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# Physics/Notes 6.2

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### Physics/Notes 6.2

1. 1. Motion in Two Dimensions
2. 2. Section 6.2Circular Motion How do I explain why an object that is moving in a circle at constant velocity has acceleration? How can I calculate centripetal acceleration? How can I identify the forces that cause centripetal acceleration?
3. 3. Uniform Circular Motion A mass being rotated at a constant velocity
4. 4. Uniform Circular Motion Velocity is constant The velocity vector is constantly changing direction This change in direction provides an acceleration towards the center of the circle
5. 5. Centripetal Acceleration
6. 6. Circular Velocity What if they do not give you velocity in m/s? How about 33 rpm? T = Period = the time needed to turn 1 complete revolution What is the T for a 33 rpm record?
7. 7. Centripetal Acceleration
8. 8. Centripetal Force Since the acceleration points towards the center, the centripetal force points towards the center F = ma, so Fc = ? Fc is the result of another force that turns the object in a circle This force can be supplied by tension or friction
9. 9. Centripetal Force Supplied by tension A 13 g stopper is attached to a 0.93 m string. The stopper is swung in a horizontal circle, making one revolution in 1.18 s. Find the tension force exerted by the string on the stopper.
10. 10. Centripetal Force
11. 11. Homework Page 156 # 12 - 15