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# Unit 3 hw 2 - solving 1 step equations

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• ### Unit 3 hw 2 - solving 1 step equations

1. 1. Unit 3 - Homework 2 Solving 1-Step Equations
2. 2. Solving EquationsSolving means to get the variable alone.Think OPPOSITE SIDE = OPPOSITEOPERATION
3. 3. Solve for x.x+3= 5
4. 4. Solve for x. Circle the term with thex+3= 5 variable you need to isolate.
5. 5. Solve for x. Circle the term with thex+3= 5 variable you need to isolate.
6. 6. Solve for x. Circle the term with thex+3= 5 variable you need to isolate. Anything outside the circle needs to move to the other side by doing the opposite operation.
7. 7. Solve for x. Circle the term with thex+3= 5 variable you need to isolate. Anything outside the circle needs to move to the other side by doing the opposite operation. Opposite of addition is Subtraction.
8. 8. Solve for x. Circle the term with thex+3= 5 variable you need to isolate. −3 −3 Anything outside the circle needs to move to the other side by doing the opposite operation. Opposite of addition is Subtraction.
9. 9. Solve for x. Circle the term with thex+3= 5 variable you need to isolate. −3 −3 Anything outside the circle needs to move to the other side by doing the opposite x=2 operation. Opposite of addition is Subtraction.
10. 10. Solve for x. Circle the term with thex+3= 5 variable you need to isolate. −3 −3 Anything outside the circle needs to move to the other side by doing the opposite x=2 operation. Opposite of addition is Subtraction. x is alone so you are done.
11. 11. Solve for x.x − 8 = −2
12. 12. Solve for x. Circle the term with thex − 8 = −2 variable you need to isolate.
13. 13. Solve for x. Circle the term with thex − 8 = −2 variable you need to isolate.
14. 14. Solve for x. Circle the term with thex − 8 = −2 variable you need to isolate. Move 8 by opposite operation.
15. 15. Solve for x. Circle the term with thex − 8 = −2 variable you need to isolate. Move 8 by opposite operation. Opposite of subtraction is addition.
16. 16. Solve for x. Circle the term with thex − 8 = −2 variable you need to +8 +8 isolate. Move 8 by opposite operation. Opposite of subtraction is addition.
17. 17. Solve for x. Circle the term with thex − 8 = −2 variable you need to +8 +8 isolate. Move 8 by opposite x=6 operation. Opposite of subtraction is addition.
18. 18. Solve for x. Circle the term with thex − 8 = −2 variable you need to +8 +8 isolate. Move 8 by opposite x=6 operation. Opposite of subtraction is addition. x is alone so you are done.
19. 19. Solve for x.−3x = −8
20. 20. Solve for x. Circle the term with the−3x = −8 variable you need to isolate.
21. 21. Solve for x. Circle the term with the−3x = −8 variable you need to isolate.
22. 22. Solve for x. Circle the term with the−3x = −8 variable you need to isolate. There is nothing outside the circle so look inside now.
23. 23. Solve for x. Circle the term with the−3x = −8 variable you need to isolate. There is nothing outside the circle so look inside now. Opposite of multiplication is division.
24. 24. Solve for x. Circle the term with the−3x = −8 variable you need to isolate. − 3 −3 There is nothing outside the circle so look inside now. Opposite of multiplication is division.
25. 25. Solve for x. Circle the term with the−3x = −8 variable you need to isolate. − 3 −3 There is nothing outside the circle so look inside 8 now. x= Opposite of multiplication is 3 division.
26. 26. Solve for x. Circle the term with the−3x = −8 variable you need to isolate. − 3 −3 There is nothing outside the circle so look inside 8 now. x= Opposite of multiplication is 3 division. x is alone so you are done.
27. 27. Solve for x. x =7 5
28. 28. Solve for x. x Circle the term with the =7 variable you need to 5 isolate.
29. 29. Solve for x. x Circle the term with the =7 variable you need to 5 isolate.
30. 30. Solve for x. x Circle the term with the =7 variable you need to 5 isolate. There is nothing outside the circle so look inside.
31. 31. Solve for x. x Circle the term with the =7 variable you need to 5 isolate. There is nothing outside the circle so look inside. Opposite of division is multiplication.
32. 32. Solve for x. x Circle the term with the5 ⋅ = 7⋅ 5 variable you need to 5 isolate. There is nothing outside the circle so look inside. Opposite of division is multiplication.
33. 33. Solve for x. x Circle the term with the5 ⋅ = 7⋅ 5 variable you need to 5 isolate. There is nothing outside x = 35 the circle so look inside. Opposite of division is multiplication.
34. 34. Solve for x. x Circle the term with the5 ⋅ = 7⋅ 5 variable you need to 5 isolate. There is nothing outside x = 35 the circle so look inside. Opposite of division is multiplication. x is alone so you are done.
35. 35. Solve for x.7 − x = −1
36. 36. Solve for x. Circle the term with the7 − x = −1 variable you need to isolate.
37. 37. Solve for x. Circle the term with the7 − x = −1 variable you need to isolate.
38. 38. Solve for x. Circle the term with the7 − x = −1 variable you need to isolate. Anything outside the circle needs to move to the other side by doing the opposite operation.
39. 39. Solve for x. Circle the term with the7 − x = −1 variable you need to isolate. Anything outside the circle needs to move to the other side by doing the opposite operation. The 7 is positive so Subtract.
40. 40. Solve for x. Circle the term with the 7 − x = −1 variable you need to isolate.−7 −7 Anything outside the circle needs to move to the other side by doing the opposite operation. The 7 is positive so Subtract.
41. 41. Solve for x. Circle the term with the 7 − x = −1 variable you need to isolate.−7 −7 Anything outside the circle needs to move to the other −x = −8 side by doing the opposite operation. The 7 is positive so Subtract.
42. 42. Solve for x. Circle the term with the 7 − x = −1 variable you need to isolate.−7 −7 Anything outside the circle needs to move to the other −x = −8 side by doing the opposite operation. The 7 is positive so Subtract. x is NOT alone. Divide by negative one.
43. 43. Solve for x. Circle the term with the 7 − x = −1 variable you need to isolate.−7 −7 Anything outside the circle needs to move to the other −x = −8 side by doing the opposite operation. −1 −1 The 7 is positive so Subtract. x is NOT alone. Divide by negative one.
44. 44. Solve for x. Circle the term with the 7 − x = −1 variable you need to isolate.−7 −7 Anything outside the circle needs to move to the other −x = −8 side by doing the opposite operation. −1 −1 The 7 is positive so Subtract. x is NOT alone. Divide by x=8 negative one.
45. 45. Solve for x. Circle the term with the 7 − x = −1 variable you need to isolate.−7 −7 Anything outside the circle needs to move to the other −x = −8 side by doing the opposite operation. −1 −1 The 7 is positive so Subtract. x is NOT alone. Divide by x=8 negative one. x is alone so you are done.