X2 T01 07 nth roots of unity

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    X2 T01 07 nth roots of unity - Presentation Transcript

    1. nth Roots Of Unity  z n  1
    2. nth Roots Of Unity  z n  1 The solutions of equations of the form, z n  1, are the nth roots of unity
    3. nth Roots Of Unity  z n  1 The solutions of equations of the form, z n  1, are the nth roots of unity When placed on an Argand Diagram, they form a regular n sided polygon, with vertices on the unit circle.
    4. nth Roots Of Unity  z n  1 The solutions of equations of the form, z n  1, are the nth roots of unity When placed on an Argand Diagram, they form a regular n sided polygon, with vertices on the unit circle. e.g . z 5  1
    5. nth Roots Of Unity  z n  1 The solutions of equations of the form, z n  1, are the nth roots of unity When placed on an Argand Diagram, they form a regular n sided polygon, with vertices on the unit circle. e.g . z 5  1  2 k  0  z  cis   k  0, 1, 2  5 
    6. nth Roots Of Unity  z n  1 The solutions of equations of the form, z n  1, are the nth roots of unity When placed on an Argand Diagram, they form a regular n sided polygon, with vertices on the unit circle. e.g . z 5  1  2 k  0  z  cis   k  0, 1, 2  5  2 2 4 4 z  cis 0, cis , cis  , cis , cis  5 5 5 5
    7. nth Roots Of Unity  z n  1 The solutions of equations of the form, z n  1, are the nth roots of unity When placed on an Argand Diagram, they form a regular n sided polygon, with vertices on the unit circle. e.g . z 5  1  2 k  0  z  cis   k  0, 1, 2  5  2 2 4 4 z  cis 0, cis , cis  , cis , cis  y 5 5 5 5 x
    8. nth Roots Of Unity  z n  1 The solutions of equations of the form, z n  1, are the nth roots of unity When placed on an Argand Diagram, they form a regular n sided polygon, with vertices on the unit circle. e.g . z 5  1  2 k  0  z  cis   k  0, 1, 2  5  2 2 4 4 z  cis 0, cis , cis  , cis , cis  y 5 5 5 5 cis0 x
    9. nth Roots Of Unity  z n  1 The solutions of equations of the form, z n  1, are the nth roots of unity When placed on an Argand Diagram, they form a regular n sided polygon, with vertices on the unit circle. e.g . z 5  1  2 k  0  z  cis   k  0, 1, 2  5  2 2 4 4 z  cis 0, cis , cis  , cis , cis  y 2 5 5 5 5 cis 5 cis0 x
    10. nth Roots Of Unity  z n  1 The solutions of equations of the form, z n  1, are the nth roots of unity When placed on an Argand Diagram, they form a regular n sided polygon, with vertices on the unit circle. e.g . z 5  1  2 k  0  z  cis   k  0, 1, 2  5  2 2 4 4 z  cis 0, cis , cis  , cis , cis  y 2 5 5 5 5 cis 5 cis0 x 2 cis  5
    11. nth Roots Of Unity  z n  1 The solutions of equations of the form, z n  1, are the nth roots of unity When placed on an Argand Diagram, they form a regular n sided polygon, with vertices on the unit circle. e.g . z 5  1  2 k  0  z  cis   k  0, 1, 2  5  2 2 4 4 z  cis 0, cis , cis  , cis , cis  4 y 2 5 5 5 5 cis cis 5 5 cis0 x 2 cis  5
    12. nth Roots Of Unity  z n  1 The solutions of equations of the form, z n  1, are the nth roots of unity When placed on an Argand Diagram, they form a regular n sided polygon, with vertices on the unit circle. e.g . z 5  1  2 k  0  z  cis   k  0, 1, 2  5  2 2 4 4 z  cis 0, cis , cis  , cis , cis  4 y 2 5 5 5 5 cis cis 5 5 cis0 x 4 cis  2 5 cis  5
    13. nth Roots Of Unity  z n  1 The solutions of equations of the form, z n  1, are the nth roots of unity When placed on an Argand Diagram, they form a regular n sided polygon, with vertices on the unit circle. e.g . z 5  1  2 k  0  z  cis   k  0, 1, 2  5  2 2 4 4 z  cis 0, cis , cis  , cis , cis  4 y 2 5 5 5 5 cis cis 5 5 cis0 x 4 cis  2 5 cis  5
    14. nth Roots Of Unity  z n  1 The solutions of equations of the form, z n  1, are the nth roots of unity When placed on an Argand Diagram, they form a regular n sided polygon, with vertices on the unit circle. e.g . z 5  1  2 k  0  z  cis   k  0, 1, 2  5  2 2 4 4 z  cis 0, cis , cis  , cis , cis  4 y 2 5 5 5 5 cis cis 5 5 cis0 x 4 cis  2 5 cis  5
    15. b) i  If  is a complex root of z 5  1  0, show that  2 ,  3 ,  4 and  5 are the other roots.
    16. b) i  If  is a complex root of z 5  1  0, show that  2 ,  3 ,  4 and  5 are the other roots. z5  1
    17. b) i  If  is a complex root of z 5  1  0, show that  2 ,  3 ,  4 and  5 are the other roots. z5  1 If  is a solution then  5  1
    18. b) i  If  is a complex root of z 5  1  0, show that  2 ,  3 ,  4 and  5 are the other roots. z5  1 If  is a solution then  5  1     15 5 5 1
    19. b) i  If  is a complex root of z 5  1  0, show that  2 ,  3 ,  4 and  5 are the other roots. z5  1 If  is a solution then  5  1     15 5 5  1  is a solution 5
    20. b) i  If  is a complex root of z 5  1  0, show that  2 ,  3 ,  4 and  5 are the other roots. z5  1 If  is a solution then  5  1     15 5 5  1  is a solution 5      2 5 5 2
    21. b) i  If  is a complex root of z 5  1  0, show that  2 ,  3 ,  4 and  5 are the other roots. z5  1 If  is a solution then  5  1     15 5 5  1  is a solution 5      2 5 5 2  12 1
    22. b) i  If  is a complex root of z 5  1  0, show that  2 ,  3 ,  4 and  5 are the other roots. z5  1 If  is a solution then  5  1     15 5 5  1  is a solution 5      2 5 5 2  12 1  2 is a solution
    23. b) i  If  is a complex root of z 5  1  0, show that  2 ,  3 ,  4 and  5 are the other roots. z5  1 If  is a solution then  5  1     15 5 5  1  is a solution 5      2 5 5 2      3 5 5 3  12 1  2 is a solution
    24. b) i  If  is a complex root of z 5  1  0, show that  2 ,  3 ,  4 and  5 are the other roots. z5  1 If  is a solution then  5  1     15 5 5  1  is a solution 5      2 5 5 2      3 5 5 3  12  13 1 1  2 is a solution
    25. b) i  If  is a complex root of z 5  1  0, show that  2 ,  3 ,  4 and  5 are the other roots. z5  1 If  is a solution then  5  1     15 5 5  1  is a solution 5      2 5 5 2      3 5 5 3  12  13 1 1  2 is a solution  3 is a solution
    26. b) i  If  is a complex root of z 5  1  0, show that  2 ,  3 ,  4 and  5 are the other roots. z5  1 If  is a solution then  5  1     15 5 5  1  is a solution 5      2 5 5 2      3 5 5 3      4 5 5 4  12  13 1 1  2 is a solution  3 is a solution
    27. b) i  If  is a complex root of z 5  1  0, show that  2 ,  3 ,  4 and  5 are the other roots. z5  1 If  is a solution then  5  1     15 5 5  1  is a solution 5      2 5 5 2      3 5 5 3      4 5 5 4  12  13  14 1 1 1  2 is a solution  3 is a solution
    28. b) i  If  is a complex root of z 5  1  0, show that  2 ,  3 ,  4 and  5 are the other roots. z5  1 If  is a solution then  5  1     15 5 5  1  is a solution 5      2 5 5 2      3 5 5 3      4 5 5 4  12  13  14 1 1 1  2 is a solution  3 is a solution  4 is a solution
    29. b) i  If  is a complex root of z 5  1  0, show that  2 ,  3 ,  4 and  5 are the other roots. z5  1 If  is a solution then  5  1     15 5 5  1  is a solution 5      2 5 5 2      3 5 5 3      4 5 5 4  12  13  14 1 1 1  2 is a solution  3 is a solution  4 is a solution Thus if  is a root then  2 ,  3 ,  4 and  5 are also roots
    30. ii  Prove that 1     2   3   4  0
    31. ii  Prove that 1     2   3   4  0 b   2  3  4  5   a
    32. ii  Prove that 1     2   3   4  0 b   2  3  4  5   sum of the roots  a
    33. ii  Prove that 1     2   3   4  0 b   2  3  4  5   sum of the roots  a 1   2  3  4  0
    34. ii  Prove that 1     2   3   4  0 b   2  3  4  5   sum of the roots  a 1   2  3  4  0  5  1
    35. ii  Prove that 1     2   3   4  0 b   2  3  4  5   sum of the roots  a 1   2  3  4  0  5  1 OR   1  0 5
    36. ii  Prove that 1     2   3   4  0 b   2  3  4  5   sum of the roots  a 1   2  3  4  0  5  1 OR   1  0 5   11     2   3   4   0
    37. ii  Prove that 1     2   3   4  0 b   2  3  4  5   sum of the roots  a 1   2  3  4  0   1 5 OR   1  0 5  NOTE :   n    11     2   3   4   0  1  0    11     2     n1   0  
    38. ii  Prove that 1     2   3   4  0 b   2  3  4  5   sum of the roots  a 1   2  3  4  0   1 5 OR   1  0 5  NOTE :   n    11     2   3   4   0  1  0  1     2   3   4  0   1   11     2     n1   0  
    39. ii  Prove that 1     2   3   4  0 b   2  3  4  5   sum of the roots  a 1   2  3  4  0   1 5 OR   1  0 5  NOTE :   n    11     2   3   4   0  1  0  1     2   3   4  0   1   11     2     n1   0   OR 1   2  3  4
    40. ii  Prove that 1     2   3   4  0 b   2  3  4  5   sum of the roots  a 1   2  3  4  0   1 5 OR   1  0 5  NOTE :   n    11     2   3   4   0  1  0  1     2   3   4  0   1   11     2     n1   0   OR 1   2  3  4 GP: a  1, r   , n  5
    41. ii  Prove that 1     2   3   4  0 b   2  3  4  5   sum of the roots  a 1   2  3  4  0  5  1 OR   1  0 5  NOTE :   n    11     2   3   4   0  1  0  1     2   3   4  0   1   11     2     n1   0   OR a  r n  1 1   2  3  4  GP: a  1, r   , n  5 r 1
    42. ii  Prove that 1     2   3   4  0 b   2  3  4  5   sum of the roots  a 1   2  3  4  0  5  1 OR   1  0 5  NOTE :   n    11     2   3   4   0  1  0  1     2   3   4  0   1   11     2     n1   0   OR a  r n  1 1   2  3  4  GP: a  1, r   , n  5 r 1 1 5  1   1
    43. ii  Prove that 1     2   3   4  0 b   2  3  4  5   sum of the roots  a 1   2  3  4  0  5  1 OR   1  0 5  NOTE :   n    11     2   3   4   0  1  0  1     2   3   4  0   1   11     2     n1   0   OR a  r n  1 1   2  3  4  GP: a  1, r   , n  5 r 1 1 5  1  0  1
    44. ii  Prove that 1     2   3   4  0 b   2  3  4  5   sum of the roots  a 1   2  3  4  0  5  1 OR   1  0 5  NOTE :   n    11     2   3   4   0  1  0  1     2   3   4  0   1   11     2     n1   0   OR a  r n  1 1   2  3  4  GP: a  1, r   , n  5 r 1 1 5  1  5 1  0  0  1
    45. ii  Prove that 1     2   3   4  0 b   2  3  4  5   sum of the roots  a 1   2  3  4  0  1 5 OR   1  0 5  NOTE :   n    11           0  2 3 4  1  0  1     2   3   4  0   11     2     n1   0   1   OR a  r n  1 1   2  3  4  GP: a  1, r   , n  5 r 1 1 5  1  5  1  0   0  1 iii  Find the quadratic equation whose roots are    4 and  2   3
    46. ii  Prove that 1     2   3   4  0 b   2  3  4  5   sum of the roots  a 1   2  3  4  0  1 5 OR   1  0 5  NOTE :   n    11           0  2 3 4  1  0  1     2   3   4  0   11     2     n1   0   1   OR a  r n  1 1   2  3  4  GP: a  1, r   , n  5 r 1 1 5  1  5  1  0   0  1 iii  Find the quadratic equation whose roots are    4 and  2   3       4  2  3
    47. ii  Prove that 1     2   3   4  0 b   2  3  4  5   sum of the roots  a 1   2  3  4  0  1 5 OR   1  0 5  NOTE :   n    11           0  2 3 4  1  0  1     2   3   4  0   11     2     n1   0   1   OR a  r n  1 1   2  3  4  GP: a  1, r   , n  5 r 1 1 5  1  5  1  0   0  1 iii  Find the quadratic equation whose roots are    4 and  2   3       4  2  3  1
    48. ii  Prove that 1     2   3   4  0 b   2  3  4  5   sum of the roots  a 1   2  3  4  0   1 5 OR   1  0 5  NOTE :   n    11           0  2 3 4  1  0  1     2   3   4  0   11     2     n1   0   1   OR a  r n  1 1   2  3  4  GP: a  1, r   , n  5 r 1 1 5  1  5  1  0   0  1 iii  Find the quadratic equation whose roots are    4 and  2   3        4 2 3      4  2   3   1
    49. ii  Prove that 1     2   3   4  0 b   2  3  4  5   sum of the roots  a 1   2  3  4  0   1 5 OR   1  0 5  NOTE :   n    11           0  2 3 4  1  0  1     2   3   4  0   11     2     n1   0   1   OR a  r n  1 1   2  3  4  GP: a  1, r   , n  5 r 1 1 5  1  5  1  0   0  1 iii  Find the quadratic equation whose roots are    4 and  2   3        4 2 3      4  2   3   1  3  4  6  7
    50. ii  Prove that 1     2   3   4  0 b   2  3  4  5   sum of the roots  a 1   2  3  4  0   1 5 OR   1  0 5  NOTE :   n    11           0  2 3 4  1  0  1     2   3   4  0   11     2     n1   0   1   OR a  r n  1 1   2  3  4  GP: a  1, r   , n  5 r 1 1 5  1  5  1  0   0  1 iii  Find the quadratic equation whose roots are    4 and  2   3        4 2 3      4  2   3   1  3  4  6  7  3  4    2  1
    51. ii  Prove that 1     2   3   4  0 b   2  3  4  5   sum of the roots  a 1   2  3  4  0   1 5 OR   1  0 5  NOTE :   n    11           0  2 3 4  1  0  1     2   3   4  0   11     2     n1   0   1   OR a  r n  1 1   2  3  4  GP: a  1, r   , n  5 r 1 1 5  1  5  1  0   0  1 iii  Find the quadratic equation whose roots are    4 and  2   3        4 2 3      4  2   3   1  3  4  6  7  3  4    2  equation is x 2  x  1  0  1
    52. c) If  is a complex cube root of unity, use the fact that 1  ω  ω 2  0 to;
    53. c) If  is a complex cube root of unity, use the fact that 1  ω  ω 2  0 to; (i ) Evaluate 1    2 3
    54. c) If  is a complex cube root of unity, use the fact that 1  ω  ω 2  0 to; (i ) Evaluate 1    2 3     3
    55. c) If  is a complex cube root of unity, use the fact that 1  ω  ω 2  0 to; (i ) Evaluate 1   2 3      3   3  1
    56. c) If  is a complex cube root of unity, use the fact that 1  ω  ω 2  0 to; (i ) Evaluate 1   2 3 1 1 (ii ) Evaluate  1  1 2     3   3  1
    57. c) If  is a complex cube root of unity, use the fact that 1  ω  ω 2  0 to; (i ) Evaluate 1   2 3 1 1 (ii ) Evaluate  1  1 2     3 1 1  2    3    1
    58. c) If  is a complex cube root of unity, use the fact that 1  ω  ω 2  0 to; (i ) Evaluate 1   2 3 1 1 (ii ) Evaluate  1  1 2     3 1 1  2    3    1 1    2
    59. c) If  is a complex cube root of unity, use the fact that 1  ω  ω 2  0 to; (i ) Evaluate 1   2 3 1 1 (ii ) Evaluate  1  1 2     3 1 1  2    3    1 1    2 2  2  1
    60. c) If  is a complex cube root of unity, use the fact that 1  ω  ω 2  0 to; (i ) Evaluate 1   2 3 1 1 (ii ) Evaluate  1  1 2     3 1 1  2    3    1 1   (iii) Form the cubic equation with roots 1, 1   , 1   2 2 2  2  1
    61. c) If  is a complex cube root of unity, use the fact that 1  ω  ω 2  0 to; (i ) Evaluate 1    2 3 1 1 (ii ) Evaluate  1  1 2     3 1 1  2    3    1 1   (iii) Form the cubic equation with roots 1, 1   , 1   2 2  z  1z  2     z  1         0 2 2 2 3  2 2 1
    62. c) If  is a complex cube root of unity, use the fact that 1  ω  ω 2  0 to; (i ) Evaluate 1    2 3 1 1 (ii ) Evaluate  1  1 2     3 1 1  2    3    1 1   (iii) Form the cubic equation with roots 1, 1   , 1   2 2  z  1z  2     z  1         0 2 2 2 3  2 2  z  1z 2  z  1  0 1
    63. c) If  is a complex cube root of unity, use the fact that 1  ω  ω 2  0 to; (i ) Evaluate 1    2 3 1 1 (ii ) Evaluate  1  1 2     3 1 1  2    3    1 1   (iii) Form the cubic equation with roots 1, 1   , 1   2 2  z  1z  2     z  1         0 2 2 2 3  2 2  z  1z 2  z  1  0 1 z  z  z  z  z 1  0 3 2 2
    64. c) If  is a complex cube root of unity, use the fact that 1  ω  ω 2  0 to; (i ) Evaluate 1    2 3 1 1 (ii ) Evaluate  1  1 2     3 1 1  2    3    1 1   (iii) Form the cubic equation with roots 1, 1   , 1   2 2  z  1z  2     z  1         0 2 2 2 3  2 2  z  1z 2  z  1  0 1 z  z  z  z  z 1  0 3 2 2 z3  2z 2  2z 1  0
    65. c) If  is a complex cube root of unity, use the fact that 1  ω  ω 2  0 to; (i ) Evaluate 1    2 3 1 1 (ii ) Evaluate  1  1 2     3 1 1  2    3    1 1   (iii) Form the cubic equation with roots 1, 1   , 1   2 2  z  1z  2     z  1         0 2 2 2 3  2 2  z  1z 2  z  1  0 1 z  z  z  z  z 1  0 3 2 2 z3  2z 2  2z 1  0 Exercise 4I; 1, 3, 5 (need 4b), 7
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