As the widths decrease, the estimate becomes more accurate, lets
investigate one of these rectangles.
y
y = f(x)
x
As the widths decrease, the estimate becomes more accurate, lets
investigate one of these rectangles.
y
y = f(x)
x
As the widths decrease, the estimate becomes more accurate, lets
investigate one of these rectangles.
y
y = f(x)
c x
A(c) is the area from 0 to c
As the widths decrease, the estimate becomes more accurate, lets
investigate one of these rectangles.
y
y = f(x)
c x x
A(c) is the area from 0 to c
A(x) is the area from 0 to x
A(x) – A(c) denotes the area from c to x, and can be estimated by
the rectangle;
A(x) – A(c) denotes the area from c to x, and can be estimated by
the rectangle;
f(x)
x-c
A(x) – A(c) denotes the area from c to x, and can be estimated by
the rectangle;
f(x)
x-c
A x Ac x c f x
A(x) – A(c) denotes the area from c to x, and can be estimated by
the rectangle;
f(x)
x-c
A x Ac x c f x
A x Ac
f x
xc
A(x) – A(c) denotes the area from c to x, and can be estimated by
the rectangle;
f(x)
x-c
A x Ac x c f x
A x Ac
f x
xc
Ac h Ac
h = width of rectangle
h
A(x) – A(c) denotes the area from c to x, and can be estimated by
the rectangle;
f(x)
x-c
A x Ac x c f x
A x Ac
f x
xc
Ac h Ac
h = width of rectangle
h
As the width of the rectangle decreases, the estimate becomes more
accurate.
i.e. as h 0, the Area becomes exact
i.e. as h 0, the Area becomes exact
Ac h Ac
f x lim
h 0 h
i.e. as h 0, the Area becomes exact
Ac h Ac
f x lim
h 0 h
A x h A x
lim
h 0
as h 0, c x
h
i.e. as h 0, the Area becomes exact
Ac h Ac
f x lim
h 0 h
A x h A x
lim
h 0
as h 0, c x
h
A x
i.e. as h 0, the Area becomes exact
Ac h Ac
f x lim
h 0 h
A x h A x
lim
h 0
as h 0, c x
h
A x
the equation of the curve is the derivative of the Area function.
i.e. as h 0, the Area becomes exact
Ac h Ac
f x lim
h 0 h
A x h A x
lim
h 0
as h 0, c x
h
A x
the equation of the curve is the derivative of the Area function.
The area under the curve y f x between x a and x b is;
i.e. as h 0, the Area becomes exact
Ac h Ac
f x lim
h 0 h
A x h A x
lim
h 0
as h 0, c x
h
A x
the equation of the curve is the derivative of the Area function.
The area under the curve y f x between x a and x b is;
b
A f x dx
a
i.e. as h 0, the Area becomes exact
Ac h Ac
f x lim
h 0 h
A x h A x
lim
h 0
as h 0, c x
h
A x
the equation of the curve is the derivative of the Area function.
The area under the curve y f x between x a and x b is;
b
A f x dx
a
F b F a
i.e. as h 0, the Area becomes exact
Ac h Ac
f x lim
h 0 h
A x h A x
lim
h 0
as h 0, c x
h
A x
the equation of the curve is the derivative of the Area function.
The area under the curve y f x between x a and x b is;
b
A f x dx
a
F b F a
where F x is the primitive function of f x
e.g. (i) Find the area under the curve y x 3 , between x = 0 and
x= 2
e.g. (i) Find the area under the curve y x 3 , between x = 0 and
2
x= 2
A x 3 dx
0
e.g. (i) Find the area under the curve y x 3 , between x = 0 and
2
x= 2
A x 3 dx
0
2
x4
1
4 0
e.g. (i) Find the area under the curve y x 3 , between x = 0 and
2
x= 2
A x 3 dx
0
2
x4
1
4 0
2 04
1 4
4
e.g. (i) Find the area under the curve y x 3 , between x = 0 and
2
x= 2
A x 3 dx
0
2
x4
1
4 0
2 04
1 4
4
4 units 2
e.g. (i) Find the area under the curve y x 3 , between x = 0 and
2
x= 2
A x 3 dx
0
2
x4
1
4 0
2 04
1 4
4
4 units 2
3
ii x 2 1dx
2
e.g. (i) Find the area under the curve y x 3 , between x = 0 and
2
x= 2
A x 3 dx
0
2
x4
1
4 0
2 04
1 4
4
4 units 2
3 3
ii x 1dx
2 1 x 3 x
2
2 3
e.g. (i) Find the area under the curve y x 3 , between x = 0 and
2
x= 2
A x 3 dx
0
2
x4
1
4 0
2 04
1 4
4
4 units 2
3 3
ii x 1dx
2 1 x 3 x
2
2 3
1 33 3 1 2 3 2
3 3
e.g. (i) Find the area under the curve y x 3 , between x = 0 and
2
x= 2
A x 3 dx
0
2
x4
1
4 0
2 04
1 4
4
4 units 2
3 3
ii x 1dx
2 1 x 3 x
2
2 3
1 33 3 1 2 3 2
3 3
22
3
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