Slideshare uses cookies to improve functionality and performance, and to provide you with relevant advertising. If you continue browsing the site, you agree to the use of cookies on this website. See our User Agreement and Privacy Policy.

Slideshare uses cookies to improve functionality and performance, and to provide you with relevant advertising. If you continue browsing the site, you agree to the use of cookies on this website. See our Privacy Policy and User Agreement for details.

Like this presentation? Why not share!

- Motion in two dimensions by mkhwanda 3183 views
- 05 kinematics in two dimension by IZZUDIN IBRAHIM 2517 views
- Relative motion by Mustafa Demirdag 1985 views
- Relative Motion by Woodland Christia... 944 views
- Relative velocity by indrasir 6093 views
- Relative velocity introduction by Lily Maryati 5770 views

1,382 views

1,083 views

1,083 views

Published on

No Downloads

Total views

1,382

On SlideShare

0

From Embeds

0

Number of Embeds

0

Shares

0

Downloads

48

Comments

0

Likes

2

No embeds

No notes for slide

- 1. +
- 2. + Motion in Two Dimensions
- 3. + Projectile Motion Two-dimensional motion is called projectile motion. Objects that are thrown or launched into the air and are subject to gravity are called projectiles. Some examples of projectiles are Softballs, Footballs Arrows
- 4. + The parabolic path which is common for all projectile motion is called trajectory. The horizontal distance covered by a projectile which returns its original height is called the range of the projectile.
- 5. + An object is projected with an initial velocity, vi, at an angle of θ. Resolve the initial velocity into its x and ycomponents. Then, the kinematic equations can be applied to describe the motion of the projectile throughout its flight.
- 6. + Suppose the initial velocity vector makes an angle θ with the horizontal. Again, to analyze the motion of such a projectile, you must resolve the initial velocity vector into its components. vx,i= vicosθ and vy,i= visinθ
- 7. + Example: (a) Without air resistance, the soccer ball would travel along a parabola. (b) With air resistance, the soccer ball would travel along a shorter path.
- 8. + Example: (a) A long jumper’s velocity while sprinting along the runway can be represented by a horizontal vector. (b) Once the jumper is airborne, the jumper’s velocity at any instant can be described by the components of the velocity.
- 9. + We can substitute these values for v0x and v0y into the kinematic equations to obtain a set of equations that can be used to analyze the motion of a projectile launched at an angle. v0x=v0cosθ For the motion on x x = v0xt = v0cosθt axis v0y=v0sinθ vy = v0y – gt Δy =v0yt – (1/2)gt2 For the motion on y Δy = (1/2)(v0y+vy)t axis vy2 = v0y2 – 2gΔy The relation between v2 = vx2 + vy2 speeds
- 10. + Example A ball is launched at a velocity of 8 m/s and an angle of 53o with the horizontal line axis. a) Calculate the time for the ball to reach its max. height. b) How high will the ball rise? c) What is the range of the ball? d) What is the ball’s velocity just before it strikes the ground?
- 11. + Example A rocket is launched at a velocity of 25 m/s and an angle of 37o with the horizontal line axis. a) Calculate the time for the ball to reach its max. height. b) How high will the ball rise? c) What is the range of the ball? d) What is the ball’s velocity just before it strikes the ground?

No public clipboards found for this slide

Be the first to comment