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    Center 5#Summary Center 5#Summary Presentation Transcript

    • Numerically
      • Mean: arithmetic average, add all observations together and divide by the number of observations.
      • If there are n observations which are labeled as ;
      • The mean is
      • Read as “x bar”
      • Must be written with the bar!!!!
    •  
      • the middle obsevation
      • Arrange the data in order from least to greatest
      • If an odd number of obs. find the middle number
      • If an even number of obs. find the average of the middle two numbers
      • Order:
      • 2 2 3 4 5 5 6 6 7 7 7 7 7 8 9 9 9 10 11 12 14 16 19 27 35
      • Med =
      • If the distribution is symmetric the mean the median will be approximately the same
      • If the distribution is skewed to the left, the mean will be less than the median
      • If the distribution is skewed to the right, the mean will be higher than the median
      • The mean is affected by outliers and the median is resistant to outliers
      • When the data is symmetric use the mean
      • When the data is skewed use the median
      • Numeric description of the distribution
      • Minimum
      • 1 st Quartile (Q 1 ) – Middle number of the bottom half of the data
      • Median
      • 3 rd Quartile (Q 3 ) – Middle number of the top half of the data
      • Maximum
      • Put data in order
      • 2 2 3 4 5 5 6 6 7 7 7 7 7 8 9 9 9 10 11 12 14 16 19 27 35
      Min = 2 Q 1 = 5.5 Med = 7 Q 3 = 11.5 Max = 35
      • Graphical display of 5 number summary
      • Range = Max – Min
      •  
      • Interquartile Range
      • IQR = Q 3 – Q 1
      • Any observation below the Lower Fence (LF) or above the Upper Fence (UF) is considered an outlier
      • LF = Q 1 – 1.5(IQR)
      • UF = Q 3 + 1.5(IQR)
      • If outliers are present the whisker extends to the last value not an outlier
      • The outlier is marked with an x, box, or point