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1. MEGA PROJECT
TRIGONOMETRY 10

2. MEASUREMENTS

Prominence/horizontal measurement/base:
1,919 meters or 6,296 feet

Crater: 1,500 meters x 3,500 meters and
2,010 meters or 6,900 feet deep

Elevation: 2,170 meters or 7,119 feet above
sea level

3. Trigonometry Problem
Given that the Husgado is 0 ft above sea
level, Kalbaryo is 704 ft / 0.13 mi above sea
level and the straight line distance in
between them is 2581 ft / 0.49 mi, what is
the angle of elevation?

4. Representation

5. Values

Refer to angle A

b = 2581 ft

a =704 ft

A = ??

6. Solution
Given: 704 ft and 2581 ft
Find: A
Solution: tanA = 704/2581
tanA = 0.27276249515692
A = tan^-1(0.2727624951692)
A = 15.26

7. The angle of elevation is 15.26
degrees.