1. Universidad Privada Antenor Orrego
Escuela Profesional de Ingeniería Civil
Análisis Estructural Ing. Juan Manuel Urteaga García
Modulo de Elasticidad E= 29000.00 Ksi
16' 16'
2
1
2
15 Kb
12'
1
12'
3
3
1 2

2. Longitud Longitud Area
Elemento 2
(pies) (in) (in )
1 12.00 144.00 3.00
2 16.00 192.00 3.00
3 20.00 240.00 3.00
1 3/5
1
Elemento D1 D2 D3
4/5 0 0 1
1
0 0 0
0 0 0
2
1 1 0 0
3/5 0 0 3/5
3
4/5 3/5 0
K2,1
EA2/L2(1)
K1,1 = (1)(29000)(3)/(192)+(4/5)(29000)(3)/(192)(4/5) = 685.13 Klb
K1,1
K2,1 = (29000)(3)/(240)(4/5)(3/5)) = 174.00 Klb
K3,1 = -(29000)(3)/(240)(4/5)(3/5)) = -174.00 Klb
EA3/L3 (4/5)
K3,1

3. K2,2
K1,2 = (29000)(3)/(240)(3/5)(4/5)) = 174.00 Klb
K1,2
K2,2 = (29000)(3)/(240)(3/5)(3/5)) = 130.50 Klb
K3,2 = -(29000)(3)(240)(3/5)(3/5)) = -130.50 Klb
EA3/L3 (3/5)
K3,2
K2,3
K1,3 = -(29000)(3)/(240)(3/5)(4/5)) = -174.00 Klb
K1,3
K2,3 = -(29000)(3)/(240)(3/5)(3/5)) = -130.50 Klb
K3,3 = (29000)(3)/(240)(3/5)(3/5)+(29000)(3)/(144) = 734.67 Klb
EA1/L1 (1)
EA3/L3 (3/5)
K3,3

4. Solución del Sistema de Ecuaciones
{Q} = {K}{D}
0 685 174 -174 D1
-15 = 174 131 -131 D2
0 -174 -131 735 D3
{K}-1{Q} = {K}-1{K}{D}
{K}-1{Q} = {I}{D}
2.21E-03 -2.94E-03 0.00E+00 0 D1
-2.94E-03 1.32E-02 1.66E-03 -15 = D2
0.00E+00 1.66E-03 1.66E-03 0 D3
Desplazamientos Globales
D1 = 4.41E-02 in
D2 = -1.99E-01 in
D3 = -2.48E-02 in

5. Desplazamientos Locales
d1,1 = D3 = -2.48E-02 0.00000 0.00000 1.00000 4.41E-02 -2.48E-02
d2,1 = 0.00E+00 0.00000 0.00000 0.00000 -1.99E-01 0.00E+00
-2.48E-02
d1,2 = 0.00E+00 0.00000 0.00000 0.00000 4.41E-02 0.00E+00
d2,2 = D1 = 4.41E-02 1.00000 0.00000 0.00000 -1.99E-01 4.41E-02
-2.48E-02
d1,3 = (3/5)D3 = -1.49E-02 0.00000 0.00000 0.60000 4.41E-02 -1.49E-02
d2,3 = (4/5)D1+(3/5)D2 = -8.39E-02 0.80000 0.60000 0.00000 -1.99E-01 -8.39E-02
-2.48E-02
Esfuerzos Locales
q1,1 = (29000)(3)(2.48E-02)/(144) - (29000)(3)(0)/(144) = -15.00 Klb
q2,1 = -(29000)(3)(2.48E-02)/(144)+(29000)(3)(0)/(144) = 15.00 Klb
q1,2 = (29000)(3)(0)/(194) - (29000)(3)(4.41E-02)/(194) = -20.00 Klb
q2,2 = -(29000)(3)(0)/((16)(12))+(29000)(3)(4.41E-02)/((16)(12)) = 20.00 Klb
q1,3 = (29000)(3)(-1.49E-02)/((20)(12)) - (29000)(3)(-8.39E-02)/((20)(12)) = 25.00 Klb
q2,3 = -(29000)(3)(-1.49E-02)/((20)(12)) + (29000)(3)(-8.39E-02)/((20)(12)) = -25.00 Klb

6. Diagramas
15 Klb
20 Klb 20 Klb
20 Klb
15.Klb
25 Klb
15.Klb
20 Klb 25 Klb