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Resolución de triangulos rectángulos
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Resolución de triangulos rectángulos

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  • 1. Bach. Juan Parraguez Capitán Bach. Oscar Parraguez Capitán trigonometría AV.MAMM-MAT.5A
  • 2. RESOLUCIÓN DE TRIANGULOS RECTÁNGULOS
  • 3. RESOLUCIÓN DE TRIÁNGULOS RECTÁNGULOS CASO 1 : DATOS , HIPOTENUSA y ÁNGULO AGUDO CASO 2 : DATOS ; CATETO ADYACENTE Y ÁNGULO AGUDO
  • 4. EJEMPLO ) ) Calcular L en términos de y ; CASO 3 : DATOS; CATETO OPUESTO y ÁNGULO AGUDO
  • 5. SOLUCIÓN NOTA : DESCOMPOSICIÓN DE UN VECTOR
  • 6. ÁREA DEL TRIÁNGULO A B C a b c EJEMPLO 5m 8m
  • 7. PROBLEMAS SOBRE RESOLUCIÓN DE TRIÁNGULOS RECTÁNGULOS
    • De la figura mostrada hallar el valor de “a” y “b”, siendo θ = 37º y c = 120m.
    • Sen θ = a/c a = c. Sen θ
    • a = 120.( / )
    • a =
    • Cos θ = b/c b = c. Cos θ
    • b = 120 ( / )
    • b =
    A B C a c b
  • 8.
    • Hallar BH ; si AC = 5 m.
    • BH = a = CH (Por ángulo de 45º)
    • Tg 37º = BH / AH ¾ = a /( a +5)
    • 3( a +5) = 4a 3a +15 = 4a a = 15
    • Por lo tanto BH = 15m
    37º 45º A B H C a a 5m
  • 9.
    • 3. De la figura mostrada . Hallar BC
    • 6
    • Se traza AH Sen 30º = BH / 6 BH = 3
    • Cos 37º = HC / 5 √3 HC = 4√3
    • Luego : BC = BH + HC BC = 3 + 4√3
    A B C 6 5 √3 60º 37º H A 5√3 60º 37º B C 30º
  • 10.
    • 4. En la figura mostrada , hallar “x”
    • Tg 16º = EB / DB
    • 7/24 = X / DB
    • DB = 24 X / 7
    • Tg 37º = AB / CB
    • ¾ = 3X / (20+ 24X/7)
    • 3(20+ 24X/7) = 12X 20+ 24X/7 = 4X
    • 140 + 24X = 28X 140 = 4X
    • Luego : X = 35
    A B E D 2X X 37º 20 C 16º