Upcoming SlideShare
Loading in …5
×

# Algebra 1B Section 5-3

479 views

Published on

Solving Multi-Step Inequalities

Published in: Education, Technology, Business
0 Comments
0 Likes
Statistics
Notes
• Full Name
Comment goes here.

Are you sure you want to Yes No
Your message goes here
• Be the first to comment

• Be the first to like this

No Downloads
Views
Total views
479
On SlideShare
0
From Embeds
0
Number of Embeds
40
Actions
Shares
0
Downloads
7
Comments
0
Likes
0
Embeds 0
No embeds

No notes for slide

### Algebra 1B Section 5-3

1. 1. SECTION 5-3 Solving Multi-Step Inequalities Monday, September 30, 13
2. 2. ESSENTIAL QUESTION • How do we solve multi-step inequalities? Monday, September 30, 13
3. 3. WARM UP 2x − 7 = 9 + 4xa. 1 2 a = a − 3 4 b. Monday, September 30, 13
4. 4. WARM UP 2x − 7 = 9 + 4xa. 1 2 a = a − 3 4 b. −2x Monday, September 30, 13
5. 5. WARM UP 2x − 7 = 9 + 4xa. 1 2 a = a − 3 4 b. −2x −2x Monday, September 30, 13
6. 6. WARM UP 2x − 7 = 9 + 4xa. 1 2 a = a − 3 4 b. −2x −2x−9 Monday, September 30, 13
7. 7. WARM UP 2x − 7 = 9 + 4xa. 1 2 a = a − 3 4 b. −2x −2x−9−9 Monday, September 30, 13
8. 8. WARM UP 2x − 7 = 9 + 4xa. 1 2 a = a − 3 4 b. −2x −2x−9−9 Monday, September 30, 13
9. 9. WARM UP 2x − 7 = 9 + 4xa. 1 2 a = a − 3 4 b. −2x −2x−9−9 −16 = 2x Monday, September 30, 13
10. 10. WARM UP 2x − 7 = 9 + 4xa. 1 2 a = a − 3 4 b. −2x −2x−9−9 −16 = 2x 22 Monday, September 30, 13
11. 11. WARM UP 2x − 7 = 9 + 4xa. 1 2 a = a − 3 4 b. −2x −2x−9−9 −16 = 2x 22 −8 = x Monday, September 30, 13
12. 12. WARM UP 2x − 7 = 9 + 4xa. 1 2 a = a − 3 4 b. −2x −2x−9−9 −16 = 2x 22 −8 = x x = −8 Monday, September 30, 13
13. 13. WARM UP 2x − 7 = 9 + 4xa. 1 2 a = a − 3 4 b. −2x −2x−9−9 −16 = 2x 22 −8 = x x = −8 4 • 1 2 a = a − 3 4 • 4 Monday, September 30, 13
14. 14. WARM UP 2x − 7 = 9 + 4xa. 1 2 a = a − 3 4 b. −2x −2x−9−9 −16 = 2x 22 −8 = x x = −8 4 • 1 2 a = a − 3 4 • 4 2a = a − 3 Monday, September 30, 13
15. 15. WARM UP 2x − 7 = 9 + 4xa. 1 2 a = a − 3 4 b. −2x −2x−9−9 −16 = 2x 22 −8 = x x = −8 4 • 1 2 a = a − 3 4 • 4 2a = a − 3 −a−a Monday, September 30, 13
16. 16. WARM UP 2x − 7 = 9 + 4xa. 1 2 a = a − 3 4 b. −2x −2x−9−9 −16 = 2x 22 −8 = x x = −8 4 • 1 2 a = a − 3 4 • 4 2a = a − 3 −a−a a = −3 Monday, September 30, 13
17. 17. EXAMPLE 1 Maggie Brann has a budget of \$115 for faxes.The fax service she uses charges \$25 to activate an account and \$0.08 per page to send faxes. How many pages can she fax and stay within her budget? Identify a variable, then set up and solve an inequality. Interpret your solution. Monday, September 30, 13
18. 18. EXAMPLE 1 Maggie Brann has a budget of \$115 for faxes.The fax service she uses charges \$25 to activate an account and \$0.08 per page to send faxes. How many pages can she fax and stay within her budget? Identify a variable, then set up and solve an inequality. Interpret your solution. p = pages she can fax Monday, September 30, 13
19. 19. EXAMPLE 1 Maggie Brann has a budget of \$115 for faxes.The fax service she uses charges \$25 to activate an account and \$0.08 per page to send faxes. How many pages can she fax and stay within her budget? Identify a variable, then set up and solve an inequality. Interpret your solution. p = pages she can fax 25+ .08p ≤115 Monday, September 30, 13
20. 20. EXAMPLE 1 Maggie Brann has a budget of \$115 for faxes.The fax service she uses charges \$25 to activate an account and \$0.08 per page to send faxes. How many pages can she fax and stay within her budget? Identify a variable, then set up and solve an inequality. Interpret your solution. p = pages she can fax 25+ .08p ≤115 −25 −25 Monday, September 30, 13
21. 21. EXAMPLE 1 Maggie Brann has a budget of \$115 for faxes.The fax service she uses charges \$25 to activate an account and \$0.08 per page to send faxes. How many pages can she fax and stay within her budget? Identify a variable, then set up and solve an inequality. Interpret your solution. p = pages she can fax 25+ .08p ≤115 −25 −25 .08p ≤ 90 Monday, September 30, 13
22. 22. EXAMPLE 1 Maggie Brann has a budget of \$115 for faxes.The fax service she uses charges \$25 to activate an account and \$0.08 per page to send faxes. How many pages can she fax and stay within her budget? Identify a variable, then set up and solve an inequality. Interpret your solution. p = pages she can fax 25+ .08p ≤115 −25 −25 .08p ≤ 90 .08 .08 Monday, September 30, 13
23. 23. EXAMPLE 1 Maggie Brann has a budget of \$115 for faxes.The fax service she uses charges \$25 to activate an account and \$0.08 per page to send faxes. How many pages can she fax and stay within her budget? Identify a variable, then set up and solve an inequality. Interpret your solution. p = pages she can fax 25+ .08p ≤115 −25 −25 .08p ≤ 90 .08 .08 p ≤1125 Monday, September 30, 13
24. 24. EXAMPLE 1 Maggie Brann has a budget of \$115 for faxes.The fax service she uses charges \$25 to activate an account and \$0.08 per page to send faxes. How many pages can she fax and stay within her budget? Identify a variable, then set up and solve an inequality. Interpret your solution. p = pages she can fax 25+ .08p ≤115 −25 −25 .08p ≤ 90 .08 .08 p ≤1125 p | p ≤1125{ } Monday, September 30, 13
25. 25. EXAMPLE 1 Maggie Brann has a budget of \$115 for faxes.The fax service she uses charges \$25 to activate an account and \$0.08 per page to send faxes. How many pages can she fax and stay within her budget? Identify a variable, then set up and solve an inequality. Interpret your solution. p = pages she can fax 25+ .08p ≤115 −25 −25 .08p ≤ 90 .08 .08 p ≤1125 p | p ≤1125{ } Maggie can send up to 1125 faxes. Monday, September 30, 13
26. 26. EXAMPLE 2 Solve the inequality. 13−11d ≥ 79 Monday, September 30, 13
27. 27. EXAMPLE 2 Solve the inequality. 13−11d ≥ 79 −13 −13 Monday, September 30, 13
28. 28. EXAMPLE 2 Solve the inequality. 13−11d ≥ 79 −13 −13 −11d ≥ 66 Monday, September 30, 13
29. 29. EXAMPLE 2 Solve the inequality. 13−11d ≥ 79 −13 −13 −11d ≥ 66 −11 −11 Monday, September 30, 13
30. 30. EXAMPLE 2 Solve the inequality. 13−11d ≥ 79 −13 −13 −11d ≥ 66 −11 −11 d ≤ −6 Monday, September 30, 13
31. 31. EXAMPLE 2 Solve the inequality. 13−11d ≥ 79 −13 −13 −11d ≥ 66 −11 −11 d ≤ −6 d | d ≤ −6{ } Monday, September 30, 13
32. 32. EXAMPLE 3 Deﬁne a variable, write an inequality and solve the problem.Then check your solution. Four times a number increased by twelve is less than the difference of that number and three. Monday, September 30, 13
33. 33. EXAMPLE 3 Deﬁne a variable, write an inequality and solve the problem.Then check your solution. Four times a number increased by twelve is less than the difference of that number and three. n = the number Monday, September 30, 13
34. 34. EXAMPLE 3 Deﬁne a variable, write an inequality and solve the problem.Then check your solution. Four times a number increased by twelve is less than the difference of that number and three. n = the number 4n +12 < n − 3 Monday, September 30, 13
35. 35. EXAMPLE 3 Deﬁne a variable, write an inequality and solve the problem.Then check your solution. Four times a number increased by twelve is less than the difference of that number and three. n = the number 4n +12 < n − 3 −n −n Monday, September 30, 13
36. 36. EXAMPLE 3 Deﬁne a variable, write an inequality and solve the problem.Then check your solution. Four times a number increased by twelve is less than the difference of that number and three. n = the number 4n +12 < n − 3 −n −n 3n +12 < −3 Monday, September 30, 13
37. 37. EXAMPLE 3 Deﬁne a variable, write an inequality and solve the problem.Then check your solution. Four times a number increased by twelve is less than the difference of that number and three. n = the number 4n +12 < n − 3 −n −n 3n +12 < −3 −12 −12 Monday, September 30, 13
38. 38. EXAMPLE 3 Deﬁne a variable, write an inequality and solve the problem.Then check your solution. Four times a number increased by twelve is less than the difference of that number and three. n = the number 4n +12 < n − 3 −n −n 3n +12 < −3 −12 −12 3n < −15 Monday, September 30, 13
39. 39. EXAMPLE 3 Deﬁne a variable, write an inequality and solve the problem.Then check your solution. Four times a number increased by twelve is less than the difference of that number and three. n = the number 4n +12 < n − 3 −n −n 3n +12 < −3 −12 −12 3n < −15 3n < −15 Monday, September 30, 13
40. 40. EXAMPLE 3 Deﬁne a variable, write an inequality and solve the problem.Then check your solution. Four times a number increased by twelve is less than the difference of that number and three. n = the number 4n +12 < n − 3 −n −n 3n +12 < −3 −12 −12 3n < −15 3n < −15 3 3 Monday, September 30, 13
41. 41. EXAMPLE 3 Deﬁne a variable, write an inequality and solve the problem.Then check your solution. Four times a number increased by twelve is less than the difference of that number and three. n = the number 4n +12 < n − 3 −n −n 3n +12 < −3 −12 −12 3n < −15 3n < −15 3 3 n < −5 Monday, September 30, 13
42. 42. EXAMPLE 3 Deﬁne a variable, write an inequality and solve the problem.Then check your solution. Four times a number increased by twelve is less than the difference of that number and three. n = the number 4n +12 < n − 3 −n −n 3n +12 < −3 −12 −12 3n < −15 3n < −15 3 3 n < −5 n | n < −5{ } Monday, September 30, 13
43. 43. EXAMPLE 4 6c + 3(2 − c) > −2c +1a. Monday, September 30, 13
44. 44. EXAMPLE 4 6c + 3(2 − c) > −2c +1a. 6c + 6 − 3c > −2c +1 Monday, September 30, 13
45. 45. EXAMPLE 4 6c + 3(2 − c) > −2c +1a. 6c + 6 − 3c > −2c +1 3c + 6 > −2c +1 Monday, September 30, 13
46. 46. EXAMPLE 4 6c + 3(2 − c) > −2c +1a. 6c + 6 − 3c > −2c +1 3c + 6 > −2c +1 +2c +2c Monday, September 30, 13
47. 47. EXAMPLE 4 6c + 3(2 − c) > −2c +1a. 6c + 6 − 3c > −2c +1 3c + 6 > −2c +1 +2c +2c 5c + 6 > +1 Monday, September 30, 13
48. 48. EXAMPLE 4 6c + 3(2 − c) > −2c +1a. 6c + 6 − 3c > −2c +1 3c + 6 > −2c +1 +2c +2c 5c + 6 > +1 −6 −6 Monday, September 30, 13
49. 49. EXAMPLE 4 6c + 3(2 − c) > −2c +1a. 6c + 6 − 3c > −2c +1 3c + 6 > −2c +1 +2c +2c 5c + 6 > +1 −6 −6 5c > −5 Monday, September 30, 13
50. 50. EXAMPLE 4 6c + 3(2 − c) > −2c +1a. 6c + 6 − 3c > −2c +1 3c + 6 > −2c +1 +2c +2c 5c + 6 > +1 −6 −6 5c > −5 5 5 Monday, September 30, 13
51. 51. EXAMPLE 4 6c + 3(2 − c) > −2c +1a. 6c + 6 − 3c > −2c +1 3c + 6 > −2c +1 +2c +2c 5c + 6 > +1 −6 −6 5c > −5 5 5 c > −1 Monday, September 30, 13
52. 52. EXAMPLE 4 6c + 3(2 − c) > −2c +1a. 6c + 6 − 3c > −2c +1 3c + 6 > −2c +1 +2c +2c 5c + 6 > +1 −6 −6 5c > −5 5 5 c > −1 c | c > −1{ } Monday, September 30, 13
53. 53. EXAMPLE 4 −7(k + 4)+11k ≥ 8k − 2(2k +1)b. Monday, September 30, 13
54. 54. EXAMPLE 4 −7(k + 4)+11k ≥ 8k − 2(2k +1)b. −7k − 28 +11k ≥ 8k − 4k −1 Monday, September 30, 13
55. 55. EXAMPLE 4 −7(k + 4)+11k ≥ 8k − 2(2k +1)b. −7k − 28 +11k ≥ 8k − 4k −1 4k − 28 ≥ 4k −1 Monday, September 30, 13
56. 56. EXAMPLE 4 −7(k + 4)+11k ≥ 8k − 2(2k +1)b. −7k − 28 +11k ≥ 8k − 4k −1 4k − 28 ≥ 4k −1 −4k −4k Monday, September 30, 13
57. 57. EXAMPLE 4 −7(k + 4)+11k ≥ 8k − 2(2k +1)b. −7k − 28 +11k ≥ 8k − 4k −1 4k − 28 ≥ 4k −1 −4k −4k −28 ≥ −1 Monday, September 30, 13
58. 58. EXAMPLE 4 −7(k + 4)+11k ≥ 8k − 2(2k +1)b. −7k − 28 +11k ≥ 8k − 4k −1 4k − 28 ≥ 4k −1 −4k −4k −28 ≥ −1 This is an untrue statement! Monday, September 30, 13
59. 59. EXAMPLE 4 −7(k + 4)+11k ≥ 8k − 2(2k +1)b. −7k − 28 +11k ≥ 8k − 4k −1 4k − 28 ≥ 4k −1 −4k −4k −28 ≥ −1 This is an untrue statement! ∅ Monday, September 30, 13
60. 60. EXAMPLE 4 2(4r + 3) ≤ 22 + 8(r − 2)c. Monday, September 30, 13
61. 61. EXAMPLE 4 2(4r + 3) ≤ 22 + 8(r − 2)c. 8r + 6 ≤ 22 + 8r −16 Monday, September 30, 13
62. 62. EXAMPLE 4 2(4r + 3) ≤ 22 + 8(r − 2)c. 8r + 6 ≤ 22 + 8r −16 8r + 6 ≤ 8r + 6 Monday, September 30, 13
63. 63. EXAMPLE 4 2(4r + 3) ≤ 22 + 8(r − 2)c. 8r + 6 ≤ 22 + 8r −16 8r + 6 ≤ 8r + 6 −8r −8r Monday, September 30, 13
64. 64. EXAMPLE 4 2(4r + 3) ≤ 22 + 8(r − 2)c. 8r + 6 ≤ 22 + 8r −16 8r + 6 ≤ 8r + 6 −8r −8r 6 ≤ 6 Monday, September 30, 13
65. 65. EXAMPLE 4 2(4r + 3) ≤ 22 + 8(r − 2)c. 8r + 6 ≤ 22 + 8r −16 8r + 6 ≤ 8r + 6 −8r −8r 6 ≤ 6 This is a true statement! Monday, September 30, 13
66. 66. EXAMPLE 4 2(4r + 3) ≤ 22 + 8(r − 2)c. 8r + 6 ≤ 22 + 8r −16 8r + 6 ≤ 8r + 6 −8r −8r 6 ≤ 6 This is a true statement! r | r is any real number{ } Monday, September 30, 13
67. 67. EXAMPLE 4 2(4r + 3) ≤ 22 + 8(r − 2)c. 8r + 6 ≤ 22 + 8r −16 8r + 6 ≤ 8r + 6 −8r −8r 6 ≤ 6 This is a true statement! r | r is any real number{ } or Monday, September 30, 13
68. 68. EXAMPLE 4 2(4r + 3) ≤ 22 + 8(r − 2)c. 8r + 6 ≤ 22 + 8r −16 8r + 6 ≤ 8r + 6 −8r −8r 6 ≤ 6 This is a true statement! r | r is any real number{ } r | r = { } or Monday, September 30, 13
69. 69. SUMMARIZER −3p + 7 > 2How could you solve without multiplying or dividing each side by a negative number. Monday, September 30, 13
70. 70. PROBLEM SETS Monday, September 30, 13
71. 71. PROBLEM SETS Problem Set 1: p. 298 #1-11 Problem Set 2: p. 298 #13-39 odd (skip #37), "The secret of success in life is for a man to be ready for his opportunity when it comes." - Earl of Beaconsﬁeld Monday, September 30, 13