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Slide 1: Given: Initial Amount Ao = 30g m= 1 Multiplying Factor 2 Period p = 8 days A = ? Final Amount t Time that has passed The formula we are using is.. A = Ao(m)(t/p) 1
Slide 2: How much will remain of the 30g sample in the following time: a.) 2 weeks = 14 days First, change the weeks into days since the half life of the substance is in days. Then, substitute the given values to the equation. A = Ao(m)(t/p) A = 30 (1/2)(14/8) A = 8.9191 8.9191 g will remain in 2 weeks. 2
Slide 3: b.) 278 days A = Ao(m)(t/p) A = 30(1/2)(278/8) A = 1.0 x 109 1.0 x 109 g will remain in 278 days. c.) 1 year = 365 days First, change the year into days. There are 365 days in a year. Then, substitute the given values to the equation. A = Ao(m)(t/p) A = 30(1/2)(365/8) A = 5.5 x 1013 5.5 x 1013 g will remain in 1 year. 3
Slide 4: d.) 24 weeks = 168 days First, change the weeks into days since the half life of the substance is in days. Then, substitute the given values to the equation. A = Ao(m)(t/p) A = 30(1/2)(168/8) A = 1.4 x 105 1.4 x 105 g will remain in 24 weeks. 4
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