Penetapan normalitas na oh dengan bbp (cooh)2

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Presentasi Kelompok 5 KKPI (11-5)

Presentasi Kelompok 5 KKPI (11-5)

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  • 1. BasicReactionEquipments and the MaterialsProcedureCalculationConclusion
  • 2. Basic NaOH can be react by oxalic acidbecome sodium oxalic acid. Form the salt(COONa)2. Because of NaoH is strongbase and oxalic acid is weak acid, so usedthe PP indicator with the end point isslightly pink.
  • 3. Reaction2 NaOH (COOH)2 2 COONa 2 H 2O
  • 4. (COOH)2 . 2H2O NaOH 0,1 N PP Indicator Aquadest
  • 5. 1. Prepared the equipments and the materials that is needed.2. Balanced + 0,63 gr oxalic acid.3. Diluted by aquadest in volumetric flask.4. Take 10,00 ml of solution with volumetric pipette 10 ml.5. Get into the erlenmeyer 250 ml.6. Diluted by aquadest until + 100 ml.7. Added 2-3 drops of PP indicator.8. Titrated by NaOH 0,1 N until the end point is slightly pink.9. Write down the volume of titrant.10. Do the determination for twice.
  • 6. Take 10.00 ml of solutionBalance 0.63 grams Dissolve withof oxalic acid aquadest, and make it homogen Titrate with NaOH 0.1 N Dilute and EP : slightly add 2-3 pink drops of PP indicator
  • 7. m g sam pleN NaOH Fp Vp BstNaOH
  • 8. • This titration include into netralization titration.• The method that used is direct titration• Normality of NaOH by using Oxalic Acid as primary raw material can be calculated by formula: m g sam ple N NaOH Fp Vp BstNaOH
  • 9. (>^.^)>thank’s For You Attention!