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# Unit 3 hw 2 - solving 1 step equations

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• ### Transcript

• 1. Unit 3 - Homework 2 Solving 1-Step Equations
• 2. Solving EquationsSolving means to get the variable alone.Think OPPOSITE SIDE = OPPOSITEOPERATION
• 3. Solve for x.x+3= 5
• 4. Solve for x. Circle the term with thex+3= 5 variable you need to isolate.
• 5. Solve for x. Circle the term with thex+3= 5 variable you need to isolate.
• 6. Solve for x. Circle the term with thex+3= 5 variable you need to isolate. Anything outside the circle needs to move to the other side by doing the opposite operation.
• 7. Solve for x. Circle the term with thex+3= 5 variable you need to isolate. Anything outside the circle needs to move to the other side by doing the opposite operation. Opposite of addition is Subtraction.
• 8. Solve for x. Circle the term with thex+3= 5 variable you need to isolate. −3 −3 Anything outside the circle needs to move to the other side by doing the opposite operation. Opposite of addition is Subtraction.
• 9. Solve for x. Circle the term with thex+3= 5 variable you need to isolate. −3 −3 Anything outside the circle needs to move to the other side by doing the opposite x=2 operation. Opposite of addition is Subtraction.
• 10. Solve for x. Circle the term with thex+3= 5 variable you need to isolate. −3 −3 Anything outside the circle needs to move to the other side by doing the opposite x=2 operation. Opposite of addition is Subtraction. x is alone so you are done.
• 11. Solve for x.x − 8 = −2
• 12. Solve for x. Circle the term with thex − 8 = −2 variable you need to isolate.
• 13. Solve for x. Circle the term with thex − 8 = −2 variable you need to isolate.
• 14. Solve for x. Circle the term with thex − 8 = −2 variable you need to isolate. Move 8 by opposite operation.
• 15. Solve for x. Circle the term with thex − 8 = −2 variable you need to isolate. Move 8 by opposite operation. Opposite of subtraction is addition.
• 16. Solve for x. Circle the term with thex − 8 = −2 variable you need to +8 +8 isolate. Move 8 by opposite operation. Opposite of subtraction is addition.
• 17. Solve for x. Circle the term with thex − 8 = −2 variable you need to +8 +8 isolate. Move 8 by opposite x=6 operation. Opposite of subtraction is addition.
• 18. Solve for x. Circle the term with thex − 8 = −2 variable you need to +8 +8 isolate. Move 8 by opposite x=6 operation. Opposite of subtraction is addition. x is alone so you are done.
• 19. Solve for x.−3x = −8
• 20. Solve for x. Circle the term with the−3x = −8 variable you need to isolate.
• 21. Solve for x. Circle the term with the−3x = −8 variable you need to isolate.
• 22. Solve for x. Circle the term with the−3x = −8 variable you need to isolate. There is nothing outside the circle so look inside now.
• 23. Solve for x. Circle the term with the−3x = −8 variable you need to isolate. There is nothing outside the circle so look inside now. Opposite of multiplication is division.
• 24. Solve for x. Circle the term with the−3x = −8 variable you need to isolate. − 3 −3 There is nothing outside the circle so look inside now. Opposite of multiplication is division.
• 25. Solve for x. Circle the term with the−3x = −8 variable you need to isolate. − 3 −3 There is nothing outside the circle so look inside 8 now. x= Opposite of multiplication is 3 division.
• 26. Solve for x. Circle the term with the−3x = −8 variable you need to isolate. − 3 −3 There is nothing outside the circle so look inside 8 now. x= Opposite of multiplication is 3 division. x is alone so you are done.
• 27. Solve for x. x =7 5
• 28. Solve for x. x Circle the term with the =7 variable you need to 5 isolate.
• 29. Solve for x. x Circle the term with the =7 variable you need to 5 isolate.
• 30. Solve for x. x Circle the term with the =7 variable you need to 5 isolate. There is nothing outside the circle so look inside.
• 31. Solve for x. x Circle the term with the =7 variable you need to 5 isolate. There is nothing outside the circle so look inside. Opposite of division is multiplication.
• 32. Solve for x. x Circle the term with the5 ⋅ = 7⋅ 5 variable you need to 5 isolate. There is nothing outside the circle so look inside. Opposite of division is multiplication.
• 33. Solve for x. x Circle the term with the5 ⋅ = 7⋅ 5 variable you need to 5 isolate. There is nothing outside x = 35 the circle so look inside. Opposite of division is multiplication.
• 34. Solve for x. x Circle the term with the5 ⋅ = 7⋅ 5 variable you need to 5 isolate. There is nothing outside x = 35 the circle so look inside. Opposite of division is multiplication. x is alone so you are done.
• 35. Solve for x.7 − x = −1
• 36. Solve for x. Circle the term with the7 − x = −1 variable you need to isolate.
• 37. Solve for x. Circle the term with the7 − x = −1 variable you need to isolate.
• 38. Solve for x. Circle the term with the7 − x = −1 variable you need to isolate. Anything outside the circle needs to move to the other side by doing the opposite operation.
• 39. Solve for x. Circle the term with the7 − x = −1 variable you need to isolate. Anything outside the circle needs to move to the other side by doing the opposite operation. The 7 is positive so Subtract.
• 40. Solve for x. Circle the term with the 7 − x = −1 variable you need to isolate.−7 −7 Anything outside the circle needs to move to the other side by doing the opposite operation. The 7 is positive so Subtract.
• 41. Solve for x. Circle the term with the 7 − x = −1 variable you need to isolate.−7 −7 Anything outside the circle needs to move to the other −x = −8 side by doing the opposite operation. The 7 is positive so Subtract.
• 42. Solve for x. Circle the term with the 7 − x = −1 variable you need to isolate.−7 −7 Anything outside the circle needs to move to the other −x = −8 side by doing the opposite operation. The 7 is positive so Subtract. x is NOT alone. Divide by negative one.
• 43. Solve for x. Circle the term with the 7 − x = −1 variable you need to isolate.−7 −7 Anything outside the circle needs to move to the other −x = −8 side by doing the opposite operation. −1 −1 The 7 is positive so Subtract. x is NOT alone. Divide by negative one.
• 44. Solve for x. Circle the term with the 7 − x = −1 variable you need to isolate.−7 −7 Anything outside the circle needs to move to the other −x = −8 side by doing the opposite operation. −1 −1 The 7 is positive so Subtract. x is NOT alone. Divide by x=8 negative one.
• 45. Solve for x. Circle the term with the 7 − x = −1 variable you need to isolate.−7 −7 Anything outside the circle needs to move to the other −x = −8 side by doing the opposite operation. −1 −1 The 7 is positive so Subtract. x is NOT alone. Divide by x=8 negative one. x is alone so you are done.