Inverse variation

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Inverse Variation

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Inverse variation

  1. 1. The length of time, m, it takesNeed to know: • It is an water to boil varies unknownk – constant of inversely as value – a variation constant temperature, t. k m t Formula • Notice the location of the k variables; As one value y x increases the other decreases. • Commonly “y vary written inversely as x” this way
  2. 2. The length of time, m, it takes water to boil k varies inversely as temperature, t. m This means the higher the temperature, the less t amount of time it takes for the water to boilNeed to know: • It is an unknownk – constant of value – a variation constant Formula • Notice the location of the k variables; As one value y increases the other x decreases. • Commonly “y vary inversely written as x” this way
  3. 3. The length of my legs, l, varies inversely as the steps I must take to cross the room, s.If it takes me 62 steps and my legs are 30 in long, find the constant of variation. k ___ Step 1: k ___l = s Fill in the given values 30 = 62 Step 2: k ___ Multiply to (62)(30)=(62) solve for k (62) 1860 = k
  4. 4. The length of my legs, l, varies inversely as the steps I must take to cross the room, s. If it takes me 62 steps and my legs are 30 in long, how many steps would it take if my legs were only 20 in long?l= k ___ Step 1: Fill in the base 30 = __ k given values 62 s k ___ Step 2: Multiply to (62)(30) = (62) solve for k (62) 1860 = k 1860 ____Step 3:Use k and the given for the 20 = 20 s = 1860second scenario to find the s s = 93 stepsmissing value
  5. 5. The length of my legs, l, varies inversely as the steps I must take to cross the room, s. If it takes me 62 steps and mylegs are 30 in long, how long would a persons legs be if it took them 60 steps?l= k ___ Step 1: Fill in the base 30 = __ k given values 62 s k ___ Step 2: Multiply to (62)(30) = (62) solve for k (62) 1860 = kStep 3: 1860 ____ = 31 inUse k and the given for thesecond scenario to find the l=missing value 60

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