Upcoming SlideShare
×

# ใบความรู้ที่ 1 เรื่อง การถ่ายเทความร้อน

3,039 views

Published on

3 Likes
Statistics
Notes
• Full Name
Comment goes here.

Are you sure you want to Yes No
• Be the first to comment

Views
Total views
3,039
On SlideShare
0
From Embeds
0
Number of Embeds
618
Actions
Shares
0
56
0
Likes
3
Embeds 0
No embeds

No notes for slide

### ใบความรู้ที่ 1 เรื่อง การถ่ายเทความร้อน

1. 1. FF 1 1 F F F F1. F F F F F F F F F F FF F F F F F F F F F F F F F F F F F F F F ˈ 1. F ˈ 2 F F F 2. F F ( F ) Q = mc∆ t QL = mL 3. F F F ( F ) Q = mc∆ t QL = mL 4. F F F = F ˈ F F F F Q = mc∆ t QL = mL Q = mc∆ t QL = mL F F F F F F F F F F F F F F F F 100 F F http://krunok2555.wordpress.com
2. 2. 1. F F F F 00C F F F 00C F 2. F F F F 1000C F F F1000C F F2. F 1. ˈ F ˂ F F 2. F F F F F F 3. F F F F 2.1 F 1 F ( Robber Boyle ) F ˈ F F F ʾ . . 1662 F F F F F F ˈ F F ˈ 2 F F F F F F 2.5 2.5 F F P V T F F http://krunok2555.wordpress.com
3. 3. F F P= F V= F 1 F F P F V 1 P = k  K = F slope V PV = K = F K F F F F F F F F FP V ˈ F F (P) F(V) T1 , T 2 T3 F T3 > T 2 > T 1 F F F F F F ˈ F ∴ F P1 V 1 = P 2 V 2 ( F ) P1 V1 ˈ F P2 V2 ˈ F 2 F F ( Jacques Charles ) F , F F F F F F F F F ʾ . .1787 F F F F FF F F F F F F F ˈ F 2.6 -273.150C F F http://krunok2555.wordpress.com
4. 4. 2.6 F F (V) (T) v0 a F slope = 273.15  v0  V=  t + v0  273.15   t  V = v 0 1 +  ------ ∂  273.15  ∂ FF F ˈ F F F ˈ F F ˈ F273.150C 273.150C F ˈ F F 273.150C OK F F F (absolute zero) ˈ F F F F F F F ˈ F (a) ˈ F F F ˈ F F ʽ F F F F F F 0.0015 F F T = 273.15 + t T= , t= F F T t (a) F FV T (K) F (b) (b) F V = KT K = slope V = K T F F http://krunok2555.wordpress.com
5. 5. K F F F FF F ˈ F F F F F F F F F V1 V2 = T1 T2 3 F ( Gay Lussac ) Gay Lussac F F FFF F F F ˈ F ˈ F F ˈ F 2.7 F F (P) (T) F F F P = KT K = slope P = K T K F F F F F P1 T1 P2 T2 F F P1 P2 = ( ) T1 T2 F F http://krunok2555.wordpress.com
6. 6. 4 F ( Gas Law ) F F F F F F F F FP1 V1 T1 F P2 V2T2 F F ˈ F 1. P1 V1 ˈ P2 Vt F F T1 2 P1 , V 1 , T 1 T P 2 , V t , T1 F F P1 V 1 = P 2 V t ∴ PV Vt = 1 1 - -- - - - - ∂ P2 2. Vt T1 ˈ V2 T2 F ˈ P2 F 2 3 P 2 , V t , T1 P P2 , V 2 , T2 Vt V2 F F F = - -- - - - - • T1 T2 P1V1 V2 F ∂ • F = P2T1 T2 ∴ P1V1 P2V2 T1 = T2 - - - - - - -÷ PV ÷ F F F PV = K K F T T F F F F http://krunok2555.wordpress.com
7. 7. F K F F S.T.P ( T = 273 , P = 1.01x 105 2/ ) 1 22.4 ∴ F K F 1 F K= PV T 1.01x105 x 22.4x10−3 = 273 K = 8 . 28 ≈ 8 . 3 J / mole .K F F 1 = 8.3 J/mole.K F F F F FR F F Fn F F PV = nR T PV = nRT (N) F F (n) F F 1 = 6.02 × 1023 F n F = 6.02 × 1023 n F F NA = = 6.02 × 1023 N = F n N F N = nNA n= NÄ PV = nRT F F PV = N RT NÄ  R   8 .3  PV = N  N T  = N  T   Ä  6 . 02 x 10 23  ( PV = N 1 .38 x10 − 23 T ) ΡV = NK BT R KB = = 1.38x10 − 23 J / K F F F NA F F F มวลเป็ นกรัมของก๊าซ (m ) (n ) = มวลโมเลกุล ของก๊าซ (M ) F F http://krunok2555.wordpress.com
8. 8. mF F n = PV = nRT M m PV = RT M PV R = mT M R F ˈ F F F F FF F F M PV F F F mT F 1. F P, V , T PV = nRT 2. F P, V , T ΡV = NK BT 3. F F F F P1 V1 P V = 2 2 m 1T1 m 2 T2 F F http://krunok2555.wordpress.com