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Apartment design Apartment design Document Transcript

  • ELECTRICAL SYSTEM DESIGN 1 EE- 53 ELECTRICAL PLAN SUBMITTED BY: ANGELIE M. MOROSCALLO MARK ANTHONY B. ENOY SUBMITTED TO: ENGR. URSINO TABILIRAN
  • 2 TABLE OF CONTENTS PAGE ILLUMINATION DESIGN………………………………………………………...……… 3 FIRST FLOOR………………………………………………………………………. 3 SECOND FLOOR…………………………………………………………………… 7 POWER LOAD…………………………………………………………………………….. 10 CONVENIENCE OUTLET…………………………………………………………. 10 SPECIAL OUTLETS………………………………………………………………... 11 LIGHTING LOAD………...................................................................................................... 13 SUB-FEEDER………………………………………………………………………………. 14 MAIN FEEDER……………………………………………………………………………. 17
  • 3 ILLUMINATION DESIGN FIRST FLOOR A. GARAGE AREA= 25.5 sq.m. LUX= 150 COEFFICIENT OF UTILIZATION= 0.35 MAINTENANCE FACTOR= 0.7 1. Total lamp lumens LAMP LUMENS= 2. Using TT-40W; 40W; 3150 LUMENS No. of Lamps= B. PORCH AREA= 20.375 sq.m. LUX= 150 COEFFICIENT OF UTILIZATION= 0.35 MAINTENANCE FACTOR= 0.6 1. Total lamp lumens LAMP LUMENS= 2. Using TT-40W; 40W; 3150 LUMENS No. of Lamps= C. LIVING ROOM AREA= 26.375 sq.m. LUX= 150 COEFFICIENT OF UTILIZATION= 0.45 MAINTENANCE FACTOR= 0.8 1. Total lamp lumens LAMP LUMENS= 2. Using TT-40W; 40W; 3150 LUMENS No. of Lamps=
  • 4 D. DINING ROOM AREA= 16.75 sq.m. LUX= 150 COEFFICIENT OF UTILIZATION= 0.45 MAINTENANCE FACTOR= 0.8 1. Total lamp lumens LAMP LUMENS= 2. Using TT-40W; 40W; 3150 LUMENS No. of Lamps= E. KITCHEN AREA= 10.5 sq.m. LUX= 300 COEFFICIENT OF UTILIZATION= 0.45 MAINTENANCE FACTOR= 0.8 1. Total lamp lumens LAMP LUMENS= 2. Using TT-40W; 40W; 3150 LUMENS No. of Lamps= F. BEDROOM 1 AREA= 14 sq.m. LUX= 250 COEFFICIENT OF UTILIZATION= 0.35 MAINTENANCE FACTOR= 0.8 1. Total lamp lumens LAMP LUMENS= 2. Using TT-40W; 40W; 3150 LUMENS No. of Lamps= G. BEDROOM 2 AREA= 14.5 sq.m. LUX= 250
  • 5 COEFFICIENT OF UTILIZATION= 0.35 MAINTENANCE FACTOR= 0.8 1. Total lamp lumens LAMP LUMENS= 2. Using TT-40W; 40W; 3150 LUMENS No. of Lamps= H. TOILET & BATH (T & B) AREA= 5 sq.m. LUX= 150 COEFFICIENT OF UTILIZATION= 0.25 MAINTENANCE FACTOR= 0.7 1. Total lamp lumens LAMP LUMENS= 2. Using TT-36W; 36W; 2900 LUMENS No. of Lamps= I. LAUNDRY AREA AREA= 8 sq.m. LUX= 150 COEFFICIENT OF UTILIZATION= 0.35 MAINTENANCE FACTOR= 0.7 1. Total lamp lumens LAMP LUMENS= 2. Using TT-40W; 40W; 3150 LUMENS No. of Lamps= J. LOFT/ HALLWAY AREA= 5.4 sq.m. LUX= 150 COEFFICIENT OF UTILIZATION= 0.35 MAINTENANCE FACTOR= 0.8
  • 6 1. Total lamp lumens LAMP LUMENS= 2. Using TT-18W; 1150 LUMENS No. of Lamps= K. STORAGE ROOM AREA= 2.6 sq.m. LUX= 150 COEFFICIENT OF UTILIZATION= 0.25 MAINTENANCE FACTOR= 0.6 1. Total lamp lumens LAMP LUMENS= 3. Using TT-40W; 40W; 3150 LUMENS No. of Lamps= SECOND FLOOR A. LIVING ROOM AREA= 24.9 sq.m. LUX= 150 COEFFICIENT OF UTILIZATION= 0.45
  • 7 MAINTENANCE FACTOR= 0.8 1. Total lamp lumens LAMP LUMENS= 2. Using TT-40W; 40W; 3150 LUMENS No. of Lamps= STAIRCASES AREA= 3.6 sq.m. LUX= 150 COEFFICIENT OF UTILIZATION= 0.35 MAINTENANCE FACTOR= 0.8 1. Total lamp lumens LAMP LUMENS= 2. Using TT-40W; 40W; 3150 LUMENS No. of Lamps= B. LOFT AREA= 5 sq.m. LUX= 150 COEFFICIENT OF UTILIZATION= 0.35 MAINTENANCE FACTOR= 0.8 1. Total lamp lumens LAMP LUMENS= 2. Using TT-40W; 40W; 3150 LUMENS No. of Lamps= C. MASTER’S BEDROOM AREA= 25 sq.m. LUX= 250 COEFFICIENT OF UTILIZATION= 0.35 MAINTENANCE FACTOR= 0.8 1. Total lamp lumens LAMP LUMENS=
  • 8 2. Using TT-40W; 40W; 3150 LUMENS No. of Lamps= D. MASTER’S T&B AND COMMON T&B AREA= 5 sq.m. LUX= 150 COEFFICIENT OF UTILIZATION= 0.25 MAINTENANCE FACTOR= 0.7 1. Total lamp lumens LAMP LUMENS= 2. Using TT-36W; 36W; 2900 LUMENS No. of Lamps= E. MASTER’S BALCONY AREA= 6 sq.m. LUX= 150 COEFFICIENT OF UTILIZATION= 0.35 MAINTENANCE FACTOR= 0.6 1. Total lamp lumens LAMP LUMENS= 2. Using TT-40W; 3150 LUMENS No. of Lamps= F. BEDROOM 3 & 4 AREA= 20 sq.m. LUX= 250 COEFFICIENT OF UTILIZATION= 0.35 MAINTENANCE FACTOR= 0.8 1. Total lamp lumens LAMP LUMENS= 2. Using TT-40W; 40W; 3150 LUMENS No. of Lamps=
  • 9 G. LIBRARY & COMPUTER ROOM AREA= 19.25 sq.m. LUX= 300 COEFFICIENT OF UTILIZATION= 0.45 MAINTENANCE FACTOR= 0.8 1. Total lamp lumens LAMP LUMENS= 2. Using TT-40W; 40W; 3150 LUMENS No. of Lamps= H. BALCONY AREA= 16.25 sq.m. LUX= 150 COEFFICIENT OF UTILIZATION= 0.35 MAINTENANCE FACTOR= 0.6 1. Total lamp lumens LAMP LUMENS= 2. Using TT-40W; 40W; 3150 LUMENS No. of Lamps= POWER LOAD CONVENIENCE OUTLET: A. For circuit (1, 4 & 5) with 10 outlets Maximum load for convenience outlet= 180W 1. Total load 2. Total expected current load
  • 10 3. Size of the branch circuit wire Referring to Table 2-5 Use 2 pcs. of 3.5 mm2 TW copper wire 4. Size of conduit pipe Referring to Table 2-9 Use 13 mm diameter conduit pipe 5. Size of the Overcurrent Protection Device Referring to Table 4-1 Use 1 pc. 30 Ampere trip breaker B. For circuit (2) with 6 outlets 1. 2. 3. Use 2 pcs. of 3.5 mm2 TW copper wire 4. Use 13 mm diameter conduit pipe 5. Use 1 pc. 30 Ampere trip breaker C. For circuit (3) with 7 outlets 1. 2. 3. Use 2 pcs. of 3.5 mm2 TW copper wire 4. Use 13 mm diameter conduit pipe 5. Use 1 pc. 30 Amp trip breaker SPECIAL PURPOSE OUTLET D. For circuit (6) laundry circuit at 1500 W per circuit (PEC) Total load x demand factor (df) 1. Total Expected Current Load
  • 11 2. Size of the Branch Circuit wire Referring to Table 2-5 Use 2pcs. of 3.5 mm2 TW copper wire 3. Size of conduit pipe Referring to Table 2-9 Use 13 mm diameter conduit pipe 4. Size of the Overcurrent Protection Device Referring to Table 4-1 Use 1 pc. 30 Amperes trip breaker SPECIAL PURPOSE OUTLET E. For circuit (7 & 8) with 1 unit of air condition at 2.5 HP each 1. Total load 2.5 2. Total Expected current Load “Branch circuit conductor supplying a motor shall have an ampacity not less than 125% of the full load current” 3. Size of the branch circuit wire Referring to Table 2-5 Use 2 pcs. of 5.5 mm2 TW copper wire 4. Size of conduit pipe Referring to Table 2-5 Use 20 mm diameter conduit pipe 5. Size of the Overcurrent Protection Device 8.11 x 2.5= 20.275 A Referring to Table 4-1 Use 1pc. 60 Amperes trip breaker F. For circuit (9, 10, 11 & 12) with 1 unit of air conditioner at 3 HP each 1. Total load 3 x 746= 2238 W 2. “Branch circuit conductor supplying a motor shall have an ampacity not less than 125% of the full load current” 3. Use 2 pcs. of 8.0 mm2 THW copper wire
  • 12 4. Use 30 mm diameter conduit pipe 5. 9.73 x 2.5= 24.33 A Referring to Table 4-1 Use 1pc. 70 Amperes trip breaker SPECIAL PURPOSE OUTLET G. For circuit (13) cooking unit at 5,100 W Total load x Demand Factor (df); 5,100 x 0.8= 4,080 W 1. Total Expected Current Load 2. Size of the branch circuit wire Referring to Table 2-5 Use 2 pcs. of 5.5 mm2 3. Size of conduit pipe Referring to Table 2-9 Use 20 mm diameter conduit pipe 4. Size of the Overcurrent Protection Device Referring to Table 4-1 Use 1 pc. 30 Amperes trip LIGHTING LOAD H. For circuit (14, 19 & 20) with 11 lighting outlets Maximum Load for lighting outlet= 100 W 1. Total load 11 x 100= 1100 W 2. Total Expected Current Load 3. Size of the branch circuit wire
  • 13 Referring to Table 2-5 Use 2 pcs. of 2.0 mm2 TW copper wire 4. Size of conduit pipe Referring to Table 5-7 Use 13 mm diameter conduit pipe 5. Size of the Overcurrent Protection Device Referring to Table 5-2 Use 1 pc. 15 Amperes trip breaker I. For circuit (15, 16 & 20) with 8 lighting outlets 1. 8 x 100= 800 W 2. 3. Use 2 pcs. of 2.0 mm2 TW copper wire 4. Use 13 mm diameter conduit pipe 5. Use 1 pc. 15 amperes trip breaker J. For circuit (17) with 9 lighting outlets 1. 9 x 100= 900W 2. 3. Use 2 pcs. of 2.0 mm2 TW copper wire 4. Use 13 mm diameter conduit pipe 5. Use 1 pc. 15 amperes trip breaker K. For circuit (18) with 10 lighting outlets 1. 10 x 100= 1000 W 2. 3. Use 2 pcs. of 2.0 mm2 TW copper wire 4. Use 13 mm diameter conduit pipe 5. Use 1 pc. 15 amperes trip breaker SUB-FEEDER For circuits 1 to 21: 1. Total connected load For circuits 1, 4 & 5------------------------------------------------------------------------10800 W For circuits 2---------------------------------------------------------------------------------3240 W For circuits 3---------------------------------------------------------------------------------2520 W For circuits 6---------------------------------------------------------------------------------1500 W For circuits 13--------------------------------------------------------------------------------5100 W For circuits 14, 19 & 21---------------------------------------------------------------------3300 W
  • 14 For circuits 15, 16 & 20---------------------------------------------------------------------2400 W For circuits 17--------------------------------------------------------------------------------900 W For circuits 18--------------------------------------------------------------------------------1000 W TOTAL (excluding the Aircon Unit)-----------------------30.760 W From Table 4-4, optional calculation for Dwelling Unit, apply Demand Factor (df) For the first 10,000 Watts at 100% df--------------------------------------------------------10,000 Watts For the remaining load apply 40% df 30,760- 10,000= 20, 760 Watts at 40% (df)----------------------------------------- 8304 Watts For circuit 7 to 8: Aircon units at 100% Demand Factor (df) 2- units at 1865 Watts-------------------------------------------------------------------3730 Watts For circuit 9 to 12: Aircon units at 100% Demand Factor (df) 4- units at 2238 Watts-------------------------------------------------------------------8952 Watts TOTAL= 30,986 Watt 2. Total Line Current 3. Size of sub-feeder wire Referring to Table 4-2 Use 2 pcs. of 80 mm2 TW copper wire 4. Size of conduit pipe Referring to Table 2-9 Use 32 mm diameter conduit pipe 5. Size of the Overcurrent Device Referring to Table 4-1 Use 1pc. 175 amperes trip breaker SPECIAL PURPOSE OUTLET For circuit (22) with 1 unit of Motor Pump @ 3 HP Total Load 3 x 746= 2238 Watts Total expected Current Load “ Branch circuit conductor supplying a motor shall have an ampacity not less than 125% of full load current”
  • 15 9.73 x 125%= 12.16 A 1. Size of the branch circuit wire Referring to Table 2.5 Use 2pcs. of 8.0 mm2 TW copper wire 2. Size of conduit pipe Referring to Table 2-9 Use 30 mm diameter conduit pipe 3. Size of the Overcurrent Protection Device 9.73 x 2.5= 24.33 A Referring to Table 4-1 Use 1 pc. 70 amperes trip breaker MAIN FEEDER Total current load of 2 dwelling units at 134.72 A----------------------------------------------269.44 A Motor unit at 100% Demand Factor (df) 1-unit at 9.73 A-------------------------------------------------------------------------9.73 A TOTAL-----------------------------------------------------------------------------279.17 A At 125% of Full Load Current 279.17 x 1.25= 348.96 A
  • 16 1. Size of the branch circuit wire Referring to Table 2-5 Use 2 pcs. of No. 600 AWG MCM 2. Size of Conduit Pipe Referring to Table 2-9 Use 80 mm diameter conduit pipe 3. Size of the Overcurrent Protection Device Referring to Table 4-1 Use 1 pc. 450 amperes trip breaker