11X1 T14 04 areas

565 views
403 views

Published on

Published in: Education
0 Comments
0 Likes
Statistics
Notes
  • Be the first to comment

  • Be the first to like this

No Downloads
Views
Total views
565
On SlideShare
0
From Embeds
0
Number of Embeds
20
Actions
Shares
0
Downloads
18
Comments
0
Likes
0
Embeds 0
No embeds

No notes for slide

11X1 T14 04 areas

  1. 1. (1) Area Below x axis Areas y y = f(x) x
  2. 2. (1) Area Below x axis Areas y y = f(x) A1 a b x
  3. 3. (1) Area Below x axis Areas y y = f(x) A1 a b x  f  x dx  0 b a
  4. 4. (1) Area Below x axis Areas y y = f(x) A1 a b x  f  x dx  0 b a  A1   f  x dx b a
  5. 5. (1) Area Below x axis Areas y y = f(x) A1 c x a b A2  f  x dx  0 b a  A1   f  x dx b a
  6. 6. (1) Area Below x axis Areas y y = f(x) A1 c x a b A2  f  x dx  0 c f  x dx  0 b a b  A1   f  x dx b a
  7. 7. (1) Area Below x axis Areas y y = f(x) A1 c x a b A2  f  x dx  0 c f  x dx  0 b a b  A2    f  x dx c  A1   f  x dx b a b
  8. 8. Area below x axis is given by;
  9. 9. Area below x axis is given by; A    f  x dx c b
  10. 10. Area below x axis is given by; A    f  x dx c b OR  f  x dx c  b
  11. 11. Area below x axis is given by; A    f  x dx c b OR  f  x dx c  b OR   f  x dx b c
  12. 12. e.g. (i) y y  x3 -1 1 x
  13. 13. e.g. (i) y y  x3 0 1 A    x dx   x 3 dx 3 1 0 -1 1 x
  14. 14. e.g. (i) y y  x3 0 1 A    x dx   x 3 dx 3 1 0  4 x 1  4 x 0 1 40 1 41 -1 1 x
  15. 15. e.g. (i) y y  x3 0 1 A    x dx   x 3 dx 3 1 0  4 x 1  4 x 0 1 40 1 41 -1 1 x 1 4  4    0   1   4  0 1 4 1 1 1   4 4 1  units 2 2
  16. 16. e.g. (i) y y  x3 0 1 A    x dx   x 3 dx 3 1 0  4 x 1  4 x 0 1 40 1 41 -1 1 x 1 4  4    0   1   4  0 1 4 1 1 1   OR using symmetry of odd function 4 4 1  units 2 2
  17. 17. e.g. (i) y y  x3 0 1 A    x dx   x 3 dx 3 1 0  4 x 1  4 x 0 1 40 1 41 -1 1 x 1 4  4    0   1   4  0 1 4 1 1 1   OR using symmetry of odd function 4 4 1 1 A  2  x 3 dx  units 2 0 2
  18. 18. e.g. (i) y y  x3 0 1 A    x dx   x 3 dx 3 1 0  4 x 1  4 x 0 1 40 1 41 -1 1 x 1 4  4    0   1   4  0 1 4 1 1 1   OR using symmetry of odd function 4 4 1 1 A  2  x 3 dx  units 2 0 2  x 0 1 41 2
  19. 19. e.g. (i) y y  x3 0 1 A    x dx   x 3 dx 3 1 0  4 x 1  4 x 0 1 40 1 41 -1 1 x 1 4  4    0   1   4  0 1 4 1 1 1   OR using symmetry of odd function 4 4 1 1 A  2  x 3 dx  units 2 0 2  x 0 1 41 2   4  0 1 1 2 1  units 2 2
  20. 20. (ii) y y  x x  1 x  2  -2 -1 x
  21. 21. (ii) y y  x x  1 x  2  -2 -1 x A   x  3 x  2 x dx   x 3  3 x 2  2 x dx 1 0 3 2 2 1
  22. 22. (ii) y y  x x  1 x  2  -2 -1 x A   x  3 x  2 x dx   x 3  3 x 2  2 x dx 1 0 3 2 2 1 1 1   x 4  x3  x 2    x 4  x3  x 2  1 1 4   2  4   0 
  23. 23. (ii) y y  x x  1 x  2  -2 -1 x A   x  3 x  2 x dx   x 3  3 x 2  2 x dx 1 0 3 2 2 1 1 1   x 4  x3  x 2    x 4  x3  x 2  1 1 4   2  4   0   2 1  14   13   12    1  2 4   2 3   2 2   0     4   4  1  units 2 2
  24. 24. (2) Area On The y axis y y = f(x) (b,d) (a,c) x
  25. 25. (2) Area On The y axis (1) Make x the subject y i.e. x = g(y) y = f(x) (b,d) (a,c) x
  26. 26. (2) Area On The y axis (1) Make x the subject y i.e. x = g(y) y = f(x) (2) Substitute the y coordinates (b,d) (a,c) x
  27. 27. (2) Area On The y axis (1) Make x the subject y i.e. x = g(y) y = f(x) (2) Substitute the y coordinates (b,d) d 3 A   g  y dy c (a,c) x
  28. 28. (2) Area On The y axis (1) Make x the subject y i.e. x = g(y) y = f(x) (2) Substitute the y coordinates (b,d) d 3 A   g  y dy c (a,c) x e.g. y y  x4 1 2 x
  29. 29. (2) Area On The y axis (1) Make x the subject y i.e. x = g(y) y = f(x) (2) Substitute the y coordinates (b,d) d 3 A   g  y dy c (a,c) x e.g. y y  x4 1 x y 4 1 2 x
  30. 30. (2) Area On The y axis (1) Make x the subject y i.e. x = g(y) y = f(x) (2) Substitute the y coordinates (b,d) d 3 A   g  y dy c (a,c) 16 1 x A   y dy 4 1 e.g. y y  x4 1 x y 4 1 2 x
  31. 31. (2) Area On The y axis (1) Make x the subject y i.e. x = g(y) y = f(x) (2) Substitute the y coordinates (b,d) d 3 A   g  y dy c (a,c) 16 1 x A   y dy 4 1 5 16 e.g. y yx 4 4  1  y  4 5  1 x y 4 1 2 x
  32. 32. (2) Area On The y axis (1) Make x the subject y i.e. x = g(y) y = f(x) (2) Substitute the y coordinates (b,d) d 3 A   g  y dy c (a,c) 16 1 x A   y dy 4 1 5 16 e.g. y yx 4 4  1  y  4 5  1 x y 4 4  5 5  16 4  14  5  1 2 x 124  units 2 5
  33. 33. (3) Area Between Two Curves y x
  34. 34. (3) Area Between Two Curves y y = f(x)…(1) x
  35. 35. (3) Area Between Two Curves y y = g(x)…(2) y = f(x)…(1) x
  36. 36. (3) Area Between Two Curves y y = g(x)…(2) y = f(x)…(1) a b x
  37. 37. (3) Area Between Two Curves y y = g(x)…(2) y = f(x)…(1) a b x Area = Area under (1) – Area under (2)
  38. 38. (3) Area Between Two Curves y y = g(x)…(2) y = f(x)…(1) a b x Area = Area under (1) – Area under (2) b b   f  x dx   g  x dx a a
  39. 39. (3) Area Between Two Curves y y = g(x)…(2) y = f(x)…(1) a b x Area = Area under (1) – Area under (2) b b   f  x dx   g  x dx a a b    f  x   g  x dx a
  40. 40. e.g. Find the area enclosed between the curves y  x 5 and y  x in the positive quadrant.
  41. 41. e.g. Find the area enclosed between the curves y  x 5 and y  x in the positive quadrant. y y  x5 yx x
  42. 42. e.g. Find the area enclosed between the curves y  x 5 and y  x in the positive quadrant. y y  x5 yx x x x 5
  43. 43. e.g. Find the area enclosed between the curves y  x 5 and y  x in the positive quadrant. y y  x5 yx x x x 5 x5  x  0 xx 4  1  0 x  0 or x  1
  44. 44. e.g. Find the area enclosed between the curves y  x 5 and y  x in the positive quadrant. y y  x5 yx A   x  x 5 dx 1 x 0 x x 5 x5  x  0 xx 4  1  0 x  0 or x  1
  45. 45. e.g. Find the area enclosed between the curves y  x 5 and y  x in the positive quadrant. y y  x5 yx A   x  x 5 dx 1 x 0 x x 5 1 1 1  x5  x  0   x2  x6  2 6 0 xx 4  1  0 x  0 or x  1
  46. 46. e.g. Find the area enclosed between the curves y  x 5 and y  x in the positive quadrant. y y  x5 yx A   x  x 5 dx 1 x 0 x x 5 1 1 1  x5  x  0   x2  x6  2 6 0 xx 4  1  0 1 1 2  1 1 6   0    x  0 or x  1  2 6  1  unit 2 3
  47. 47. 2002 HSC Question 4d) The graphs of y  x  4 and y  x 2  4 x intersect at the points  4,0  A.
  48. 48. 2002 HSC Question 4d) The graphs of y  x  4 and y  x 2  4 x intersect at the points  4,0  A. (i) Find the coordinates of A (2)
  49. 49. 2002 HSC Question 4d) The graphs of y  x  4 and y  x 2  4 x intersect at the points  4,0  A. (i) Find the coordinates of A (2) To find points of intersection, solve simultaneously
  50. 50. 2002 HSC Question 4d) The graphs of y  x  4 and y  x 2  4 x intersect at the points  4,0  A. (i) Find the coordinates of A (2) To find points of intersection, solve simultaneously x  4  x2  4x
  51. 51. 2002 HSC Question 4d) The graphs of y  x  4 and y  x 2  4 x intersect at the points  4,0  A. (i) Find the coordinates of A (2) To find points of intersection, solve simultaneously x  4  x2  4x x2  5x  4  0
  52. 52. 2002 HSC Question 4d) The graphs of y  x  4 and y  x 2  4 x intersect at the points  4,0  A. (i) Find the coordinates of A (2) To find points of intersection, solve simultaneously x  4  x2  4x x2  5x  4  0  x  4  x  1  0
  53. 53. 2002 HSC Question 4d) The graphs of y  x  4 and y  x 2  4 x intersect at the points  4,0  A. (i) Find the coordinates of A (2) To find points of intersection, solve simultaneously x  4  x2  4x x2  5x  4  0  x  4  x  1  0 x  1 or x  4
  54. 54. 2002 HSC Question 4d) The graphs of y  x  4 and y  x 2  4 x intersect at the points  4,0  A. (i) Find the coordinates of A (2) To find points of intersection, solve simultaneously x  4  x2  4x x2  5x  4  0  x  4  x  1  0 x  1 or x  4  A is (1, 3)
  55. 55. (ii) Find the area of the shaded region bounded by y  x 2  4 x and (3) y  x  4.
  56. 56. (ii) Find the area of the shaded region bounded by y  x 2  4 x and (3) y  x  4. 4 A    x  4   x 2  4 x  dx 1
  57. 57. (ii) Find the area of the shaded region bounded by y  x 2  4 x and (3) y  x  4. 4 A    x  4   x 2  4 x  dx 1 4     x 2  5 x  4 dx 1
  58. 58. (ii) Find the area of the shaded region bounded by y  x 2  4 x and (3) y  x  4. 4 A    x  4   x 2  4 x  dx 1 4     x 2  5 x  4 dx 1 4   1 x3  5 x 2  4 x    3 2 1 
  59. 59. (ii) Find the area of the shaded region bounded by y  x 2  4 x and (3) y  x  4. 4 A    x  4   x 2  4 x  dx 1 4     x 2  5 x  4 dx 1 4   1 x3  5 x 2  4 x   3 2 1  1 3 5 2  1 3 5 2    4    4   4  4    1  1  4 1 3 2 3 2 
  60. 60. (ii) Find the area of the shaded region bounded by y  x 2  4 x and (3) y  x  4. 4 A    x  4   x 2  4 x  dx 1 4     x 2  5 x  4 dx 1 4   1 x3  5 x 2  4 x   3 2 1  1 3 5 2  1 3 5 2    4    4   4  4    1  1  4 1 3 2 3 2  9  units 2 2
  61. 61. 2005 HSC Question 8b) (3) The shaded region in the diagram is bounded by the circle of radius 2 centred at the origin, the parabola y  x 2  3 x  2 , and the x axis. By considering the difference of two areas, find the area of the shaded region.
  62. 62. 2005 HSC Question 8b) (3) The shaded region in the diagram is bounded by the circle of radius 2 centred at the origin, the parabola y  x 2  3 x  2 , and the x axis. By considering the difference of two areas, find the area of the shaded region. Note: area must be broken up into two areas, due to the different boundaries.
  63. 63. 2005 HSC Question 8b) (3) The shaded region in the diagram is bounded by the circle of radius 2 centred at the origin, the parabola y  x 2  3 x  2 , and the x axis. By considering the difference of two areas, find the area of the shaded region. Note: area must be broken up into two areas, due to the different boundaries.
  64. 64. 2005 HSC Question 8b) (3) The shaded region in the diagram is bounded by the circle of radius 2 centred at the origin, the parabola y  x 2  3 x  2 , and the x axis. By considering the difference of two areas, find the area of the shaded region. Note: area must be broken up into two areas, due to the different boundaries. Area between circle and parabola
  65. 65. 2005 HSC Question 8b) (3) The shaded region in the diagram is bounded by the circle of radius 2 centred at the origin, the parabola y  x 2  3 x  2 , and the x axis. By considering the difference of two areas, find the area of the shaded region. Note: area must be broken up into two areas, due to the different boundaries. Area between circle and parabola and area between circle and x axis
  66. 66. It is easier to subtract the area under the parabola from the quadrant.
  67. 67. It is easier to subtract the area under the parabola from the quadrant. 1 A    2     x 2  3 x  2 dx 1 2 4 0
  68. 68. It is easier to subtract the area under the parabola from the quadrant. 1 A    2     x 2  3 x  2 dx 1 2 4 0 1     x  x  2x 1 3 3 2 3  2 0 
  69. 69. It is easier to subtract the area under the parabola from the quadrant. 1 A    2     x 2  3 x  2 dx 1 2 4 0 1     x  x  2x 1 3 3 2 3  2 0   1 3 3 2    1  1  2 1  0 3 2 
  70. 70. It is easier to subtract the area under the parabola from the quadrant. 1 A    2     x 2  3 x  2 dx 1 2 4 0 1     x  x  2x 1 3 3 2 3  2 0   1 3 3 2    1  1  2 1  0 3 2     5  units 2   6
  71. 71. Exercise 11E; 2bceh, 3bd, 4bd, 5bd, 7begj, 8d, 9a, 11, 18* Exercise 11F; 1bdeh, 4bd, 7d, 10, 11b, 13, 15*

×