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Unit 3   hw 2 - solving 1 step equations
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Unit 3 hw 2 - solving 1 step equations

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  • Transcript

    • 1. Unit 3 - Homework 2 Solving 1-Step Equations
    • 2. Solving EquationsSolving means to get the variable alone.Think OPPOSITE SIDE = OPPOSITEOPERATION
    • 3. Solve for x.x+3= 5
    • 4. Solve for x. Circle the term with thex+3= 5 variable you need to isolate.
    • 5. Solve for x. Circle the term with thex+3= 5 variable you need to isolate.
    • 6. Solve for x. Circle the term with thex+3= 5 variable you need to isolate. Anything outside the circle needs to move to the other side by doing the opposite operation.
    • 7. Solve for x. Circle the term with thex+3= 5 variable you need to isolate. Anything outside the circle needs to move to the other side by doing the opposite operation. Opposite of addition is Subtraction.
    • 8. Solve for x. Circle the term with thex+3= 5 variable you need to isolate. −3 −3 Anything outside the circle needs to move to the other side by doing the opposite operation. Opposite of addition is Subtraction.
    • 9. Solve for x. Circle the term with thex+3= 5 variable you need to isolate. −3 −3 Anything outside the circle needs to move to the other side by doing the opposite x=2 operation. Opposite of addition is Subtraction.
    • 10. Solve for x. Circle the term with thex+3= 5 variable you need to isolate. −3 −3 Anything outside the circle needs to move to the other side by doing the opposite x=2 operation. Opposite of addition is Subtraction. x is alone so you are done.
    • 11. Solve for x.x − 8 = −2
    • 12. Solve for x. Circle the term with thex − 8 = −2 variable you need to isolate.
    • 13. Solve for x. Circle the term with thex − 8 = −2 variable you need to isolate.
    • 14. Solve for x. Circle the term with thex − 8 = −2 variable you need to isolate. Move 8 by opposite operation.
    • 15. Solve for x. Circle the term with thex − 8 = −2 variable you need to isolate. Move 8 by opposite operation. Opposite of subtraction is addition.
    • 16. Solve for x. Circle the term with thex − 8 = −2 variable you need to +8 +8 isolate. Move 8 by opposite operation. Opposite of subtraction is addition.
    • 17. Solve for x. Circle the term with thex − 8 = −2 variable you need to +8 +8 isolate. Move 8 by opposite x=6 operation. Opposite of subtraction is addition.
    • 18. Solve for x. Circle the term with thex − 8 = −2 variable you need to +8 +8 isolate. Move 8 by opposite x=6 operation. Opposite of subtraction is addition. x is alone so you are done.
    • 19. Solve for x.−3x = −8
    • 20. Solve for x. Circle the term with the−3x = −8 variable you need to isolate.
    • 21. Solve for x. Circle the term with the−3x = −8 variable you need to isolate.
    • 22. Solve for x. Circle the term with the−3x = −8 variable you need to isolate. There is nothing outside the circle so look inside now.
    • 23. Solve for x. Circle the term with the−3x = −8 variable you need to isolate. There is nothing outside the circle so look inside now. Opposite of multiplication is division.
    • 24. Solve for x. Circle the term with the−3x = −8 variable you need to isolate. − 3 −3 There is nothing outside the circle so look inside now. Opposite of multiplication is division.
    • 25. Solve for x. Circle the term with the−3x = −8 variable you need to isolate. − 3 −3 There is nothing outside the circle so look inside 8 now. x= Opposite of multiplication is 3 division.
    • 26. Solve for x. Circle the term with the−3x = −8 variable you need to isolate. − 3 −3 There is nothing outside the circle so look inside 8 now. x= Opposite of multiplication is 3 division. x is alone so you are done.
    • 27. Solve for x. x =7 5
    • 28. Solve for x. x Circle the term with the =7 variable you need to 5 isolate.
    • 29. Solve for x. x Circle the term with the =7 variable you need to 5 isolate.
    • 30. Solve for x. x Circle the term with the =7 variable you need to 5 isolate. There is nothing outside the circle so look inside.
    • 31. Solve for x. x Circle the term with the =7 variable you need to 5 isolate. There is nothing outside the circle so look inside. Opposite of division is multiplication.
    • 32. Solve for x. x Circle the term with the5 ⋅ = 7⋅ 5 variable you need to 5 isolate. There is nothing outside the circle so look inside. Opposite of division is multiplication.
    • 33. Solve for x. x Circle the term with the5 ⋅ = 7⋅ 5 variable you need to 5 isolate. There is nothing outside x = 35 the circle so look inside. Opposite of division is multiplication.
    • 34. Solve for x. x Circle the term with the5 ⋅ = 7⋅ 5 variable you need to 5 isolate. There is nothing outside x = 35 the circle so look inside. Opposite of division is multiplication. x is alone so you are done.
    • 35. Solve for x.7 − x = −1
    • 36. Solve for x. Circle the term with the7 − x = −1 variable you need to isolate.
    • 37. Solve for x. Circle the term with the7 − x = −1 variable you need to isolate.
    • 38. Solve for x. Circle the term with the7 − x = −1 variable you need to isolate. Anything outside the circle needs to move to the other side by doing the opposite operation.
    • 39. Solve for x. Circle the term with the7 − x = −1 variable you need to isolate. Anything outside the circle needs to move to the other side by doing the opposite operation. The 7 is positive so Subtract.
    • 40. Solve for x. Circle the term with the 7 − x = −1 variable you need to isolate.−7 −7 Anything outside the circle needs to move to the other side by doing the opposite operation. The 7 is positive so Subtract.
    • 41. Solve for x. Circle the term with the 7 − x = −1 variable you need to isolate.−7 −7 Anything outside the circle needs to move to the other −x = −8 side by doing the opposite operation. The 7 is positive so Subtract.
    • 42. Solve for x. Circle the term with the 7 − x = −1 variable you need to isolate.−7 −7 Anything outside the circle needs to move to the other −x = −8 side by doing the opposite operation. The 7 is positive so Subtract. x is NOT alone. Divide by negative one.
    • 43. Solve for x. Circle the term with the 7 − x = −1 variable you need to isolate.−7 −7 Anything outside the circle needs to move to the other −x = −8 side by doing the opposite operation. −1 −1 The 7 is positive so Subtract. x is NOT alone. Divide by negative one.
    • 44. Solve for x. Circle the term with the 7 − x = −1 variable you need to isolate.−7 −7 Anything outside the circle needs to move to the other −x = −8 side by doing the opposite operation. −1 −1 The 7 is positive so Subtract. x is NOT alone. Divide by x=8 negative one.
    • 45. Solve for x. Circle the term with the 7 − x = −1 variable you need to isolate.−7 −7 Anything outside the circle needs to move to the other −x = −8 side by doing the opposite operation. −1 −1 The 7 is positive so Subtract. x is NOT alone. Divide by x=8 negative one. x is alone so you are done.