11 Y B=M(X A)

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11 Y B=M(X A)

  1. 1. Finding Equation of any Line 11.
  2. 2. Finding Equation of any Line 0 y x A (x , y) B (x 1 , y 1 ) Take the points A and B shown in the diagram. To find the gradient we have: NB y = mx + c is simply a variation on this with point (0 , c) substituted
  3. 3. Copy the following: To find the equation of any line if we know at least one point on that line we use: This is the most important formula in this outcome
  4. 4. Example 1 Find the equation of the line with gradient -2 passing through (-1 , 3) Solution : <ul><li>Have m and a point on the </li></ul><ul><li>line so sub into: </li></ul>2. Get rid of brackets 3. Tidy up and make sure X’s are positive Double Negatives
  5. 5. Example 2 Solution : <ul><li>Must find the gradient this time </li></ul><ul><li>Sub x and y-values of either </li></ul><ul><li>point into </li></ul>Find the equation of the line through the points (4 , 9) and (6 , -1) 3. Tidy up and make sure X’s are positive NAB
  6. 6. Heinemann, p.11, Ex 1G, Q2, 3 & 4

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