangle The area of a parallelogram is found by multiplying the ____ and the ______. base height Base – the bottom of a geometric figure. Height – measured from top to bottom, perpendicular to the base. base height
  30. 30. A Plan for Problem Solving Find the area of the parallelogram:
  31. 31. A Plan for Problem Solving Find the area of the parallelogram:
  32. 32. A Plan for Problem Solving Find the area of the parallelogram:
  33. 33. §1.6 A Plan for Problem Solving End of Lesson

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