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- 1. Unit 3 - Homework 2 Solving 1-Step Equations
- 2. Solving EquationsSolving means to get the variable alone.Think OPPOSITE SIDE = OPPOSITEOPERATION
- 3. Solve for x.x+3= 5
- 4. Solve for x. Circle the term with thex+3= 5 variable you need to isolate.
- 5. Solve for x. Circle the term with thex+3= 5 variable you need to isolate.
- 6. Solve for x. Circle the term with thex+3= 5 variable you need to isolate. Anything outside the circle needs to move to the other side by doing the opposite operation.
- 7. Solve for x. Circle the term with thex+3= 5 variable you need to isolate. Anything outside the circle needs to move to the other side by doing the opposite operation. Opposite of addition is Subtraction.
- 8. Solve for x. Circle the term with thex+3= 5 variable you need to isolate. −3 −3 Anything outside the circle needs to move to the other side by doing the opposite operation. Opposite of addition is Subtraction.
- 9. Solve for x. Circle the term with thex+3= 5 variable you need to isolate. −3 −3 Anything outside the circle needs to move to the other side by doing the opposite x=2 operation. Opposite of addition is Subtraction.
- 10. Solve for x. Circle the term with thex+3= 5 variable you need to isolate. −3 −3 Anything outside the circle needs to move to the other side by doing the opposite x=2 operation. Opposite of addition is Subtraction. x is alone so you are done.
- 11. Solve for x.x − 8 = −2
- 12. Solve for x. Circle the term with thex − 8 = −2 variable you need to isolate.
- 13. Solve for x. Circle the term with thex − 8 = −2 variable you need to isolate.
- 14. Solve for x. Circle the term with thex − 8 = −2 variable you need to isolate. Move 8 by opposite operation.
- 15. Solve for x. Circle the term with thex − 8 = −2 variable you need to isolate. Move 8 by opposite operation. Opposite of subtraction is addition.
- 16. Solve for x. Circle the term with thex − 8 = −2 variable you need to +8 +8 isolate. Move 8 by opposite operation. Opposite of subtraction is addition.
- 17. Solve for x. Circle the term with thex − 8 = −2 variable you need to +8 +8 isolate. Move 8 by opposite x=6 operation. Opposite of subtraction is addition.
- 18. Solve for x. Circle the term with thex − 8 = −2 variable you need to +8 +8 isolate. Move 8 by opposite x=6 operation. Opposite of subtraction is addition. x is alone so you are done.
- 19. Solve for x.−3x = −8
- 20. Solve for x. Circle the term with the−3x = −8 variable you need to isolate.
- 21. Solve for x. Circle the term with the−3x = −8 variable you need to isolate.
- 22. Solve for x. Circle the term with the−3x = −8 variable you need to isolate. There is nothing outside the circle so look inside now.
- 23. Solve for x. Circle the term with the−3x = −8 variable you need to isolate. There is nothing outside the circle so look inside now. Opposite of multiplication is division.
- 24. Solve for x. Circle the term with the−3x = −8 variable you need to isolate. − 3 −3 There is nothing outside the circle so look inside now. Opposite of multiplication is division.
- 25. Solve for x. Circle the term with the−3x = −8 variable you need to isolate. − 3 −3 There is nothing outside the circle so look inside 8 now. x= Opposite of multiplication is 3 division.
- 26. Solve for x. Circle the term with the−3x = −8 variable you need to isolate. − 3 −3 There is nothing outside the circle so look inside 8 now. x= Opposite of multiplication is 3 division. x is alone so you are done.
- 27. Solve for x. x =7 5
- 28. Solve for x. x Circle the term with the =7 variable you need to 5 isolate.
- 29. Solve for x. x Circle the term with the =7 variable you need to 5 isolate.
- 30. Solve for x. x Circle the term with the =7 variable you need to 5 isolate. There is nothing outside the circle so look inside.
- 31. Solve for x. x Circle the term with the =7 variable you need to 5 isolate. There is nothing outside the circle so look inside. Opposite of division is multiplication.
- 32. Solve for x. x Circle the term with the5 ⋅ = 7⋅ 5 variable you need to 5 isolate. There is nothing outside the circle so look inside. Opposite of division is multiplication.
- 33. Solve for x. x Circle the term with the5 ⋅ = 7⋅ 5 variable you need to 5 isolate. There is nothing outside x = 35 the circle so look inside. Opposite of division is multiplication.
- 34. Solve for x. x Circle the term with the5 ⋅ = 7⋅ 5 variable you need to 5 isolate. There is nothing outside x = 35 the circle so look inside. Opposite of division is multiplication. x is alone so you are done.
- 35. Solve for x.7 − x = −1
- 36. Solve for x. Circle the term with the7 − x = −1 variable you need to isolate.
- 37. Solve for x. Circle the term with the7 − x = −1 variable you need to isolate.
- 38. Solve for x. Circle the term with the7 − x = −1 variable you need to isolate. Anything outside the circle needs to move to the other side by doing the opposite operation.
- 39. Solve for x. Circle the term with the7 − x = −1 variable you need to isolate. Anything outside the circle needs to move to the other side by doing the opposite operation. The 7 is positive so Subtract.
- 40. Solve for x. Circle the term with the 7 − x = −1 variable you need to isolate.−7 −7 Anything outside the circle needs to move to the other side by doing the opposite operation. The 7 is positive so Subtract.
- 41. Solve for x. Circle the term with the 7 − x = −1 variable you need to isolate.−7 −7 Anything outside the circle needs to move to the other −x = −8 side by doing the opposite operation. The 7 is positive so Subtract.
- 42. Solve for x. Circle the term with the 7 − x = −1 variable you need to isolate.−7 −7 Anything outside the circle needs to move to the other −x = −8 side by doing the opposite operation. The 7 is positive so Subtract. x is NOT alone. Divide by negative one.
- 43. Solve for x. Circle the term with the 7 − x = −1 variable you need to isolate.−7 −7 Anything outside the circle needs to move to the other −x = −8 side by doing the opposite operation. −1 −1 The 7 is positive so Subtract. x is NOT alone. Divide by negative one.
- 44. Solve for x. Circle the term with the 7 − x = −1 variable you need to isolate.−7 −7 Anything outside the circle needs to move to the other −x = −8 side by doing the opposite operation. −1 −1 The 7 is positive so Subtract. x is NOT alone. Divide by x=8 negative one.
- 45. Solve for x. Circle the term with the 7 − x = −1 variable you need to isolate.−7 −7 Anything outside the circle needs to move to the other −x = −8 side by doing the opposite operation. −1 −1 The 7 is positive so Subtract. x is NOT alone. Divide by x=8 negative one. x is alone so you are done.

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