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# Speed and velocity

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### Speed and velocity

1. 1. Re p u b li c o f t he P hi li ppi ne s D e pa r t me nt o f E d uc a t i o n Re g i o n V II , Ce nt r a l Vi s a ya s D i vi s i o n o f M a nd a ue Ci t y Labogon, Mandaue City SPEED AND VELOCITY Prepared by: RHONNEL M. ALBURO IV - GalatiaVisit my website: http://www.alfore.info/ to see my collection of school related works!
2. 2. I. Title PageII. Table of ContentsIII. Guide CardIV. IntroductionV. Activity Card #1VI. Activity Card #2VII. Assessment Card #1VIII. Assessment Card #2IX. Enrichment Card #1X. Enrichment Card #2XI. Enrichment Card #3XII. Answer CardXIII. Reference Card
3. 3. Hello! I am Mr. Sim. Welcome to another fun-filled adventure as we take another journey to the world of Physics. This time we will be talking about Speed and Velocity. So fasten your seatbelt as we go and learn! This Strategic Intervention Material is designed to give the learner betterunderstanding on the different concepts related to speed and velocity. Upon finishingthis SIM the reader is expected to: • Define speed and velocity. • Identify and understand the key concepts on speed and velocity. • Differentiate Instantaneous Speed and Average Speed • Differentiate Instantaneous Velocity and Average Velocity • Plot the movement of an object to determine its average speed and velocity • Solve problems related to speed and velocity.Now that you know what you will be learning, let’s take a little review about thetopic.
4. 4. Just as distance and displacement have distinctly different meanings (despitetheir similarities), so do speed and velocity. Speed is a scalar quantity which refers to"how fast an object is moving." Speed can be thought of as the rate at which an objectcovers distance. A fast-moving object has a high speed and covers a relatively largedistance in a short amount of time. A slow-moving object has a low speed and coversa relatively small amount of distance in a short amount of time. Velocity is a vector quantity which refers to "the rate at which an object changesits position." If a person in motion wishes to maximize their velocity, then that personmust make every effort to maximize the amount that they are displaced from theiroriginal position. Every step must go into moving that person further from where heor she started. Velocity is a vector quantity. As such, velocity is direction aware. Whenevaluating the velocity of an object, one must keep track of direction. It would not beenough to say that an object has a velocity of 55 mi/hr. One must include directioninformation in order to fully describe the velocity of the object. For instance, youmust describe an objects velocity as being 55 mi/hr, east. This is one of the essentialdifferences between speed and velocity. Speed is a scalar quantity and does not keeptrack of direction; velocity is a vector quantity and is direction aware. The task of describing the direction of the velocityvector is easy. The direction of the velocity vector is simplythe same as the direction which an object is moving. Itwould not matter whether the object is speeding up orslowing down. If an object is moving rightwards, then itsvelocity is described as being rightwards. If an object ismoving downwards, then its velocity is described as beingdownwards. So an airplane moving towards the west with aspeed of 300 mi/hr has a velocity of 300 mi/hr, west.Note that speed has no direction (it is a scalar) and velocityat any instant is simply the speed with a direction. Now you are ready to perform the coming activities. Good Luck!
5. 5. Activity #1Test I. Ranking SpeedGiven are four objects with varying speed. Convert the speed of each object to the desired unit 22and rank them from 1 to 4, where 1 is the fastest and 4 is the slowest. (Let π = .) 7_____ A wheel of radius 28 cm moving at 60 rpm = ______ m/s_____ A plane moving at a speed of 30 kph = ______ m/s_____ A sprinter running 100 m in 15 seconds = ______ m/s_____ A car running 72 meters after 9 seconds = ______ m/sTest II. Average SpeedDetermine the average speed of the following object.1. A car speed tabulated for every seconds under a 10-second time duration. Speed 0 10 8 7 10 15 8 7 10 10 15 m/s time 0 1 2 3 4 5 6 7 8 9 10 sec2. A runner whose movement is as follow: 200 m for 80 sec, 100 m for 30 sec, and 300 m for 90sec.Test III. How fast you move.Fill up the table below (Use approximate values) and calculate your speed in m/s for thatactivity. Activity Distance Time Consumed Average Speed Walking (House to School) meters __hr __min __sec m/s Climbing a Staircase meters __hr __min __sec m/s Riding a Bicycle meters __hr __min __sec m/s Going to the Mall meters __hr __min __sec m/s Swimming meters __hr __min __sec m/s Walking (Classroom to Canteen) meters __hr __min __sec m/s
6. 6. Activity #2Test I. Speed Vs. VelocityDetermine whether the following suggest speed or velocity. Write S for speed and V for velocity._____ An elevator moving for 30m from the first floor to the third floor for 5 minutes._____ A man walked for half an hour and covered 600 meters._____ A ball dropped 30 m above a building is found on the ground 3 seconds after._____ The news reported that the speed of Hanging Habagat is 20 km/h._____ A sprinter finish a 400 meter race after 2 minutes and 16 seconds.Test II. The Friendly RaceRead and analyze the situation. Answer the questions that follow. 4 friends decided to have a race from the gate of their school to the beach. Thebeach is 30 km north of the starting position. Since the friends are racing from each other theydecided to take different paths.Ramon: 20 km North for 15 minutes; 5 km N 30° E for 5 minutes; and 5 km West for 5 minutes.Ronald: 20 2 km NW for 27 minutes; 20 km East for 20 minutes; and 10 km North for 6minutes.Eduard: 15 km North for 10 minutes; 15 km West for 11 minutes; and 15 2 km NE for 15minutes.Adolfo: 50 km N 60° E for 50 minutes; 15 km West for 11 minutes; and 5 km South for 7minutes.1. Complete the table below. Name Total Distance Total Time Average Speed Ramon km __hr __min km/h Ronald km __hr __min km/h Eduard km __hr __min km/h Adolfo km __hr __min km/h2. Who did not finish the race?3. Who finished the race?
7. 7. 4. Who won the race?5. Using the Cartesian plane below, plot the movement of each friend. (Use the scale 1 unit: 5 km and let the starting position be at the origin.)6. From the plot above, determine the displacement of the four friends. (Round off answers to two decimalplaces) Name Displacement Ramon km Ronald km Eduard km Adolfo km7. Calculate the average velocity of the four friends. (Round off answers to two decimal places) Name Average Velocity Ramon _____ km/h ______ Ronald _____ km/h ______ Eduard _____ km/h ______ Adolfo _____ km/h ______
8. 8. Assessment Card #2 Test I. Multiple Choice. (Use π=3.14) 1. A plane’s speed after landing is defined by the equation s = 180 − 18t m s , how long would it take the plane to stop? a. 10 seconds b. 11 seconds c. 12 seconds d. 13 seconds 2. A 50 m train of constant speed enters a 300 m tunnel, if a stationary light located in the tunnel has been above the train for 4 seconds. How fast is the train moving? a. 10 m/s b. 12.5 m/s c. 15 m/s d. 17.5 m/s 3. A car was able to take 10 laps in a circular race track whose radius is 15 m for a total time of 15 minutes and 42 second. What is the average speed of the car? a. 10 km/h b. 20 km/h c. 30 km/h d. 40 km/h 4. Two men were walking towards each other. The speed of the first man (A) is 2/3 of the speed of the second man (B) and the distance between them is 150m. After t seconds the two men meet each other, by this point how far did man A travelled? a. 50 m b. 60 m c. 70 m d. cannot be determined 5. A runner ran around an oval and returned to his original position. If the average speed of the runner is 2 mph and he ran for 13 minutes, which of the following could be his velocity? a. 2 mph East b. 0 mph North c. 4 mph East d. 1 mph North Test II. Matching Type – Match Column A with Column B. Connect the Circles of the corresponding matches. Column A Column B 1. The rate at which an object covers a distance. • • A. Odometer 2. The distance of the line connecting the initial • • B. Velocity and the final position. 3. The rate at which an object moves with respect • • C. Displacement to direction. 4. It refers to how fast an object is moving in • • D. Speed a given period of time 5. A device used to measure speed. • • E. Instantaneous Speed
9. 9. Enrichment #1 Test I. Vocabulary Enhancement Define the following: 1. Average Speed 2. Azimuth 3. Direction 4. Displacement 5. Instantaneous Speed 6. Kinematics 7. Scalar Quantity 8. Speed 9. Vector Quantity 10. Velocity Test II. Relationship of Distance, Time, Speed and Velocity Match the definition with the appropriate illustration below. a. b. c. d. ____ Constant Speed ____ Zero Displacement ____ Increasing Speed ____ Zero Velocity ____ Constant Velocity Test II. Essay A. Explain why it is possible to have positive average speed but zero average velocity. __________________________________________________________________________________ __________________________________________________________________________________ __________________________________________________________________________________ ________. B. Explain the difference between a vector and a scalar quantity. __________________________________________________________________________________ __________________________________________________________________________________ __________________________________________________________________________________ ________.
10. 10. Enrichment #2 Test I. Which Car was that? Two cars were moving at constant speed. Car A is moving at a rate of (1)_____ mph. Car B is moving at 80 mph. After 3 hours Car A is 27 miles from Car B which by this time has travelled (2) _____. Two hours earlier Car A is (3) _____ miles ahead of Car B. On the fourth hour, Car B decided to stop for (4) _____ minutes. From the moment Car B stopped till it started to continue its track Car A has travelled (5)____ miles making the distance between the two cars equal to 80.5 miles. (6-10) If a snail moving at a rate of 0.0000001 mile/s crossing the road 500 miles away from the starting point and the road is 0.004 mile wide which car is closer to the snail when it reaches the middle of the road?(The snail started crossing the moment the two cars started the moving.) Test II. Average Velocity (Use 1:20meters and 1:5naut.miles in plotting) Plot the movement of the following objects and determine their average velocity. 1. A ship move at a speed of 30 knots with a bearing of 120° for half an hour. Then turned 30° to the left and travelled 20 n.m. for 45 minutes to reach its destination. 2. To reach the school, Ramon walked the following distance: 160m N 30° E for 3 minutes; 100m West for 5 minutes; and 20 2 m NE for 2 minutes. y 9 8 7 6 5 4 3 2 1 x -9 -8 -7 -6 -5 -4 -3 -2 -1 1 2 3 4 5 6 7 8 9 -1 -2 -3 -4 -5 -6 -7 -8 -9
11. 11. Enrichment #3 Top Ten (10) Fastest Land Animals 1. Cheetah (70 mph) The cheetah is the fastest member of the cat family and is unique because what it lacks in climbing abilities it makes up for in speed and stealth. The cheetah is the fastest of all land animals and can reach speeds between 112 kilometres per hour (70 mph) and 120 kilometres per hour (75 mph) in short bursts up to 460 metres (500 yd). The cheetahs ability to accelerate is unmatched. The animal can easily accelerate from 0 to 110 kilometres per hour (68 mph) in three seconds, faster than most supercars.2. Pronghorn Antelope (61 mph) The Pronghorn Antelopes exceptional speed is necessary in order toevade predators by outrunning them. The animal is considered to be the fastestanimal in the new world. The top speed is very hard to measure accurately and itvaries between individuals, however the animal has been clocked at 61mph. It isoften cited as the second-fastest land animal with the Cheetah being the fastest.The animal can sustain these speeds much longer than a cheetah due to itslarger heart and lungs. These animals are poor jumpers. 3. Wildebeest (50 mph) The Wildebeest is another animal that relies on its speed to evade predators. These animals are favorites of the big cats as they inhabit the plains and open woodlands of Africa. They are most plentiful in the Serengeti and can live more than 20 years.4. Lion (50 mph) The king of bests doesnt often use his speed when hunting becausethe lioness does the majority of the hunting. Those Lions without a pride useclever stealth and speed to catch their prey. Males can exceed 550lbs, makingit the second largest living cat after the tiger. Wild lions can only be found insub-Saharan Africa, Asia and a small population in northwest India. 5. Thomson’s Gazelle (50 mph) Named after explorer Joseph Thompson, the Thompsons Gazelle is one of the best known gazelles. In order to evade its main enemy, the cheetah, these animals can reach speeds of 50 mph, and can sustain longer bursts than their mortal enemy.6. Quarterhorse (47.5 mph) 8. Cape Hunting Dog (45 mph) 10. Gray Fox (42 mph) 7. Elk (45 mph) 9. Coyote (43 mph)
12. 12. Assessment #1 UP-SIDE-DOWN WORD SEARCHDirectionInstruction: Connect the letters inside the box to form the word that answers the questionor completes the statement. You may connect adjacent letters upward, downward andsideward. You are not allowed to connect letters diagonally. Find the 8 Items to uncover themystery word using the unused letters. K S C A L A I E Example D I T O R R A G N B I T P S C E O E R N O M R E L A C V U N A E C P E S M A E M S A V A I U T A N A L E N T T I I T S T A N I A F I N I C I S L1. _______ is an entity characterized by a magnitude and a direction.2. Average speed is the mean of all the ___________ speed recorded for a certain period oftime.3. The length of the line directly connecting the initial and the final position.4. Speed is not direction aware making it a _______ quantity.5. The ratio of the displacement and the total time is called ________ velocity.6-7. An object has zero displacement if its _______ and ________ positions is the same.8. What is the displacement if an object moved 6 km East and 8 km North?9. The mystery word is __________.10. Give your own definition of the mystery word: __________________________________ _____________________________________________________________________ ____________________________________________________________________.
13. 13. Activity #1Test I. Ranking SpeedGiven are four objects with varying speed. Convert the speed of each object to the desired unit 22and rank them from 1 to 4, where 1 is the fastest and 4 is the slowest. (Let π = .) 7 See next page 4 A wheel of radius 28 cm moving at 60 rpm = 1.76 m/s for the solution. 1 A plane moving at a speed of 30 kph = 8.33 m/s 3 A sprinter running 100 m in 15 seconds = 6.67 m/s 2 A car running 72 meters after 9 seconds = 8.00 m/sTest II. Average SpeedDetermine the average speed of the following objects.1. A car speed tabulated for every seconds under a 10-second time duration. Speed 0 10 8 7 10 15 8 7 10 10 15 m/s save = 10 m / s time 0 1 2 3 4 5 6 7 8 9 10 sec2. A runner whose movement is as follow: 200 m for 80 sec, 100 m for 25 sec, and 300 m for 90sec.s ave = 3 m / sTest III. How fast you move.Fill up the table below (Use approximate values) and calculate your speed in m/s for thatactivity. Activity Distance Time Consumed Average Speed Answers for this activity may __hr __minSee to it that the Walking (House to School) meters vary. __sec m/s Climbing a Staircase meters __hr __min __sec m/s Average Bicycle Riding a speed calculated is correct as what is meters __hr __min __sec m/s recorded in the distancemeters the time consumed. Going to the Mall Swimming and __hr __min __sec meters __hr __min __sec m/s m/s Walking (Classroom to Canteen) meters __hr __min __sec m/s
14. 14. Solutions for Activity I Test I 8.00 m/s Solutions for Activity I Test II 1. A car speed tabulated for every seconds under a 10-second time duration. Speed 0 10 8 7 10 15 8 7 10 10 15 m/s time 0 1 2 3 4 5 6 7 8 9 10 sec To determine the average speed, we will calculate the mean of instantaneous speed of thecar as recorded in the table. 10 ∑s 10 + 8 + 7 + 10 + 15 + 8 + 7 + 10 + 10 + 15 100s ave = n =1 s ave = s ave = s ave = 10 m / s n 10 10 2. A runner whose movement is as follow: 200 m for 80 sec, 100 m for 30 sec, and 300 m for 90 sec. s ave = ∑d s ave = 200 + 100 + 300 s ave = 600 s ave = 600 s ave = 3 m / s ∑t 80 + 30 + 90 200 200
15. 15. Activity #2Test I. Speed Vs. VelocityDetermine whether the following suggest speed or velocity. Write S for speed and V for velocity. V An elevator moving 30m from the first floor to the third floor for 5 minutes (Upward) S A man walked for half an hour and covered 600 meters. V A ball dropped 30 m above a building is found on the ground 3 seconds after. (Downward) V The news reported that the speed of Hanging Habagat is 20 km/h. (Southwest) S A sprinter finishes a 400 meter race after 2 minutes and 16 seconds.Test II. The Friendly RaceRead and analyze the situation. Answer the questions that follow. 4 friends decided to have a race from the gate of their school to the beach. The beach is30 km north of the starting position. Since the friends are racing from each other they decidedto take different paths.Ramon: 20 km North for 15 minutes; 5 km N 30° E for 5 minutes; and 5 km West for 5 minutes.Ronald: 20 2 km NW for 27 minutes; 20 km East for 20 minutes; and 10 km North for 6minutes.Eduard: 15 km North for 10 minutes; 15 km West for 11 minutes; and 15 2 km NE for 15minutes.Adolfo: 50 km N 60° E for 50 minutes; 15 km West for 11 minutes; and 5 km South for 7minutes.1. Complete the table below. Name Total Distance Total Time Average Speed Ramon 30 km 0 hr 25 min 72.00 km/h Ronald 58 km 0 hr 53 min 65.66 km/h Eduard 51 km 0 hr 36 min 85.00 km/h Adolfo 70 km 1 hr 08 min 61.76 km/h2. Who did not finish the race? Ramon and Adolfo3. Who finished the race? Ronald and Eduard
16. 16. 4. Who won the race? Eduard won the race for reaching the beach with a total time of 36minutes.5. Using the Cartesian plane below, plot the movement of each friend. (Use the scale 1 unit: 5 km and let the starting position be at the origin.)6. From the plot above, determine the displacement of the four friends. (Round off answers to two decimalplaces.) Name Displacement Ramon 24.46 km Ronald 30.00 km Eduard 30.00 km Adolfo 34.65 km7. Calculate the average velocity of the four friends. (Round off answers to two decimal places.) Name Average Velocity See next page Ramon 58.70 km/h N 5.87° W for the solution. Ronald 33.96 km/h North Eduard 50.00 km/h North Adolfo 30.57 km/h N 54.75° E
17. 17. Solutions for items number 6 and 7.6. To calculate for displacement, we use component method. Ramon: 20 km North for 15 min; 5 km Displacement Direction X-component Y-component N 30° E for 5 min; and 5 km West for 20 km North 0 20 5 min. 5 km N 30° E 2.5 2.5 3 5 km W -5 0 Total -2.5 20+2.5 3 (∑ x − component ) + (∑ y − component ) (− 2.5)2 + (20 + 2.5 ) 2 2 2D= D= 3 D ≈ 24.46 km Ronald: 20 2 km NW for 27 min; Displacement Direction X-component Y-component 20 km East for 20 min; and 10 km 20 2 km NW -20 20 North for 6 minutes. 20 km E 20 0 10 km N 0 10 Total 0 30D= (∑ x − component ) + (∑ y − component ) 2 2 D= (0)2 + (30)2 D = 30.00 km Eduard: 15 km North for 10 min; 15 Displacement Direction X-component Y-component km West for 11 min; and 15 2 km 15 km N 0 15 15 km W -15 0 NE for 15 min. 15 2 km NE 15 15 Total 0 30D= (∑ x − component ) + (∑ y − component ) 2 2 D= (0)2 + (30)2 D = 30.00 km Adolfo: 50 km N 60° E for 50 min; Displacement Direction X-component Y-component 50 km N 60° E 25 15 km West for 11 min; and 5 km 25 3 South for 7 min. 15 km W -15 0 5 km S 0 -5 Total 20 25 3 -15D= (∑ x − component ) + (∑ y − component ) 2 2 D= (25 ) 3 − 15 + (20 ) 2 2 D ≈ 34.65 km7. For the direction of the velocity use the results of the component method in item number 6. y 20 + 2.5 3Ramon: tan − θ= tan − θ = tan − θ = −9.732050808 θ = −84.13 x − 2.5 24.46 Therefore, Ramon’s average velocity is N 90 − 84.13°W = 58.70 N 5.87°W 25 min y 30 30Ronald: tan − θ= tan − θ = tan − θ = undefined θ = 90° Therefore, Ronald’s vave= = x 0 53 min33.96km / h N y 30 30Eduard: tan − θ= tan − θ = tan − θ = undefined θ = 90° Therefore, Eduard’s vave= = x 0 36 min50.00km / h N y 20Adolfo: tan − θ= tan − θ = tan − θ = 0.070668 θ = 35.25 x 25 3 − 15 34.65Therefore, Adolfo’s average velocity is N 90 − 35.25° E = 30.57 km / h N 54.75° E 68 min
18. 18. Assessment #1 UP-SIDE-DOWN WORD SEARCHDirectionInstruction: Connect the letters inside the box to form the word that answers the questionor completes the statement. You may connect adjacent letters upward, downward andsideward. You are not allowed to connect letters diagonally. Find the 8 Items to uncover themystery word using the unused letters.1. VECTOR is an entity characterized by a magnitude and a direction.2. Average speed is the mean of all the INSTANTENOUS speed recorded for a certain periodof time.3. The length of the line directly connecting the initial and the final position. DISPLACEMENT4. Speed is not direction aware making it a SCALAR quantity.5. The ratio of the displacement and the total time is called AVERAGE velocity.6-7. An object has zero displacement if it’s INITIAL and FINAL positions is the same.8. What is the displacement if an object moved 6 km East and 8 km North? TEN (10 km)9. The mystery word is KINEMATICS.10. Give your own definition of the mystery word: Kinematics is the study of motion and its components.
19. 19. See next page forAssessment Card #2 the solution. Test I. Multiple Choice. (Use π=3.14) 1. A plane’s speed after landing is defined by the equation s = 180 − 18t m s , how long would it take the plane to stop? a. 10 seconds b. 11 seconds c. 12 seconds d. 13 seconds 2. A 50 m train of constant speed enters a 300 m tunnel, if a stationary light located in the tunnel has been above the train for 4 seconds. How fast is the train moving? a. 10 m/s b. 12.5 m/s c. 15 m/s d. 17.5 m/s 3. A car was able to take 10 laps in a circular race track whose radius is 15 m for a total time of 15 minutes and 42 second. What is the average speed of the car? a. 10 km/h b. 20 km/h c. 30 km/h d. 40 km/h 4. Two men were walking towards each other. The speed of the first man (A) is 2/3 of the speed of the second man (B) and the distance between them is 150m. After t seconds the two men meet each other, by this point how far did man A travelled? a. 50 m b. 60 m c. 70 m d. cannot be determined 5. A runner ran around an oval and returned to his original position. If the average speed of the runner is 2 mph and he ran for 13 minutes, which of the following could be his velocity? a. 2 mph East b. 0 mph North c. 4 mph East d. 1 mph North Test II. Matching Type – Match Column A with Column B. Connect the Circles of the corresponding matches.
20. 20. Solutions for Assessment Card #2 Test 1
21. 21. Enrichment #1 Test I. Vocabulary Enhancement Define the following: 1. Average Speed is the ratio of the total distance travelled to the total time. 2. Azimuth is a horizontal angle measured clockwise from a north base line or meridian. 3. Direction is the line or course upon which anything is moving or aimed to move, or in which anything is lying or pointing. 4. Displacement is the length of the track connecting the initial and the final position. 5. Instantaneous Speed is the speed of an object at a given moment of time. 6. Kinematics is the study of motion and its components. 7. Scalar Quantity is a simple physical quantity that is not direction aware. 8. Speed the rate at which an object is moving. 9. Vector Quantity a quantity having a magnitude and a direction. 10. Velocity the speed at which an object is moving with respect to the direction. Test II. Relationship of Distance, Time, Speed and Velocity Match the definition with the appropriate illustration below. a. b. c. d. a & c Constant Speed b Zero Displacement d Increasing Speed b Zero Velocity a & c Constant Velocity Test II. Essay A. Explain why it is possible to have positive average speed but zero average velocity. It is possible to have zero average velocity but a positive average speed since average speed only takes the total distance covered over the total time while average velocity takes the displacement over the total time. Assuming that the initial and the final position is the same, the displacement would be equal to zero thus yielding zero average velocity. B. Explain the difference between a vector and a scalar quantity. A vector quantity contains a magnitude and a direction while a scalar quantity has only the magnitude.
22. 22. Enrichment #2 Test I. Which Car was that? Two cars were moving at constant speed. Car A is moving at a rate of (1) 89 mph. Car B is moving at 80 mph. After 3 hours Car A is 27 miles from Car B which by this time has travelled (2) 240 miles. Two hours earlier Car A is (3) 9 miles ahead of Car B. On the fourth hour, Car B decided to stop for (4) 30 minutes. From the moment Car B stopped till it started to continue its track Car A has travelled (5) 44.5 miles making the distance between the two cars equal to 80.5 miles. (6-10) If a snail moving at a rate of 0.0000001 mile/s crossing the road 500 miles away from the starting point and the road is 0.004 mile wide which car is closer to the snail when it reaches the middle of the road?(The snail started crossing the moment the two cars started the moving.) Car A is closer to the snail. (See next page for the solutions.) Test II. Average Velocity (Use 1:20meters and 1:5naut.miles in plotting) Plot the movement of the following objects and determine their average velocity. 1. A ship move at a speed of 30 knots with a bearing of 120° for half an hour. Then turned 30° to the left and travelled 20 n.m. for 45 minutes to reach its destination. 27.06 knots E 12.81° S 2. To reach the school, Ramon walked the following distance: 160m N 30° E for 3 minutes; 100m West for 5 minutes; and 20 2 m NE for 2 minutes. 1. Ship y 9 1. Ships Average Velocity 2. Ramon 8 2. Ramons Average Velocity 7 6 5 4 3 2 1 x -9 -8 -7 -6 -5 -4 -3 -2 -1 1 2 3 4 5 6 7 8 9 -1 -2 -3 -4 -5 -6 -7 -8 -9
23. 23. Solutions for Enrichment #2 Test I. 1. It is given that both moved at a constant speed. By examining and using the clue in sentence number four that states that car A is ahead of Car B. we can conclude that car A’s speed is 89 mph. Using this we can therefore solve the rest of the items. miles 2. 80 × 3h = 240 miles h 3. Given t=1, Sa = 89 mph and Sb = 80 mph. d a − d b = (89 − 80 )1 = 9miles 4. Using the answer on the next item we will be able to know how long did car b stopped. d 44.5mi t= = = 0.5h = 30 min s mi 90 h 5. We difference of the two cars on the fourth hour. t=4, Sa = 89 mph and Sb = 80 mph. d a − d b = (89 − 80 )4 = 36miles Subtract the value to the total distance on the moment car B Decided to continue. 80.5 − 36 = 44.5miles 6-10. We first Calculate the time it took the snail to reach the middle. 0.004 ÷ 2(half the length of the road ) 0.002mi s t= = × = 20000 sec = 5 hr 20 min 33 sec m 1 0.0000001mi 0.0000001 s Determine the distance cover by the two cars. 3. Given t=1, Sa = 89 mph and Sb = 80 mph. t 20000 sec 20000 sec 89mi 1h da = = = x × = 494.44 miles sa mi 1 h 3600 sec 89 h t 20000 sec− (.5 × 3600) 18200 sec 80mi 1h da = = = x × = 404.44 miles sa mi 1 h 3600 sec 80 h We subtracted half an hour since car b is not moving for that period of time from the 4th hour to the 4.5th hour. With distance travelled above by the two cars. We can conclude that car A is closer to the snail which is found on the 500th mile of the track.Test II. Use component method to know the average velocity. 1. A ship move at a speed of 30 Displacement Direction X-component Y-component knots with a bearing of 120° for half 15n.m. 120° bearing 7.5 3 -7.5 an hour. Then turned 30° to the left 20n.m East 20 0 and travelled 20 n.m. for 45 Total 20 + 7.5 3 -7.5 minutes to reach its destination.D= (∑ x − component ) + (∑ y − component ) 2 2 D= (20 + 7.5 3 ) 2 + (− 7.5) 2 D ≈ 33.83 nm ( (Vave = 33.83 ÷ (.5 + .75) arctan − 7.5 ÷ 20 + 7.5 3 )) Vave = 27.06 knots E 12.81°S Displacement Direction X-component Y-component 2. To reach the school, Ramon 160 m N 30° E 80 80 3 walked the following distance: 160m 100 m W -100 0 N 30° E for 3 minutes; 100m West 20 2 m NE 20 20 for 5 minutes; and 20 2 m NE for 2 Total 0 20 + 80 3 minutes. (∑ x − component ) + (∑ y − component ) (0)2 + (20 + 80 ) 2 2 2D= D= 3 D = 158.56 m m Vave = 158.56m ÷ (10 min) North Vave = 15.86 North min
24. 24. BOOKS • Richard P. Feynman, Robert B. Leighton, Matthew Sands. The Feynman Lectures on Physics, Volume I, Section 8-2. Addison-Wesley, Reading, Massachusetts (1963). ISBN 0-201-02116-1. • Robert Resnick and Jearl Walker, Fundamentals of Physics, Wiley; 7 Sub edition (June 16, 2004). ISBN 0471232319.INTERNET • http://www.physicslab.com/speed&amp;velocity.html • http://www.petsdo.com/blog/top-twenty-20-fastest- land-animals-including-humans • http://en.wikipedia.org/wiki/Speed • http://en.wikipedia.org/wiki/Velocity