DBMS lab manual

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DBMS lab manual

  1. 1. LEIT116 Exp:1 Create and modifying the relations Date: 30/7/2013 Aim: To write a query on creation and modification of relations using library management system.. Queries: SQL> create table library(book_id number(7),isbn_no number(7),subject char(25),language char(25),name char(25),copies number(7),available number(7),cost number(7),author char(25)); Table created. SQL>desc library; Name Null? Type -------------------------------- --------------- ---------------------------BOOK_ID NUMBER(7) ISBN_NO NUMBER(7) SUBJECT CHAR(25) LANGUAGE CHAR(25) NAME CHAR(25) COPIES NUMBER(7) AVAILABLE COST AUTHOR NUMBER(7) NUMBER(7) CHAR(25) SQL> create table libissue as select book_id from library; Table created. SQL> ALTER table libissue add(student_id number(7),issue_datedate,due_datedate,return_datedate,fine number(7),issuers_id number(7)); Table altered SQL>desclibissue
  2. 2. LEIT116 Name Null? Type ----------------------------------------- -------- ---------------------------BOOK_ID NUMBER(7) STUDENT_ID NUMBER(7) ISSUE_DATE DATE DUE_DATE DATE RETURN_DATE DATE FINE NUMBER(7) ISSUERS_ID NUMBER(7) SQL> create table libauthor as select author from library; Table created. SQL> alter table libauthor add(author_id number(7),edition number(7),publisher_name char(25),publications char(25),yr_of_pub number(7),address varchar(50)); Table altered. SQL>desclibauthor; Name Null? Type ----------------------------------- -------- ---------------------------AUTHOR CHAR(25) AUTHOR_ID NUMBER(7) EDITION NUMBER(7) PUBLISHER_NAME CHAR(25) PUBLICATIONS CHAR(25) YR_OF_PUB NUMBER(7) ADDRESS VARCHAR2(50) SQL> create table student as select student_id from libissue; Table created.
  3. 3. LEIT116 SQL> alter table student add(student_name char(25),acc_no number(7),reg_no number(7),department char(25),total_limit number(7),books_returned number(7),books_pending number(7)); Table altered. SQL>desc student Name Null? Type ------------------------------------- -------- ------------------------ STUDENT_ID NUMBER(7) STUDENT_NAME CHAR(25) ACC_NO NUMBER(7) REG_NO NUMBER(7) DEPARTMENT CHAR(25) TOTAL_LIMIT NUMBER(7) BOOKS_RETURNED NUMBER(7) BOOKS_PENDING NUMBER(7) SQL> create table staffincharge as select issuers_id from libissue; Table created. SQL> alter table staffincharge add(staff_id number(7),name char(25),qualification char(25),designation char(25),date_of_joiningdate,contact_no number(7),address varchar(50)); Table altered. SQL>descstaffincharge; Name Null? Type ----------------------------------------- -------- ---------------------------ISSUERS_ID NUMBER(7) NAME CHAR(25) QUALIFICATION CHAR(25) DESIGNATION CHAR(25)
  4. 4. LEIT116 DATE_OF_JOINING DATE CONTACT_NO NUMBER(7) ADDRESS VARCHAR2(50) SQL> insert into library values(1,100,'computerscience','english','java',200,50,500,'samba'); 1 row created. SQL> select * from library; BOOK_ID ISBN_NO ---------------- ----------------- 1 SUBJECT -------------- 100 COPIES 200 ------------------- -------- English COST java AUTHOR ----------------- 50 NAME ------------------- computer science AVAILABLE ---------------- LANGUAGE --------------500 samba SQL> insert into student values(12,'ram',123,97,'it',100,5,15); 1 row created. SQL> select * from student; STUDENT_ID ---------------12 STUDENT_NAME ------------------------ram TOTAL_LIMIT ----------- ACC_NO REG_NO DEPARTMENT ---------- ---------- 123 BOOKS_RETURNED ----------------97 it BOOKS_PENDING -------------- ------------- 5 15 100 SQL> insert into libauthorvalues('samba',1,10,'samba','samba publish',2013,'anna nagarchennai'); 1 row created. SQL> select * from libauthor; AUTHOR ---------------- AUTHOR_ID ---------- EDITION ---------- PUBLISHER_NAME ----------------
  5. 5. LEIT116 samba 1 10 PUBLICATIONS YR_OF_PUB ---------------------- ----------------- samba publish 2013 samba ADDRESS ----------annanagarchennai SQL> insert into staffincharge values('2','sita','mba','librarian','222222','anna nagarmadurai'); 1 row created. SQL> select * from staffincharge; ISSUERS_ID ----------- NAME QUALIFICATION ------------ 2 -------------- sita DESIGNATION CONTACT_NO --------------------- mba librarian ---------222222 ADDRESS ----------annanagarmadurai SQL> insert into libissue values('1','123','100','2','200713'); 1 row created. SQL> select * from libissue; BOOK_ID STUDENT_ID FINE ---------- ---------- ---------1 123 ISSUERS_ID ---------- 100 Table truncated. SQL>desclibissue; Name Null? ---------2 SQL> truncate table libissue; Type ---------------------------------- -------- ---------------------------BOOK_ID NUMBER(7) STUDENT_ID NUMBER(7) ISSUE_DATE 200713
  6. 6. LEIT116 FINE NUMBER(7) ISSUERS_ID NUMBER(7) ISSUE_DATE NUMBER(7) SQL> select *from libissue; no rows selected SQL> delete from libissue where book_id=1; 0 rows deleted. SQL> alter table libissue drop column issue_date; Table altered. SQL> alter table libissue drop column due_date; Table altered. SQL> alter table libissue drop column return_date; Table altered. SQL>desclibissue Name Null? Type ----------------------------------------- -------- ---------------------------BOOK_ID NUMBER(7) STUDENT_ID NUMBER(7) FINE NUMBER ISSUERS_ID NUMBER(7) SQL> alter table libissue add issue_datenumber(7); Table altered.
  7. 7. LEIT116 Result: Thus the creation and modification of relation are done and successfully output was verified.
  8. 8. LEIT116 Exp:2 Integrity Constraint Aim: To create and implement the usage of queries using constraint. Queries: Primary key : Column level: SQL> create table book2(bid number(10),bnamevarchar(10),authnamevarchar(20),co nstraint book2_bid_pk primary key(bid)); Table created. SQL>desc book1; Name ----------------------- Null? -------- BOOKNAME PRICE Type ---------------------------CHAR(20) NOT NULL NUMBER(18) Table level: SQL> create table book2(bid number(10),bnamevarchar(10),authnamevarchar(20),co nstraint book2_bid_pk primary key(bid)); Table created. SQL>desc book2; Name -----------------BID Null? Type -------- -------- NOT NULL NUMBER(10) BNAME VARCHAR2(10) AUTHNAME VARCHAR2(20) BID BNAME PID ---------- -------------------- ---------435 maths 123 social 999 998
  9. 9. LEIT116 Unique: Column level: SQL> create table bbbc(bid number(10) constraint bbbc_bid_ukunique,bnamevarchar(20),pid number(10)); Table created. SQL> insert into bbbcvalues(435,'maths',999); 1 row created. SQL> insert into bbbcvalues(123,'social',998); 1 row created. SQL> insert into bbbcvalues(123,'science',997); insert into bbbc values(123,'science',997) *ERROR at line 1: ORA-00001: unique constraint (SCOTT.BBBC_BID_UK) violated SQL> select * from bbbc; BID BNAME PID ---------- -------------------- ---------435 maths 123 social 999 998 SQL>alter table student2 add rollnonumber(6) constraint student2_rollno_ck check(rollno>=55000); Table altered. SQL>insert into student2 values('12it70','Priya','Linux',52345); ORA-02290: check constraint (SYSTEM.STUDENT2_ROLLNO_CK) violated Table level: SQL>create table book7(bid number(10),bnamevarchar(20),authnamevarchar(2),price number(3),constraint book7_price_cc check(price>0)); Table created. SQL>insert into book7 values(192,'dsd','morrismano',0); ORA-02290: check constraint (SYSTEM.BOOK7_PRICE_CC) violated Default: SQL>create table student3(rollno number(5),regnovarchar(7),department varchar(6) default 'IT');
  10. 10. LEIT116 Table created. SQL>insert into student3(rollno,regno) values(456,'12it71'); 1 row(s) inserted. SQL>select * from student3; ROLLNO REGNO DEPARTMENT -----------------------------------456 12it71 IT Foreign key Table level: SQL>create table publisher(pid number(10),pnamevarchar(20),phno number(10),constraint publisher_pid_pk primary key(pid)); Table created SQL>insert into book6 values(1232,'Linux',435,768,31245); ORA-02291: integrity constraint (SYSTEM.BOOK6_PID_FK) violated - parent key not found SQL>insert into publisher values(111,'grewal',991123459) 1 row(s) inserted. SQL>select * from publisher; PID PNAME PHNO ------ -------------------111 Grewal 991123459 SQL>insert into book6 values(1241,'Linux',610,111,6122); 1 row(s) inserted. Column level: SQL>create table book01(bid number(10),bnamevarchar(20),authnamevarchar(20),pid number(10),constraint book02_pid_fk foreign key(pid) references publisher01(pid) ); Table created. SQL>insert into book01 values(11,'Maths','Grewall',190); 1 row(s) inserted. SQL>insert into book01 values(124,'CO','Zvonko',191); 1 row(s) inserted. Not null: SQL>alter table book6 add isbnnumber(10) constraint book6_isbn_nn NOT NULL; Table altered. SQL>insert into book6(bid,bname,price,pid) values(465,'Java2',99.50,65); ORA-01400: cannot insert NULL into ("SYSTEM"."BOOK6"."ISBN")
  11. 11. LEIT116 Cascade: SQL>create table book02(bid number(10),bnamevarchar(20),authnamevarchar(20),pid number(10),constraint book02_pid_fk foreign key(pid) references publisher02(pid) on delete cascade); Table created. SQL>insert into book02 values(453,'Java','IraPohl',134); 1 row(s) inserted. SQL>insert into book02 values(456,'dsd','Morrismano',135); 1 row(s) inserted. Set : SQL>create table book03(bid number(10),bnamevarchar(20),authnamevarchar(20),pid number(10),constraint book03_pid_fk foreign key(pid) references publisher03(pid) on delete set null); Table created. SQL>insert into book03 values(862,'Surveying','Punmia',637); 1 row(s) inserted. SQL>insert into book03 values(852,'CO','Zvonko',737); 1 row(s) inserted. Result: Thus the constraint was successfully completed and output was verified
  12. 12. LEIT116 Exp:3 Simple SQL Queries Aim: To execute the simple sql queries. Queries: Query 1 To display the DOB and address of the employee ‘John Smith’. SQL> select bdate,address from employee where fname='John' and lname='Smith'; BDATE ADDRESS --------- ------------------- 18-AUG-90 Pudur, Madurai Query 2 To select the name and address of the employee who works in ‘Research department’ SQL> select fname||' '||lname as Name,address from employee where ssn=(select mgrssn from department where dname='Research'); NAME ADDRESS -------------------- -------------------- Raj Kumar Kodambakkam, Chennai Query 3 To display the Project No, Department No. And Department manager’s last name,DOB and address for the projects located in Chennai. SQL> select p.pnumber,p.dnumber,e.lname,e.bdate as DOB,e.address from employee e,projectp,department d where d.dnum=p.dnumber and p.plocation='Chennai' and d.mgrssn=e.ssn;
  13. 13. LEIT116 PNUMBER DNUMBER ---------- ------------ 21 6 LNAME DOB -------------- ------------ Smith ADDRESS -------------------- 18-AUG-90 Pudur Madurai Query 4 To retrieve the first and last name of all employees along with their Manager’s no. SQL> select e.fname,e.lname,e.ssn,d.mgrssn from employee e,department d where e.ssn!=d.mgrssn and e.dno=d.dnum; FNAME LNAME SSN ---------- ---------------- MGRSSN ---------- ---------- Raj Kumar 5 10 John Smith 2 4 Ram Kumar 1 9 Query 5 To select all employee’s name and SSN SQL> select fname||’ ‘||lname as Name,ssn from employee; NAME SSN ---------- -------- Ram Kumar 1 John Smith 2 Raj Kumar 5 Query 6: To select all employee’s name, SSN and the department’s name.
  14. 14. LEIT116 SQL> select d.dname,d.dnum,e.fname||’’||e.lname as name,e.ssn from employee e,department d where d.mgrssn=e.ssn; DNAME ---------- DNUM ---------- NAME SSN ---------- ---------- Research 3 Raj Kumar 5 Technical 6 John Smith 2 Accounts 5 Ram Kumar 1 Query 7: Retrieving the salary of all employees SQL> select fname||' '||lname as Name_Of_Employee,salary from employee; NAME_OF_EMPLOYEE -----------------------------Ram Kumar SALARY ---------14000 John Smith 10500 Raj Kumar 10500 Query 8 To retrieve the distinct salary values. SQL> select distinct salary from employee; SALARY ---------14000 10500
  15. 15. LEIT116 Query 9 To retrieve the name of the employee who is from Chennai. SQL> select fname||' '||lname as name from employee where address like '%Theni'; NAME ------------------------------Ram Kumar Query 10 Employees who were born in 1990. SQL> select fname||’ ‘||lname as name from employee where bdate like '%90'; NAME ---------------------------John Smith Query 11 To show the resulting salary and the name of the employee who is working on the project Web Design and is given 10% rise in salary. SQL> select p.pname,e.fname,w.essn,e.salary+0.1*e.salary as salary from employee e,projectp,workson w where p.pname='Web Design' and w.pno=p.pnumber and w.essn=e.ssn; PNAME FNAME --------------- ---------- ---------- Web Design John 2 Query 12 ESSN SALARY ---------11550
  16. 16. LEIT116 To retrieve all employees in the department 3 whose salary is in between 13K and 15K. SQL> select fname,salary from employee where dno=3 and salary between 13000 and 15000; FNAME SALARY ---------- ------------ Ram 14500 Query 13 To retrieve the list of employees and the project they are working on ordered by the department number. SQL> select distinct e.fname,p.pname,p.pnumber,e.dno from employee e,project p where e.dno=p.dnumber order by e.dno; FNAME PNAME ---------- --------------- Raj PNUMBER -------------- Cryptography -------- 42 Ram yyy 41 Ram zzz Web Design 3 35 John DNO 5 5 21 6 Query 14 To retrieve the name of employee whose project is being controlled by department number 6 SQL> select e.fname||' '||e.lname as name,p.pnumber,e.dno from project p,employe e e,workson w where w.essn=e.ssn and w.pno=p.pnumber and p.dnumber=6; NAME --------------------- PNUMBER -------------- DNO ----------
  17. 17. LEIT116 John Smith 21 6 Result: Thus the simple sqlqueries was successfully executed and output was verified.
  18. 18. LEIT116 Exp:4 Basic simple SQL queries 20/8/2013 Aim: To write a basic simple sql queries in library management system Queries: 1. Find the id and title of all courses which do not require any prerequisities. selectcourse_id,title from course where course.course_id not in (select course_id from prereq); COURSE_ID BIO-301 BIO-399 CS-101 FIN-201 HIS-351 MU-199 PHY-101 TITLE Genetics Computational Biology Intro.to Computer Science Investment Banking World History Music Video Production Physical Principles 2. Write SQL update query to increase 10% salary to all instructors. SALARY 65000 90000 40000 195000 60000 87000 175000 62000 80000 72000 update instructor set salary=salary+(0.1*salary); 14 row(s) updated. Select salary from instructor; SALARY
  19. 19. LEIT116 71500 99000 44000 104500 66000 95700 82500 68200 88000 79200 3.Write SQL update query to increase the total credits of all students who have taken the course title ‘Genetics’ by the no. Of credits associated with the course. select * from student; ID NAME DEPT_NAME 00128 Zhang Comp. Sci. 12345 Shankar Comp. Sci. 19991 Brandt History 23121 Chavez Finance 44553 Peltier Physics 45678 Levy Physics 54321 Williams Comp. Sci. 55739 Sanchez Music 70557 Snow Physics 76543 Brown Comp. Sci. 76653 Aoi Elec. Eng. 98765 Bourikas Elec. Eng. 98988 Tanaka Biology TOT_CRED 102 32 80 110 56 46 54 38 0 58 60 98 120 update student120 set tot_cred=tot_cred+(select credits from course where course.title='Genetics') where id in(select student120.id from student120,course where student120.dept_name=course.dept_name and course.title='Genetics'); 1 row(s) updated. ID NAME 00128 Zhang 12345 Shankar 19991 Brandt History DEPT_NAME Comp. Sci. Comp. Sci. 80 TOT_CRED 102 32
  20. 20. LEIT116 23121 Chavez Finance 44553 Peltier Physics 45678 Levy Physics 54321 Williams Comp. Sci. 55739 Sanchez Music 70557 Snow Physics 76543 Brown Comp. Sci. 76653 Aoi Elec. Eng. 98765 Bourikas Elec. Eng. 98988 Tanaka Biology 110 56 46 54 38 0 58 60 98 122 4.Find the names of students who have not taken any biology department courses. select name from student120 where dept_name!='Biology'; NAME Zhang Shankar Brandt Chavez Peltier Levy Williams Sanchez Snow Brown 5. Write SQL update query to list all the instructors who are advisor of atleast two students,increase the salary by 50000. Srinivasan Wu 71500 99000 Mozart 44000 Einstein 104500 Elsaid 66000 Gold 95700 Katz 82500 Califeri 68200
  21. 21. LEIT116 Singh 88000 Crick 79200 Brandt 101200 Sara 55000 Sandy 44000 Kim 193000 select count(advisor.s_id),instructor.name from advisor,instructor,student where student.id=advisor.s_id and instructor.id=advisor.i_id group by instructor.name; COUNT(ADVISOR.S_ID) NAME 2 Einstein 1 Crick 1 Srinivasan 2 Kim 1 Singh 2 Katz update instructor set salary=salary+50000 where name in (select name from instructor,advisor where instructor.id=advisor.i_id group by instructor.name having count(s_id) > 1); 3 row(s) updated. NAME SALARY Srinivasan 71500 Wu 99000 Mozart 44000 Einstein 214500 El Said 66000 Gold 95700 Katz 192500 Califieri 68200 Singh 88000 Crick 79200 Brandt 101200
  22. 22. LEIT116 Kim 198000 Sara 55000 Sandy 44000 6.Write SQL update query to set the credits to 2 for all courses which have less than 5 students taking them COURSE_ID TITLE DEPT_NAME CREDITS BIO-301 BIO-399 CS-101 Genetics Biology ComputationalBiology Intro.to Computer Science 4 Biology 3 Comp. Sci. 4 CS-190 Game Design Comp. Sci. 4 CS-315 Robotics Comp. Sci. 3 CS-319 Image Processing Comp. Sci. CS-347 Database System Concepts Comp. Sci. EE-181 Intro.to Digital Systems 3 FIN-201 Investment Banking HIS-351 World History MU-199 Music Video Production PHY-101 Physical Principles 3 Elec. Eng. 3 Finance 3 History 3 Music 3 Physics 4 update course set credits=2 where course_id in (select course.course_id from course,takes where course.course_id=takes.course_id group by course.course_id having count(takes.id)<5); COURSE_ID TITLE DEPT_NAME CREDITS BIO-301 Genetics Biology BIO-399 Computational Biology Biology CS-101 Intro.to Computer Science Comp. Sci. CS-190 CS-315 Game Design Robotics Comp. Sci. Comp. Sci. 2 3 4 2 2
  23. 23. LEIT116 CS-319 Image Processing CS-347 Database System Concepts EE-181 Intro.to Digital Systems FIN-201 Investment Banking HIS-351 World History MU-199 Music Video Production Comp. Sci. Comp. Sci. 2 2 Elec. Eng. Finance 2 2 History Music 2 2 Result; Thus the basic simple sql queries are successfully executed and the output was verified.
  24. 24. LEIT116 EXP:5 JOINS 27/8/13 Aim: To write a simple sql queries on joins using our application. Queries: SQL> create table stu(id number(7),name varchar(20),dept_namevarchar(20),tot_credit number(3)); Table created. SQL>descstu Name Null? Type ----------------------------------------- -------- ---------------------------ID NUMBER(7) NAME VARCHAR2(20) DEPT_NAME VARCHAR2(20) TOT_CREDIT NUMBER(3) SQL> insert into stuvalues(116,'maha','it',60); 1 row created. SQL> insert into stuvalues(97,'subha','it',90); 1 row created. SQL> insert into stuvalues(116,'sne','it',50); 1 row created. SQL> create table tak(id number(7),cource_id number(7),sec_id number(7),semester number(3),year number(7),grade char(3)); Table created. SQL>desctak Name Null? Type ----------------------------------------- -------- ---------------
  25. 25. LEIT116 ID NUMBER(7) COURCE_ID NUMBER(7) SEC_ID NUMBER(7) SEMESTER NUMBER(3) YEAR NUMBER(7) GRADE CHAR(3) SQL> insert into takvalues(45,'32',5,3,2013,'A'); 1 row created. SQL> insert into takvalues(52,31,7,3,2012,'C'); 1 row created. SQL> insert into tak values(47,35,8,4,2010,'A'); 1 row created. SQL> insert into tak(id,sec_id,semester,year,grade) values(78,9,4,2009,'C'); 1 row created. SQL> insert into takvalues(116,45,6,3,2007,'B' ); 1 row created. SQL> create table ins(id number(7),name varchar(20),dept_namevarchar(20),salary number(10)); Table created. SQL>descins; Name Null? Type ----------------------------------------- -------- ---------------------------ID NAME DEPT_NAME SALARY NUMBER(7) VARCHAR2(20) VARCHAR2(20) NUMBER(10) SQL> insert into ins values(78,'susila','cse',40000);
  26. 26. LEIT116 1 row created. SQL> insert into ins values(95,'chells','maths',45000); 1 row created. SQL> insert into ins values(64,'sankar','it',48000); 1 row created. SQL> create table teach(id number(7),cource_id number(7),sec_id number(7),semester number(3),year number(7)); Table created. SQL>desc teach Name Null? Type ----------------------------------------- -------- ------------------ID NUMBER(7) COURCE_ID NUMBER(7) SEC_ID NUMBER(7) SEMESTER NUMBER(3) YEAR NUMBER(7) SQL> insert into teach values(118,33,7,3,2009); 1 row created. SQL> insert into teach values(114,34,8,3,2009); 1 row created. SQL> insert into teach values(113,36,9,3,2010); 1 row created. Joins queries: INNER JOINS: SQL> select stu.name,tak.id from stu inner join tak on stu.id=tak.id; NAME ID -------------------- ----------
  27. 27. LEIT116 maha 116 sne 116 OUTER JOINS: Left outer join: SQL> select * from stu left outer join tak on stu.id=tak.id; ID NAME DEPT_NAME TOT_CREDIT ID ---------- -------------------- -------------------- ---------- ---------COURCE_ID SEC_ID SEMESTER YEAR GRA ---------- ---------- ---------- ---------- --97 subha it 90 116 sne it 50 Rigtht outer join: SQL> select * from stu right outer join tak on stu.id=tak.id; ID NAME DEPT_NAME TOT_CREDIT ---------- -------------------- -------------------- ---------- ---------COURCE_ID SEC_ID SEMESTER YEAR GRA ---------- ---------- ---------- ---------- --78 9 4 2009 C 52 31 7 3 2012 C ID
  28. 28. LEIT116 45 32 5 3 2013 A ID NAME DEPT_NAME TOT_CREDIT ID ---------- -------------------- -------------------- ---------- ---------COURCE_ID SEC_ID SEMESTER YEAR GRA ---------- ---------- ---------- ---------- --47 35 8 4 2010 A 116 maha it 60 Full outer join: SQL> select * from stu full outer join tak on stu.id=tak.id; ID NAME DEPT_NAME TOT_CREDIT ---------- -------------------- -------------------- ---------- ---------COURCE_ID SEC_ID SEMESTER YEAR GRA ---------- ---------- ---------- ---------- --97 subha it 90 116 sne it 50 116 maha it 60 ID
  29. 29. LEIT116 ID NAME DEPT_NAME TOT_CREDIT ID ---------- -------------------- -------------------- ---------- ---------COURCE_ID SEC_ID SEMESTER YEAR GRA ---------- ---------- ---------- ---------- --78 9 4 2009 C 52 31 7 3 2012 C 45 32 5 3 ID NAME 2013 A DEPT_NAME TOT_CREDIT ---------- -------------------- -------------------- ---------- ---------COURCE_ID SEC_ID SEMESTER YEAR GRA ---------- ---------- ---------- ---------- --47 35 8 7 rows selected. Interact: 4 2010 A ID
  30. 30. LEIT116 SQL>select name from tak interact select name from stu; NAME ----------Maha Subha Sne Union: SQL> select namedept_name from stu union select semester from tak where tot_cred=”90”; DEPT_NAME SEMESTER Subha 3
  31. 31. LEIT116 Result; Thus the joins queries are successfully executed by using the library management application application.
  32. 32. LEIT116 EXP:6 creation and updation of views 10/9/13 Aim: To write a simple queries by using views Queries: Create view: SQL> create view lib_view as select subject,author from library; View created. Display: SQL> select * from lib_view; SUBJECT AUTHOR ------------------------- ------------------------computer science balagursamy SQL>desclib_view; Name Null? Type ----------------------------------------- -------- -------------SUBJECT CHAR(25) AUTHOR CHAR(25) SQL> select author from lib_view where subject='computer science'; AUTHOR ------------------------Balagursamy SQL> create view lib_view1(name,dob,cellno) as select docname,docid,cellno from docdet where docid=12 ; View created. SQL>desc lib_view1; Name Null? Type ----------------------------------------- -------- ---------------------------
  33. 33. LEIT116 NAME VARCHAR2(5) DOB NUMBER(10) CELLNO NUMBER(10) Check option: SQL> create view lib_view3(name,address,wardno) as select docname,docid,cellno from docdet where docid=112 with check option; View created. Update: SQL>update lib_view3 libno=116 where name=’main’; O Rows selected. SQL> alter view lib_view3 compile; View altered. Read only option: SQL> create view lib_view4(name,dob,cellno) as select docname,docid,cellno from docdet where docid=1WITH READ ONLY; View created. SQL>desc lib_view4; Name Null? Type ----------------------------------------- -------- ----------------NAME DOB CELLNO Drop view: SQL> drop view lib_view; View dropped. SQL> select * from lib_view; no rows selected. VARCHAR2(5) NUMBER(10) NUMBER(10)
  34. 34. LEIT116 Result: Thus the creation and updation of view was successfully executed and output was verified.
  35. 35. LEIT116 Expno:7 EXERCISES IN PL/SQL 17/09/2013 Aim: To implement an query on pl/sql statement. Pl/sql blocks: Bind variable: SQL> set serveroutput on SQL> VARIABLE bindvar NUMBER SQL> declare 2 v_num number(2); 3 BEGIN 4 v_num := 5; 5 :bindvar := v_num*2; 6 END; 7 / PL/SQL procedure successfully completed. SQL> PRINT bindvar; G_DOUBLE ---------10 SQL> VARIABLE g_double NUMBER SQL> declare 2 v_num number(2); 3 begin 4 v_num := &p_num; 5 :g_double := v_num*2;
  36. 36. LEIT116 6 end; 7 / Enter value for p_num: 20 old 4: v_num := &p_num; new 4: v_num := 20; PL/SQL procedure successfully completed. SQL> print g_double; G_DOUBLE ---------40 SQL> variable num number SQL> set serveroutput on SQL> declare 2 double number; 3 begin 4 :num := 5; 5 double := :num*2; 6 dbms_output.put_line(('double of'||to_char(:num) || 'is' || to_char(double) )); 7 end; 8 / double of5is10 PL/SQL procedure successfully completed. Anchor declaration SQL> variable b number
  37. 37. LEIT116 SQL> declare 2 v_num number(2); 3 v_num2 v_num%type; 4 begin 5 v_num:=4; 6 v_num2:=8; 7 :b:=v_num*v_num2; 8 end; 9 / PL/SQL procedure successfully completed. SQL> print b B ---------32 Control statements Decode function SQL> select fname,lname, 2 decode(101,1000, 3 102,2000, 4 103,3000)from emp; FNAME LNAME DECODE(101,1000,102,2000,103,3000) ---------- ---------- ---------------------------------thrigaya 3000 nathpriy 3000 kumararun 3000
  38. 38. LEIT116 if..then..elseif..endif SQL> declare 2 m number:=&mark; 3 grade char; 4 begin 5 if m>=190 and m<=200then 6 grade:='a'; 7 elseif m>=160 and m<=190 then 8 grade:='b'; 9 elseif m>=120 and n<=160 then 10 grade:='u'; 11 end if; 12 dbms_output.put_line(grade); 13 end; 14 / Enter value for mark: 199 old 2: m number:=&mark; new 2: m number:=199; a PL/SQL procedure successfully completed. Searched case: SQL> declare 2 v_num number:=&any_num; 3 v_res number; 4 begin 5 v_res:=v_num
  39. 39. LEIT116 6 casev_res 7 when 0 then dbms_output.put_line(v_num||'is even'); 8 elsedbms_output.put_line(v_num||'is odd'); 9 end case; 10 end; 11./ Enter value for any_num: 3 old 2: v_num number:=&any_num; new 2: v_num number:=3; 3is odd PL/SQL procedure successfully completed. Case structure SQL> declare 2 v_num number:=&any_num; 3 v_res number; 4 begin 5 v_res:=v_num 6 casev_res 7 when 0 then dbms_output.put_line(v_num||'is even'); 8 elsedbms_output.put_line(v_num||'is odd'); 9 end case; 10 end; 11 / Enter value for any_num: 4 old 2: v_num number:=&any_num; new 2: v_num number:=4;
  40. 40. LEIT116 4is even PL/SQL procedure successfully completed. Nested if SQL> set serveroutput on SQL> declare 2 v_name char:='&name'; 3 v_id number(2):='&id'; 4 v_age number(2):='&age'; 5 begin 6 if(v_name='gayu' and v_id=11)then 7 v_age:=23; 8 end if; 9 if(v_name='anu' and v_id=12)then 10 v_age:=24; 11 end if; 12 if(v_name='priya' and v_id=13)then 13 v_age:=25; 14 end if; 15 if(v_name='kris' and v_id=14)then 16 v_age:=26; 17 end if; 18 dbms_output.put_line(v_name); 19 dbms_output.put_line(to_char(v_id)); 20 dbms_output.put_line(to_char(v_age)); 21 en 2 /
  41. 41. LEIT116 Enter value for name: anu old 2: v_name char:='&name'; new 2: v_name char:='anu'; Enter value for id: 12 old 3: v_id number(2):='&id'; new 3: v_id number(2):='12'; Enter value for age: 24 old 4: v_age number(2):='&age'; new 4: v_age number(2):='24'; anu 12 24 PL/SQL procedure successfully completed. If..then.end..if SQL> declare 2 v_num number(5):=112; 3 v_id number(5):=115; 4 employee number(5); 5 begin 6 ifv_num>113 then 7. employee:=114; 8. employee:=112; 9. end if; 10. end; 11./ PL/SQL procedure successfully completed.
  42. 42. LEIT116 If..then..else..endif SQL> declare 2 v_num number(5):=112; 3 v_id number(5):=115; 4 employee number(5); 5 begin 6 ifv_num>113 then 7 employee:=114; 8 else 9 employee:=112; 10 end if; 11 end; 12 / PL/SQL procedure successfully completed. If..then..elseif..endif SQL> declare 2 m number(3):=&mark; 3 grade char; 4 begin 5 if m>=190 and m<=200then 6 grade:='good'; 7 elseif m>=170 and m<=190; 8 grade:='excellent'; 9 elseif m>=140 and m<=170; 10 grade:='fair';
  43. 43. LEIT116 11 endif; 12 dbms_output.put_line(grade); 13 end; 14 / Enter value for mark: 170 old 2: m number(3):=&mark; new 2: m number(3):=170; Looping statements for loop SQL> declare 2 v_countnumber(2); 3 v_sumnumber(2):=0; 4 v_avgnumber(3,1); 5 begin 6 for v_count in 1..10 loop 7 v_sum:=v_sum+v_count; 8 end loop; 9 v_avg:=v_sum/10; 10 dbms_output.put_line(to_char(v_avg)); 11 end; 12 / 5.5 PL/SQL procedure successfully completed. While loop: SQL> set serveroutput on
  44. 44. LEIT116 SQL> declare 2 v_count number(2); 3 v_sum number(2):=0; 4 v_avg number(3,1); 5 begin 6 v_count:=1; 7 whilev_count<=10 loop 8 v_sum:=v_sum+v_count; 9 v_count:=v_count+1; 10 end loop; 11 v_sum:=v_sum+v_count; 12 v_avg:=v_sum/(v_count-1); 13 dbms_output.put_line(to_char(v_avg)); 14 end; 15 / 6.6 PL/SQL procedure successfully completed. Basic loop: SQL>setserveroutput on SQL> declare 2 numnumber(5); 3 id number(5); 4 begin 5 loop 6 num:=num+1; 7 id:=id+1;
  45. 45. LEIT116 8 exit when num=2; 9 end loop; 10 end; 11 / 10 2 PL/SQL procedure successfully completed. Update: SQL> set serveroutput on SQL> declare 2 cnumber number:=&value; 3 begin 4 update employee 5 set salary=salary*(1+value) 6 whereemployeeif=&emp_id; 7 commit; 8 end; 9 / Enter value for value: 3 old 2: cnumber number:=&value; new 2: cnumber number:=3; Enter value for emp_id: 3 old 6: where employeeif=&emp_id; new 6: where employeeif=3; PL/SQL procedure successfully completed. Insert:
  46. 46. LEIT116 SQL> declare 2 v_nameemployee.name%type; 3 begin 4 insert into employee(name,id,salary) values('gayu',112,1000); 5 commit; 6 end; 7 / PL/SQL procedure successfully completed. Delete: SQL> declare 2 v_nameemployee.name%type; 3 begin 4 select id from employee where name='gayu'; 5 delete from employee 6 where name=v_name; 7 commit; 8 end; 9 / PL/SQL procedure successfully completed. Comment line: Singleline: SQL> set serveroutput on SQL> variable a number SQL> declare 2 v_num number(10); 3 v_num2 v_num%type;
  47. 47. LEIT116 4 begin 5 v_num:=5; 6 v_num2:=10; 7 :a:=v_num*v_num2; 8 end; 9 --PROGRAM ENDED 10 / PL/SQL procedure successfully completed. Multiline: SQL> variable b number SQL> declare 2 v_num number(5); 3 v_num2 v_num%type; 4 begin 5 v_num:=5; 6 v_num2:=10; 7 :a:=v_num*v_num2; 8 end; 9 /* 10 */ 11 / PL/SQL procedure successfully completed.
  48. 48. LEIT116 Result: Thus the pl/sql program was executed successfully.
  49. 49. LEIT116 EXP:08 CURSOR MANAGEMENT 01/10/13 Aim: To implement the cursor management on library management system. Queries: Explicit cursor attributes: SQL> set serveroutput on; SQL> declare 2 -- declare the variables 3 c_namestudent.name%type; 4 c_tot_credstudent.tot_cred%type; 5 --declare the cursor 6 cursor student_cur is 7 select name,tot_cred 8 from student 9 where id=76543; 10 begin 11 if not student_cur%isopen then 12 --open the cursor 13 open student_cur; 14 end if; 15 loop 16 --fetch the rows from the cursor 17 fetch student_cur 18 into c_name,c_tot_cred; 19 exit when not student_cur%found;
  50. 50. LEIT116 20 dbms_output.put_line(c_name||' '||c_tot_cred); 21 end loop; 22 dbms_output.put_line(student_cur%rowcount||'student(s) found'); 23 --close the cursor 24 closestudent_cur; 25 end; 26 / Brown 58 1student(s) found PL/SQL procedure successfully completed. Cursor for loop: SQL> declare 2 cursorstudent_cur is 3 selectname,tot_cred 4 from 5 student; 6 begin 7 forstu_rec in student_cur loop 8 ifstu_rec.tot_cred>90 then 9 dbms_output.put_line(stu_rec.name||' '); 10 dbms_output.put_line(stu_rec.tot_cred||' '); 11 end if; 12 end loop; 13 end;
  51. 51. LEIT116 14 / Zhang 102 Chavez 110 Bourikas 98 Tanaka 120 PL/SQL procedure successfully completed. Create a cursor for update: SQL> declare 2 cursor student_cur is 3 select * from student 4 for update of tot_cred; 5 begin 6 for stu_rec in student_cur 7 loop 8 update student 9 set tot_cred=(stu_rec.tot_cred/10) 10 --Where current of clause 11 where current of student_cur; 12 end loop; 13 end;
  52. 52. LEIT116 14 / PL/SQL procedure successfully completed. Cursor for loop using a subquery: begin forlib_rec in (selectname,reg_no,dept,no_of_book,fine from library wheredept='it')loop dbms_output.put_line (lib_rec.name||''||lib_rec.reg_no||'$'||to_char(lib_rec.no_of _book+NVL(lib_rec.fine,0))); end loop; end; / PL/SQL procedure successfully completed. Cursor with parameter SQL> declare 2 cursorc_lib is select * from library; 3 begin 4 forlib_no in c_lib loop 5 dbms_output.put_line('lib_no.id:'||lib_no.id); 6 end loop; 7 commit; 8 end; 9 /
  53. 53. LEIT116 lib_no.id:112 lib_no.id:114 lib_no.id:115 Cursor with REF: SQL> declare 2 typebook_type is ref cursor return book%rowtype; 3 v_bookbook_type; 4 n_bookbook%rowtype; 5 begin 6 openv_book for select * from library where id=112; 7 fetchv_book into n_book; 8 dbms_output.put_line(v_book.number||' is '||n_book.name); 9 closev_book; 10 end; 11 / java 112 Exception: TOO_MANY_ROWS: SQL> set serveroutput on SQL> declare 2 v_namelibrary.id%type; 3 begin 4 dbms_output.put_line('first'||v_name); 5 select id into v_name from library;
  54. 54. LEIT116 6 dbms_output.put_line('second'||v_name); 7 exception 8 whentoo_many_rows then 9 dbms_output.put_line('third'||v_name); 10 dbms_output.put_line('exception'||v_name); 11 end; 12 / first third112 exception112 PL/SQL procedure successfully completed. User defined exception: SQL> declare 2 v_name exception; 3 v_no exception; 4 v_namelibrary.name%type; 5 begin 6 select name into v_name from libaray 7 wherelibraryid=&v_id; 8 ifv_name<0 then 9 raisev_name; 10 elseifv_name is null then 11 raisev_id; 12 else 13 dbms_output.put_line(to_char(v_name); 14 endif;
  55. 55. LEIT116 15 exception 16 whenno_data_found 17 dbms_output.put_line('no_data_found'); 18 end; 19 / Enter value for v_id: 2 old 7: where libraryeid=&v_id; new 7: where libraryid=2 Result: Thus the cursor was successfully executed and output was verified.
  56. 56. LEIT116 EXP:9 PROCEDURE,FUNCTION AND PACKAGE DATE:15/10/13 PL/SQL BLOCKS: Procedures: SQL> create or replace procedure search_lib 2 (i_libid in number, 3 o_last out varchar, 4 o_first out varchar) 5 is 6 begin 7 selectid,name 8 intoo_last,o_first 9 from wow 10 where wow.id=i_empid; 11 exception 12 when others then 13 dbms_output.put_line('name is'||o_last); 14 endsearch_emp; 15 / Procedure created. SQL> set serveroutput on; SQL> declare 2 v_lastwow.name%type; 3 v_firstwow.category%type; 4 v_idwow.id%type:=&mp_id; 5 begin 6 search_emp(v_id,v_last,v_first);
  57. 57. LEIT116 7 ifv_last is not null then 8 dbms_output.put_line('library'||v_id); 9 dbms_output.put_line('name'||v_last||','||v_first); 10 end if; 11 end; 12 / Enter value for mp_id: 12 old 4: v_idwow.id%type:=&mp_id; new 4: v_idwow.id%type:=12; library 12 name12,maha PL/SQL procedure successfully completed. Function: SQL> create or replace function val_get 2 (i_id in number) 3 returnvarchar 4 is 5 v_namevarchar(10); 6 begin 7 select name into v_name 8 from wow 9 where id=i_id; 10 returnv_name; 11 endval_get; 12 / Function created. SQL> declare
  58. 58. LEIT116 2 v_idwow.id%type:=&id; 3 v_namewow.name%type; 4 begin 5 select id 6 intov_id from wow 7 where wow.id=v_id; 8 v_name:=val_get(v_id); 9 dbms_output.put_line('the name is'||v_name); 10 exception 11 when others then 12 dbms_output.put_line(v_id||'not found'); 13 end; 14 / Enter value for id: 12 old 2: v_idwow.id%type:=&id; new 2: v_idwow.id%type:=12; the name is maha PL/SQL procedure successfully completed. SQL> create or replace procedure displayquantity is 2 temp_quantitynumber(10); 3 begin 4 select quantity into temp_quantity from book 5 where bookno=12; 6 if temp_quantity>100 then 7 dbms_output.put_line('success'); 8 else 9 dbms_output.put_line('not');
  59. 59. LEIT116 10 end if; 11 exception 12 when NO_DATA_FOUND then 13 dbms_output.put_line('medicene not found'); 14 end displayquantity; 15 / Procedure created. Execute: SQL> execute displayquantity PL/SQL procedure successfully completed. SQL> set serveroutput on; SQL> execute displayquantity success PL/SQL procedure successfully completed. SQL>drop procedure displayquantity; Procedure dropped. SQL> create or replace function retrievequantity 2 return number 3 is 4 v_quantity number(10); 5 begin 6 select quantity into v_quantity 7 from book 8 wherebookno=12; 9 returnv_quantity; 10 endretrievequantity; 11 /
  60. 60. LEIT116 Function created. SQL>varv_qty number; SQL>EXEC :v_qty := retrievequantity; PL/SQL procedure successfully completed. SQL> print v_qty; V_QTY ---------150 Drop a function: SQL>drop function retrievequantity; Function dropped. Package: SQL> create or replace PACKAGE book AS 2 PROCEDUREfindbook( 3 medno IN book.bkno%type, 4 description IN book.description%type, 5 cost IN book.cost%type); 6 v_bknoNOTFOUND EXCEPTION; 7 FUNCTIONgoodidentifier( 8 bkno IN book.bkno%type) 9 return BOOLEAN; 10 end book; 11 / Package created. SQL> create or replace PACKAGE BODY book AS 2 PROCEDURE findbook( 3 v_medno IN book.bkno%type,
  61. 61. LEIT116 4 v_description OUT book.description%type,v_cost OUT book.cost%type) IS 5 begin 6 select description,cost 7 into v_description,v_cost 8 from 9 book where medno=v_medno; 10 if SQL%ROWCOUNT = 0 then 11 RAISE v_bkno NOTFOUND; 12 end if; 13 end findbook; 14 FUNCTION goodidentifier( 15 v_medno IN book.bkno%type) 16 return BOOLEAN 17 IS 18 v_id_count number; 19 begin 20 select count(*) into v_id_count 21 from book 22 where bkno=v_bkno; 23 return (1=v_id_count); 24 EXCEPTION 25 WHEN OTHERS THEN 26 RETURN FALSE; 27 END goodidentifier; 28 end med; 29 /
  62. 62. LEIT116 Package Body created. SQL> declare 2 v_descriptionbook.description%type; 3 v_costbook.cost%type; 4 v_mednobook.bkno%type; 5 begin 6 book.findbook(v_bkno,v_description,v_cost); 7 dbms_output.put_line('the book is found'); 8 EXCEPTION 9 WHEN OTHERS THEN 10 DBMS_OUTPUT.PUT_LINE('cannot find book'); 11 end; 12 / the book is found PL/SQL procedure successfully completed. Result: Thus the pl/sql in procedure,function and packages was successfully executed and the output was verified.
  63. 63. LEIT116 EXP:10 TRIGGERS 22.10.2013 BEFORE TRIGGERS: SQL> SET SERVEROUTPUT ON SQL> CREATE OR REPLACE TRIGGER LIB_BI_TRIGGER 2 BEFORE INSERT ON LIB 3 FOR EACH ROW 4 DECLARE 5 V_BKID NUMBER(9); 6 V_BKNAME VARCHAR(12); 7 BEGIN 8 SELECT BKID,BKNAME INTO V_BKID,V_BKNAME FROM LIB; 9 :NEW.BKID:=V_BKID; 10 :NEW.BKNAME:=V_BKNAME; 11 END; 12 / Trigger created. AFTER TRIGGERS: SQL> CREATE OR REPLACE TRIGGER LIB_ADU_TRIGGER 2 AFTER DELETE OR UPDATE ON LIB 3 DECLARE 4 V_LIBNAME VARCHAR(9); 5 BEGIN 6 IF DELETING THEN 7 V_LIBNAME:='DELETE'; 8 ELSIF UPDATING THEN
  64. 64. LEIT116 9 V_LIBNAME:='UPDATE'; 10 END IF; 11 INSERT INTO LIB VALUES('AVIL',78,'RASES'); 12 END; 13 / Trigger created. DELETE: SQL> DELETE FROM LIB1 WHERE MEDNAME='PARACIT'; 1 row deleted. SQL> SELECT * FROM LIB1; BKNAME BKTYPE BKID --------- --------- ---------JAVA ENGLISH 80 UPDATE: SQL> UPDATE LIB1 SET BKID=BKID+10 WHERE BKNAME='JAVA'; 1 row updated. SQL> SELECT * FROM LIB1; BKNAME BKTYPE LIBID --------- --------- ---------JAVA ENGLISH 90 INSTEAD OF TRIGGERS: NO DATA MANIPULATION THROUGH COMPLEX VIEW: SQL> CREATE TABLE DOC1(DOCNAME VARCHAR(10),DOCID NUMBER(9),CELLNO NUMBER(10)); Table created. SQL> INSERT INTO DOC1 VALUES('SIVA',789,9876543456); 1 row created.
  65. 65. LEIT116 SQL> INSERT INTO DOC1 VALUES('GUNA',779,9878967251); 1 row created. SQL> SELECT * FROM DOC1; DOCNAME DOCID CELLNO ---------- ---------- ---------SIVA GUNA 789 9876543456 779 9878967251 SQL> CREATE OR REPLACE VIEW HOST ASSELECT DOCNAME,CELLNO FROM DOC1 WHERE DOCID=779; View created. DELETE: SQL> DELETE FROM HOST WHERE DOCNAME='GUNA'; 1 row deleted. SQL> SELECT * FROM HOST; no rows selected SQL> SELECT * FROM DOc1; DOCNAME DOCID CELLNO ---------- ---------- ---------SIVA 789 9876543456 DATA MANIPULATION AND THE INSTEAD OF TRIGGER: SQL> CREATE TABLE HOS4(DOCNAME VARCHAR(9),DOCID NUMBER(9),CELLNO NUMBER(10)); Table created. SQL> INSERT INTO HOS4 VALUES('RAVI',897,9876543212); 1 row created. SQL> INSERT INTO HOS4 VALUES('KAVI',899,9876543218); 1 row created.
  66. 66. LEIT116 SQL> CREATE OR REPLACE VIEW DOCHOS AS 2 SELECT DOCNAME,CELLNO FROM HOS4 3 WHERE DOCID=899; View created. SQL> CREATE OR REPLACE TRIGGER GOVTHOS_DELETE_IOD 2 INSTEAD OF DELETE ON DOCHOS 3 FOR EACH ROW 4 BEGIN 5 DELETE FROM HOS4 6 WHERE DOCID=899; 7 END; 8 / Trigger created. DELETE: SQL> DELETE FROM DOCHOS WHERE DOCNAME='RAVI'; 0 rows deleted. QUERIES: WRITE A PL/SQL TRIGGER TO ENFORCE THE FOLLOWING RULES : A.) AN EMPLOYEE CAN’T HAVE A SALARY HIGHER THAN HIS/HER DEPT MANAGER: B.) AN EMPLOYEE CAN’T WORK ON MORE THAN TWO PROJECTS CONTOLLED BY A SINGLE DEPT: SQL> create or replace trigger tri1 before insert on employee 2 for each row 3 declare 4 p number(20);
  67. 67. LEIT116 5 s number(10); 6 begin 7 select salary into s from employee e,department d 8 wheree.dno=d.dno; 9 selectmgrssn into p from employee e,department d 10 wheree.dno=d.dno; 11 if p>s then 12 raise_application_error(-20078,'salary of the employee shld not be greater than the manager'); 13 end if; 14 end; 15 / Trigger created. SQL> create or replace trigger pro1 before insert or update on project 2 for each row 3 declare 4 no number(10); 5 begin 6 select count(pname) into no from project where dnum=:new.dnum; 7 if no>2 then 8 raise_application_error(-20011,'an employee cant work on more than two projects'); 9 end if; 10 end; 11 / Trigger created.
  68. 68. LEIT116 SQL> insert into project values('p1',15,'ngl',13); 1 row created. SQL> insert into project values('p1',16,'ngl',13); 1 row created. RESULT: Thus the queries are implemented by using triggers.
  69. 69. LEIT116 EXP:11 CLASSIFICATION AND CLUSTERING USING WEKA 29.10.13 Aim : To implement clustering and classification by using weka. CLASSIFICATION: === Run information === Scheme: weka.classifiers.rules.ZeroR Relation: weather Instances: 14 Attributes: 5 outlook temperature humidity windy play Test mode: 10-fold cross-validation === Classifier model (full training set) === ZeroR predicts class value: yes Time taken to build model: 0 seconds === Stratified cross-validation === === Summary === Correctly Classified Instances 9 64.2857 %
  70. 70. LEIT116 Incorrectly Classified Instances Kappa statistic 5 35.7143 % 0 Mean absolute error 0.4762 Root mean squared error 0.4934 Relative absolute error 100 Root relative squared error 100 Total Number of Instances % % 14 === Detailed Accuracy By Class === TP Rate FP Rate Precision Recall F-Measure ROC Area Class 1 1 0.643 0 0 0 Weighted Avg. 0.643 0 0.643 === Confusion Matrix === a b <-- classified as 9 0 | a = yes 5 0 | b = no 1 0.783 0 0.413 0.178 yes 0.178 no 0.643 0.503 0.178
  71. 71. LEIT116 @relation weather @attribute outlook {sunny, overcast, rainy} @attribute temperature real @attribute humidity real @attribute windy {TRUE, FALSE} @attribute play {yes, no} @data sunny,85,85,FALSE,no sunny,80,90,TRUE,no overcast,83,86,FALSE,yes rainy,70,96,FALSE,yes rainy,68,80,FALSE,yes rainy,65,70,TRUE,no overcast,64,65,TRUE,yes sunny,72,95,FALSE,no
  72. 72. LEIT116 sunny,69,70,FALSE,yes rainy,75,80,FALSE,yes sunny,75,70,TRUE,yes overcast,72,90,TRUE,yes overcast,81,75,FALSE,yes rainy,71,91,TRUE,no CLUSTERING: === Run information === Scheme: weka.clusterers.EM -I 100 -N -1 -M 1.0E-6 -S 100 Relation: weather Instances: 14 Attributes: 5 outlook temperature humidity windy play Test mode: split 50% train, remainder test === Clustering model (full training set) === EM
  73. 73. LEIT116 == Number of clusters selected by cross validation: 1 Cluster Attribute 0 (1) ====================== outlook sunny 6 overcast 5 rainy 6 [total] 17 temperature mean 73.5714 std. dev. 6.3326 humidity mean 81.6429 std. dev. 9.9111 windy TRUE 7 FALSE 9 [total] 16 play yes 10
  74. 74. LEIT116 no 6 [total] 16 === Model and evaluation on test split === EM == Number of clusters selected by cross validation: 1 Cluster Attribute 0 (1) ====================== outlook sunny 3 overcast 3 rainy 4 [total] 10 temperature mean std. dev. 72.2857 6.227 humidity mean 79.5714 std. dev. 11.4998
  75. 75. LEIT116 windy TRUE 6 FALSE 3 [total] 9 play yes 5 no 4 [total] 9 Clustered Instances 0 7 (100%) Log likelihood: -9.73408
  76. 76. LEIT116
  77. 77. LEIT116 Result: Thus the implementation of classification and clustering was successfully executed.

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