Chapter 07

2,854 views

Published on

Chapter 7 powerpoint

Published in: Education
0 Comments
7 Likes
Statistics
Notes
  • Be the first to comment

No Downloads
Views
Total views
2,854
On SlideShare
0
From Embeds
0
Number of Embeds
7
Actions
Shares
0
Downloads
0
Comments
0
Likes
7
Embeds 0
No embeds

No notes for slide

Chapter 07

  1. 1. Splash Screen
  2. 2. Chapter Menu <ul><li>Lesson 7-1 Multiplying Monomials </li></ul><ul><li>Lesson 7-2 Dividing Monomials </li></ul><ul><li>Lesson 7-3 Polynomials </li></ul><ul><li>Lesson 7-4 Adding and Subtracting Polynomials </li></ul><ul><li>Lesson 7-5 Multiplying a Polynomial by a Monomial </li></ul><ul><li>Lesson 7-6 Multiplying Polynomials </li></ul><ul><li>Lesson 7-7 Special Products </li></ul>
  3. 3. Lesson 1 Menu Five-Minute Check (over Chapter 6) Main Ideas and Vocabulary Example 1: Identify Monomials Key Concept: Product of Powers Example 2: Product of Powers Key Concept: Power of a Power Example 3: Power of a Power Key Concept: Power of a Product Example 4: Power of a Product Concept Summary: Simplifying Expressions Example 5: Simplify Expressions
  4. 4. Lesson 1 MI/Vocab <ul><li>monomial </li></ul><ul><li>constant </li></ul><ul><li>Multiply monomials. </li></ul><ul><li>Simplify expressions involving powers of monomials. </li></ul>
  5. 5. Lesson 1 Ex1 Identify Monomials Determine whether each expression is a monomial. Explain your reasoning.
  6. 6. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>Lesson 1 CYP1 Which expression is a monomial? A. x 5 B. 3 p – 1 C. D.
  7. 7. Key Concept 7-1a
  8. 8. Lesson 1 Ex2 Product of Powers A. Simplify ( r 4 )(–12 r 7 ). ( r 4 )(–12 r 7 ) = (1)(–12)( r 4 )( r 7 ) Group the coefficients and the variables. = –12( r 4+7 ) Product of Powers Answer: = –12 r 11 Simplify.
  9. 9. Lesson 1 Ex2 Product of Powers B. Simplify (6 cd 5 )(5 c 5 d 2 ). Answer: = 30 c 6 d 7 Simplify. (6 cd 5 )(5 c 5 d 2 ) = (6)(5)( c ● c 5 )( d 5 d 2 ) Group the coefficients and the variables. = 30( c 1+5 )( d 5+2 ) Product of Powers
  10. 10. Lesson 1 CYP2 <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>A. 9 x 5 B. 20 x 5 C. 20 x 6 D. 9 x 6 A. Simplify (5 x 2 )(4 x 3 ).
  11. 11. Lesson 1 CYP2 <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>A. 6 xy 5 B. –6 x 2 y 6 C. 1 x 3 y 5 D. –6 x 3 y 5 B. Simplify 3 xy 2 (–2 x 2 y 3 ).
  12. 12. Key Concept 7-1b
  13. 13. Lesson 1 Ex3 Power of a Power Simplify [(2 3 ) 3 ] 2 . Answer: = 2 18 or 262,144 Simplify. [(2 3 ) 3 ] 2 = (2 3●3 ) 2 Power of a Power = (2 9 ) 2 Simplify. = 2 9●2 Power of a Power
  14. 14. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>Lesson 1 CYP3 A. 4 7 B. 4 8 C. 4 12 D. 4 10 Simplify [(4 2 ) 2 ] 3 .
  15. 15. Key Concept 7-1c
  16. 16. Lesson 1 Ex4 GEOMETRY Find the volume of a cube with side length 5 xyz . Answer: = 125 x 3 y 3 z 3 Simplify. Power of a Product Volume = s 3 Formula for volume of a cube = (5 xyz ) 3 Replace s with 5 xyz. = 5 3 x 3 y 3 z 3 Power of a Product
  17. 17. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>Lesson 1 CYP4 A. 8 p 3 q 3 B. 24 p 2 q 2 C. 6 p 2 q 2 D. 8 p 2 q 2 Express the surface area of the cube as a monomial.
  18. 18. Concept Summary 7-1d
  19. 19. Lesson 1 Ex5 Simplify [(8 g 3 h 4 ) 2 ] 2 (2 gh 5 ) 4 . [(8 g 3 h 4 ) 2 ] 2 (2 gh 5 ) 4 = (8 g 3 h 4 ) 4 (2 gh 5 ) 4 Power of a Power = (8 4 )( g 3 ) 4 ( h 4 ) 4 (2) 4 g 4 (h 5 ) 4 Power of a Product = 4096 g 12 h 16 (16) g 4 h 20 Power of a Power = 4096(16) g 12 ● g 4 ● h 16 ● h 20 Commutative Property Answer: = 65,536 g 16 h 36 Power of Powers Simplify Expressions
  20. 20. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>Lesson 1 CYP5 A. 1728 c 27 d 24 B. 6 c 7 d 5 C. 24 c 13 d 10 D. 5 c 7 d 21 Simplify [(2 c 2 d 3 ) 2 ] 3 (3 c 5 d 2 ) 3 .
  21. 21. End of Lesson 1
  22. 22. Lesson 2 Menu Five-Minute Check (over Lesson 7-1) Main Ideas and Vocabulary Key Concept: Quotient of Powers Example 1: Quotient of Powers Key Concept: Power of a Quotient Example 2: Power of a Quotient Key Concept: Zero Exponent Example 3: Zero Exponent Key Concept: Negative Exponent Example 4: Negative Exponents Example 5: Standardized Test Practice: Apply Properties of Exponents
  23. 23. Lesson 2 MI/Vocab <ul><li>zero exponent </li></ul><ul><li>negative exponent </li></ul><ul><li>Simplify expressions involving the quotient of monomials. </li></ul><ul><li>Simplify expressions containing negative exponents. </li></ul>
  24. 24. Key Concept 7-2a
  25. 25. Lesson 2 Ex1 Quotient of Powers Group powers that have the same base. Answer: = xy 9 Quotient of Powers
  26. 26. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>Lesson 2 CYP1 A. B. C. D.
  27. 27. Key Concept 7-2b BrainPOP: Multiplying and Dividing Monomials
  28. 28. Lesson 2 Ex2 Power of a Quotient Power of a Quotient Power of a Quotient Answer: Power of a Power
  29. 29. Lesson 2 CYP2 <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>A. AnsA B. AnsB C. AnsC D. AnsD Simplify
  30. 30. Key Concept 7-2c
  31. 31. Lesson 2 Ex3 Zero Exponent Answer: 1 A.
  32. 32. Lesson 2 Ex3 Zero Exponent B. a 0 = 1 Answer: n Quotient of Powers Simplify.
  33. 33. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>Lesson 2 CYP3 A. B. 1 C. 0 D. –1 A. Simplify . Assume that z is not equal to zero.
  34. 34. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>Lesson 2 CYP3 A. B. C. D. B. Simplify . Assume that x and k are not equal to zero.
  35. 35. Key Concept 7-2d
  36. 36. Lesson 2 Ex4 Negative Exponent Properties Negative Exponents A. Simplify . Assume that no denominator is equal to zero. Answer:
  37. 37. Lesson 2 Ex4 Group powers with the same base. Negative Exponents Quotient of Powers and Negative Exponent Properties B. Simplify . Assume that p , q and r are not equal to zero.
  38. 38. Lesson 2 Ex4 Negative Exponent Properties Negative Exponents Simplify. Answer: Multiply fractions.
  39. 39. Lesson 2 Ex4 Group powers with the same base. Negative Exponents Simplify. C. Simplify . Assume that no denominator is equal to zero. Answer: = Negative Exponent Property
  40. 40. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>Lesson 2 CYP4 A. Simplify . Assume that no denominator is equal to zero. A. B. C. D.
  41. 41. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>Lesson 2 CYP4 A. AnsA B. AnsB C. AnsC D. AnsD B. Simplify . Assume that no denominator is equal to zero.
  42. 42. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>Lesson 2 CYP4 A. AnsA B. AnsB C. AnsC D. AnsD C. Simplify . Assume that no denominator is equal to zero.
  43. 43. Lesson 2 Ex5 Read the Test Item A ratio is a comparison of two quantities. It can be written in fraction form. Apply Properties of Exponents Refer to the figure in Example 5 on page 370 of your textbook. Write the ratio of the circumference of the circle to the area of the square in simplest form. A B C D
  44. 44. Lesson 2 Ex5 Solve the Test Item <ul><li>circumference of circle = 2  r length of square = diameter of circle or 2 r area of square = (2 r ) 2 </li></ul>Apply Properties of Exponents Quotient of Powers <ul><li>Substitute. </li></ul>
  45. 45. Lesson 2 Ex5 Answer: C Apply Properties of Exponents Simplify.
  46. 46. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>Lesson 2 CYP5 Write the ratio of the circumference of the circle to the perimeter of the square in simplest form. A. B. C. D.
  47. 47. End of Lesson 2
  48. 48. Lesson 3 Menu Five-Minute Check (over Lesson 7-2) Main Ideas and Vocabulary Example 1: Identify Polynomials Example 2: Write a Polynomial Example 3: Degree of a Polynomial Example 4: Arrange Polynomials in Ascending Order Example 5: Arrange Polynomials in Descending Order
  49. 49. Lesson 3 MI/Vocab <ul><li>polynomial </li></ul><ul><li>binomial </li></ul><ul><li>trinomial </li></ul><ul><li>degree of a monomial </li></ul><ul><li>degree of a polynomial </li></ul><ul><li>Find the degree of a polynomial. </li></ul><ul><li>Arrange the terms of a polynomial in ascending or descending order. </li></ul>
  50. 50. Lesson 3 Ex1 Identify Polynomials State whether each expression is a polynomial. If it is a polynomial, identify it as a monomial, binomial, or trinomial .
  51. 51. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>Lesson 3 CYP1 A. yes, monomial B. yes, binomial C. yes, trinomial D. none of these A. State whether 3 x 2 + 2 y + z is a polynomial. If it is a polynomial, identify it as a monomial, binomial, or trinomial .
  52. 52. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>Lesson 3 CYP1 A. yes, monomial B. yes, binomial C. yes, trinomial D. none of these B. State whether 4 a 2 – b –2 is a polynomial. If it is a polynomial, identify it as a monomial, binomial, or trinomial .
  53. 53. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>Lesson 3 CYP1 A. yes, monomial B. yes, binomial C. yes, trinomial D. none of these C. State whether 8 r – 5 s is a polynomial. If it is a polynomial, identify it as a monomial, binomial, or trinomial .
  54. 54. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>Lesson 3 CYP1 A. yes, monomial B. yes, binomial C. yes, trinomial D. none of these D. State whether 3 y 5 is a polynomial. If it is a polynomial, identify it as a monomial, binomial, or trinomial .
  55. 55. Lesson 3 Ex2 Write a Polynomial GEOMETRY Write a polynomial to represent the area of the shaded region. Words The area of the shaded region is the area of the rectangle minus the area of the triangle. Variables area of the shaded region = A height of rectangle = 2 h area of rectangle = b (2 h )
  56. 56. Lesson 3 Ex2 Write a Polynomial Area of shaded region = rectangle area – triangle area. Answer: Answer Equation
  57. 57. Lesson 3 CYP2 <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>A. 4 r 2 –  r 2 B.  r 2 C. 4 r 2 D. 4 r –  r 2 Write a polynomial to represent the area of the shaded region.
  58. 58. Lesson 3 Ex3 Degree of a Polynomial Find the degree of each polynomial. Interactive Lab: Exploring Polynomials
  59. 59. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>Lesson 3 CYP3 A. 3 B. 2 C. 0 D. 1 A. Find the degree of 11 ab + 6 b +2 ac 2 – 7.
  60. 60. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>Lesson 3 CYP3 A. 0 B. 2 C. 4 D. 3 B. Find the degree of 3 r 2 + 5 r 2 s 2 – s 3 .
  61. 61. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>Lesson 3 CYP3 A. 0 B. 2 C. 7 D. 3 C. Find the degree of 2 x 5 yz – x 2 yz 3 .
  62. 62. Lesson 3 Ex4 A. Arrange the terms of 16 + 14 x 3 + 2 x – x 2 so that the powers of x are in ascending order. 16 + 14 x 3 + 2 x – x 2 = 16 x 0 + 14 x 3 + 2 x 1 – x 2 x 0 = 1 Answer: = 16 + 2 x – x 2 + 14 x 3 0 < 1 < 2 < 3 Arrange Polynomials in Ascending Order
  63. 63. Lesson 3 Ex4 B. Arrange the terms of 7 y 2 + 4 x 3 + 2 xy 3 – x 2 y 2 so that the powers of x are in ascending order. 7 y 2 + 4 x 3 + 2 xy 3 – x 2 y 2 = 7 y 2 + 4 x 3 + 2 x 1 y 3 – x 2 y 2 x = x 1 Answer: = 7 y 2 + 2 xy 3 – x 2 y 2 + 4 x 3 0 < 1 < 2 < 3 Arrange Polynomials in Ascending Order
  64. 64. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>Lesson 3 CYP4 A. –3 x 4 – 2 x + 6 x 2 + 1 B. 1 – 2 x + 6 x 2 – 3 x 4 C. –3 x 4 + 6 x 2 – 2 x + 1 D. 1 + 6 x 2 – 2 x – 3 x 4 A. Arrange 6 x 2 – 3 x 4 – 2 x + 1 so that the powers of x are in ascending order.
  65. 65. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>Lesson 3 CYP4 A. 4 x 3 yz – x 2 + 2 xy 4 + 3 B. 2 xy 4 + 3 + 4 x 3 yz – x 2 C. 3 + 4 x 3 yz – x 2 + 2 xy 4 D. 3 + 2 xy 4 – x 2 + 4 x 3 yz B. Arrange 3 + 2 xy 4 + 4 x 3 yz – x 2 so that the powers of x are in ascending order.
  66. 66. Lesson 3 Ex5 A. Arrange 8 + 7 x 2 – 12 x y 3 – 4 x 3 y so that the powers of x are in descending order. 8 + 7 x 2 – 12 x y 3 – 4 x 3 y = 8 x 0 + 7 x 2 – 12 x 1 y 3 – 4 x 3 y x 0 = 1 and x = x 1 Answer: = – 4 x 3 y + 7 x 2 – 12 xy 3 + 8 3 > 2 > 1 > 0 Arrange Polynomials in Descending Order
  67. 67. Lesson 3 Ex5 B. Arrange a 4 + ax 2 – 2 a 3 x y 3 – 9 x 4 y so that the powers of x are in descending order. a 4 + ax 2 – 2 a 3 x y 3 – 9 x 4 y = a 4 x 0 + a 1 x 2 – 2 a 3 x 1 y 3 – 9 x 4 y 1 x 0 = 1 and x = x 1 Answer: = – 9 x 4 y + ax 2 – 2 a 3 x y 3 + a 4 4 > 2 > 1 > 0 Arrange Polynomials in Descending Order
  68. 68. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>Lesson 3 CYP5 A. 2 – x 2 + 3 x 3 + 4 x 4 B. 4 x 4 + 3 x 3 – x 2 + 2 C. – x 2 + 2 + 3 x 3 + 4 x 4 D. 4 x 4 + 3 x 3 + 2 – x 2 A. Arrange 3 x 3 + 4 x 4 – x 2 + 2 so that the powers of x are in descending order.
  69. 69. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>Lesson 3 CYP5 A. 2 y 5 – 7 y 3 x 2 – 8 x 3 y 2 + 3 x 5 B. 3 x 5 + 2 y 5 – 7 y 3 x 2 – 8 x 3 y 2 C. 3 x 5 – 8 x 3 y 2 – 7 y 3 x 2 + 2 y 5 D. –7 y 3 x 2 + 2 y 5 – 8 x 3 y 2 + 3 x 5 B. Arrange 2 y 5 – 7 y 3 x 2 – 8 x 3 y 2 + 3x 5 so that the powers of x are in descending order.
  70. 70. End of Lesson 3
  71. 71. Lesson 4 Menu Five-Minute Check (over Lesson 7-3) Main Ideas Example 1: Add Polynomials Example 2: Subtract Polynomials Example 3: Real-World Example
  72. 72. Lesson 4 MI/Vocab <ul><li>Add polynomials. </li></ul><ul><li>Subtract polynomials. </li></ul>
  73. 73. Lesson 4 Ex1 Add Polynomials Find (7 y 2 + 2 y – 3) + (2 – 4 y + 5 y 2 ). Method 1 Horizontal (7 y 2 + 2 y – 3) + (2 – 4 y + 5 y 2 ) = (7 y 2 + 5 y 2 ) + [2 y + (–4 y) + [(– 3) + 2] Group like terms. = 12 y 2 – 2y – 1 Add like terms.
  74. 74. Lesson 4 Ex1 Add Polynomials Method 2 Vertical Answer: 12 y 2 – 2 y – 1 Notice that terms are in descending order with like terms aligned. 12 y 2 – 2 y – 1 7 y 2 + 2 y – 3 (+) 5 y 2 – 4 y + 2
  75. 75. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>Lesson 4 CYP1 A. –2 x 2 + 5 x + 3 B. 8 x 2 + 6 x – 4 C. 2 x 2 + 5 x + 4 D. –15 x 2 + 6 x – 4 Find (3 x 2 + 2 x – 1) + (–5 x 2 + 3 x + 4).
  76. 76. Lesson 4 Ex2 Subtract Polynomials Find (6 y 2 + 8 y 4 – 5 y ) – (9 y 4 – 7 y + 2 y 2 ). Method 1 Horizontal Subtract 9 y 4 – 7 y +2 y 2 by adding its additive inverse. (6 y 2 + 8 y 4 – 5 y ) – (9 y 4 – 7 y + 2 y 2 ) = (6 y 2 + 8 y 4 – 5 y ) + (–9 y 4 + 7 y – 2 y 2 ) = [8 y 4 + (–9y 4 )] + [6 y 2 + (–2 y 2 )] + (–5 y + 7 y ) = – y 4 + 4 y 2 + 2 y
  77. 77. Lesson 4 Ex2 Subtract Polynomials Method 2 Vertical Align like terms in columns and subtract by adding the additive inverse. Answer: 4 y 2 – y 4 + 2 y or – y 4 + 4 y 2 + 2 y 6 y 2 + 8 y 4 – 5 y (–) 2 y 2 + 9 y 4 – 7 y Add the opposite. 6 y 2 + 8 y 4 – 5 y (+) –2 y 2 – 9 y 4 + 7 y 4 y 2 – y 4 + 2 y
  78. 78. Lesson 4 CYP2 <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>A. 2 x 2 + 7 x 3 – 3 x 4 B. x 4 – 2 x 3 + x 2 C. x 2 + 8 x 3 – 3 x 4 D. 3 x 4 + 2 x 3 + x 2 Find (3 x 3 + 2 x 2 – x 4 ) – ( x 2 + 5 x 3 – 2 x 4 ).
  79. 79. Lesson 4 Ex3 A. VIDEO GAMES The total amount of toy sales T (in billions of dollars) consists of two groups: sales of video games V and sales of traditional toys R . In recent years, the sales of traditional toys and total sales could be modeled by the following equations, where n is the number of years since 1996. R = 0.5 n 3 + 1.9 n 2 + 3 n + 19 T = 0.45 n 3 + 1.85 n 2 + 4.4 n + 22.6
  80. 80. Lesson 4 Ex3 Find an equation that models the sales of video games V . Subtract the polynomial for R from the polynomial for T . Answer: V = –0.05 n 3 + 0.05 n 2 + 1.4 n + 3.6 Total 0.5 n 3 + 1.9 n 2 – 3 n – 19 – Trad. (–)0.45 n 3 + 1.85 n 2 – 4.4 n – 22.6 Video –0.05 n 3 + 0.05 n 2 + 1.4 n + 3.6 Add the opposite. 0.5 n 3 + 1.9 n 2 – 3 n – 19 (+) –0.45 n 3 – 1.85 n 2 + 4.4 n + 22.6 – 0.05 n 3 + 0.05 n 2 + 1.4 n + 3.6
  81. 81. Lesson 4 Ex3 B. What did this equation predict for the amount of video game sales is the year 1998? Answer: The year 1998 is 1998 – 1996 or 2 years after the year 1996. If this trend continues, the number of video game sales in 1998 would have been –0.05(2) 3 + 0.05(2) 2 + 1.4(2) + 3.6 or 6.2 billion dollars.
  82. 82. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>Lesson 4 CYP3 A. 50 x 2 – 50 x + 500 B. –50 x 2 – 50 x + 500 C. 250 x 2 + 950 x + 500 D. 50 x 2 + 950 x + 100 A. BUSINESS The profit a business makes is found by subtracting the cost to produce an item C from the amount earned in sales S . The cost to produce and the sales amount could be modeled by the following equations, where x is the number of items produced. C = 100 x 2 + 500 x – 300 S = 150 x 2 + 450 x + 200 Find an equation that models the profit.
  83. 83. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>Lesson 4 CYP3 A. $500 B. $30 C. $254,000 D. $44,000 B. What does this equation predict the profit would be if 30 items were produced and sold?
  84. 84. End of Lesson 4
  85. 85. Lesson 5 Menu Five-Minute Check (over Lesson 7-4) Main Ideas Example 1: Multiply a Polynomial by a Monomial Example 2: Simplify Expressions Example 3: Real-World Example Example 4: Polynomials on Both Sides
  86. 86. Lesson 5 MI/Vocab <ul><li>Find the product of a monomial and a polynomial. </li></ul><ul><li>Solve equations involving polynomials. </li></ul>
  87. 87. Lesson 5 Ex1 Multiply a Polynomial by a Monomial Method 1 Horizontal Find 6 y (4 y 2 – 9 y – 7). 6 y (4 y 2 – 9 y – 7) = 6 y (4 y 2 ) – 6 y (9 y) – 6 y( 7) Distributive Property = 24 y 3 – 54 y 2 – 42 y Multiply.
  88. 88. Lesson 5 Ex1 Multiply a Polynomial by a Monomial Method 2 Vertical Answer: 24 y 3 – 54 y 2 – 42 y 24 y 3 – 54 y 2 – 42 y Multiply. 4 y 2 – 9 y – 7 (x) 6 y Distributive Property
  89. 89. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>Lesson 5 CYP1 A. 6 x 2 + 9 x + 15 B. 6 x 3 + 9 x 2 + 15 x C. 5 x 3 + 6 x 2 + 8 x D. 6 x 2 + 3 x + 5 Find 3 x (2 x 2 + 3 x + 5).
  90. 90. Lesson 5 Ex2 Simplify Expressions Simplify 3(2 t 2 – 4 t – 15) + 6 t (5 t + 2). 3(2 t 2 – 4 t – 15) + 6 t (5 t + 2) = 3(2 t 2 ) – 3(4 t) – 3(15) + 6 t (5 t) + 6 t (2) Distributive Property = 6 t 2 – 12 t – 45 + 30 t 2 + 12 t Product of Powers = (6 t 2 + 30 t 2 ) + [(– 12 t) + 12 t ] – 45 Commutative and Associative Properties Answer: = 36 t 2 – 45 Combine like terms.
  91. 91. Lesson 5 CYP2 <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>A. 4 y 2 + 9 y + 1 B. 8 y 2 + 5 y – 6 C. 20 y 2 + 9 y + 6 D. 28 y 2 + 31 y – 10 Simplify 5(4 y 2 + 5 y – 2) + 2 y (4 y +3).
  92. 92. Lesson 5 Ex3 A. ENTERTAINMENT Admission to the Super Fun Amusement Park is $10. Once in the park, super rides are an additional $3 each and regular rides are an additional $2. Sarita goes to the park and rides 15 rides, of which s of those 15 are super rides. Find an expression for how much money Sarita spent at the park. Words Variable If s = the number of super rides, then 15 – s is the number of regular rides. Let M be the amount of money Sarita spent at the park. Amount of money = admission + super rides  $3 per ride regular rides $2 per ride. + 
  93. 93. Lesson 5 Ex3 Equation M = 10 + s ● 3 + (15 – s ) ● 2 = 10 +3 s + 15(2) – s (2) Distributive Property = 10 + 3 s + 30 – 2 s Simplify. = 40 + s Simplify. Answer: An expression for the amount of money Sarita spent in the park is 40 + s, where s is the number of super rides she rode.
  94. 94. Lesson 5 Ex3 B. Evaluate the expression to find the cost if Sarita rode 9 super rides. 40 + s = 40 + 9 s = 9 = 49 Add. Answer: Sarita spent $49.
  95. 95. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>Lesson 5 CYP3 A. 70 p + 210 B. 120 p + 70 C. 50 p + 14,700 D. 70 p + 120 A. The Fosters own a vacation home that they rent throughout the year. The rental rate during peak season is $120 per day and the rate during the off-peak season is $70 per day. Last year they rented the house 210 days, p of which were during peak season. Find an expression for how much rent the Fosters received.
  96. 96. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>Lesson 5 CYP3 A. $120,000 B. $21,200 C. $70,000 D. $210,000 B. Evaluate the expression if p is equal to 130.
  97. 97. Lesson 5 Ex4 Solve b (12 + b ) – 7 = 2 b + b (–4 + b ). b (12 + b ) – 7 = 2 b + b (–4 + b ) Original equation 12 b + b 2 – 7 = 2 b – 4 b + b 2 Distributive Property 12 b + b 2 – 7 = –2 b + b 2 Combine like terms. 12 b – 7 = –2 b Subtract b 2 from each side. Polynomials on Both Sides
  98. 98. Lesson 5 Ex4 12 b = –2 b + 7 Add 7 to each side. Divide each side by 14. Answer: Polynomials on Both Sides 14 b = 7 Add 2 b to each side.
  99. 99. Lesson 5 Ex4 Check b (12 + b ) – 7 = 2 b + b (–4 + b ) Original equation Simplify. Polynomials on Both Sides Multiply.  Subtract.
  100. 100. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>Lesson 5 CYP4 Solve x ( x + 2) + 2 x ( x – 3) + 7 = 3 x ( x – 5) – 12. A. B. C. D.
  101. 101. End of Lesson 5
  102. 102. Lesson 6 Menu Five-Minute Check (over Lesson 7-5) Main Ideas and Vocabulary Example 1: The Distributive Property Key Concept: FOIL Method Example 2: FOIL Method Example 3: FOIL Method Example 4: The Distributive Property
  103. 103. Lesson 6 MI/Vocab <ul><li>FOIL method </li></ul><ul><li>Multiply two binomials by using the FOIL method. </li></ul><ul><li>Multiply two polynomials by using the Distributive Property. </li></ul>
  104. 104. Lesson 6 Ex1 The Distributive Property Find ( y + 8)( y – 4). Method 1 Vertical Multiply by –4. – 4 y – 32 –4( y + 8) = –4 y – 32 Multiply by y. Combine like terms. y 2 + 4 y – 32 y + 8 ( ×) y – 4 y 2 + 8 y y ( y + 8) = y 2 + 8 y y + 8 ( ×) y – 4
  105. 105. Lesson 6 Ex1 The Distributive Property Method 2 Horizontal ( y + 8 )( y – 4) = y ( y – 4) + 8 ( y –4) Distributive Property = y ( y ) – y (4) + 8 ( y ) – 8 (4) Distributive Property = y 2 – 4 y + 8 y – 32 Multiply. = y 2 + 4 y – 32 Combine like terms. Answer: y 2 + 4 y – 32
  106. 106. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>Lesson 6 CYP1 A. c 2 – 6 c + 8 B. c 2 – 4 c – 8 C. c 2 – 2 c + 8 D. c 2 – 2 c – 8 Find ( c + 2)( c – 4).
  107. 107. Key Concept 7-6a
  108. 108. Lesson 6 Ex2 FOIL Method A. Find ( z – 6)( z – 12). ( z – 6)( z – 12) = z ( z ) Answer: z 2 – 18 z + 72 ( z – 6)( z – 12) = z ( z ) + z (–12) ( z – 6)( z – 12) = z ( z ) + z (–12) + (–6) z + (–6)(–12) ( z – 6)( z – 12) = z ( z ) + z (–12) + (–6) z = z 2 – 12 z – 6 z + 72 Multiply. = z 2 – 18 z + 72 Combine like terms. F ( z – 6)( z – 12) O I L F O I L
  109. 109. Lesson 6 Ex2 FOIL Method B. Find (5 x – 4)(2 x + 8). (5 x – 4)(2 x + 8) Answer: = 10 x 2 + 32 x – 32 Combine like terms. = 10 x 2 + 40 x – 8 x – 32 Multiply. = (5 x )(2 x ) + (5 x )(8) + (–4)(2 x ) + (–4)(8) F O I L
  110. 110. Lesson 6 CYP2 <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>A. x 2 + x – 6 B. x 2 – x – 6 C. x 2 + x + 6 D. x 2 + x + 5 A. Find ( x + 2)( x – 3).
  111. 111. Lesson 6 CYP2 <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>A. 5 x 2 – 8 x + 30 B. 6 x 2 + 28 x – 1 C. 6 x 2 – 8 x – 30 D. 6 x – 30 B. Find (3 x + 5)(2 x – 6).
  112. 112. Lesson 6 Ex3 FOIL Method GEOMETRY The area A of a triangle is one half the height h times the base b . Write an expression for the area of the triangle. Explore Identify the height and the base. h = x – 7 b = 6 x + 7 Plan Now write and apply the formula. Area equals one half height times base. A = h ● b
  113. 113. Lesson 6 Ex3 FOIL Method Original formula Substitution FOIL method Multiply.
  114. 114. Lesson 6 Ex3 FOIL Method Combine like terms. Answer: The area of the triangle is 3 x 2 – 19 x – 14 square units. Distributive Property
  115. 115. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>Lesson 6 CYP3 A. 7 x + 3 units 2 B. 12 x 2 + 11 x + 2 units 2 C. 12 x 2 + 8 x + 2 units 2 D. 7 x 2 + 11 x + 3 units 2 GEOMETRY The area of a rectangle is the measure of the base times the height. Write an expression for the area of the rectangle.
  116. 116. Lesson 6 Ex4 A. Find (3 a + 4)( a 2 – 12 a + 1). (3 a + 4)( a 2 – 12 a + 1) = 3 a ( a 2 – 12 a + 1) + 4( a 2 – 12 a + 1) Distributive Property = 3 a 3 – 36 a 2 + 3 a + 4 a 2 – 48 a + 4 Distributive Property Answer: = 3 a 3 – 32 a 2 – 45 a + 4 Combine like terms. The Distributive Property
  117. 117. Lesson 6 Ex4 B. Find (2 b 2 + 7 b + 9)( b 2 + 3 b – 1) . (2 b 2 + 7 b + 9)( b 2 + 3 b – 1) = (2 b 2 )( b 2 + 3 b – 1)+ 7 b ( b 2 + 3 b – 1) + 9( b 2 + 3 b – 1) Distributive Property = (2 b 4 + 6 b 3 – 2 b 2 + 7 b 3 + 21 b 2 – 7 b + 9 b 2 + 27 b – 9) Distributive Property Answer: = 2 b 4 + 13 b 3 + 28 b 2 + 20 b – 9 Combine like terms. The Distributive Property
  118. 118. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>Lesson 6 CYP4 A. 12 z 3 + 9 z 2 + 15 z B. 8 z 2 + 6 z + 10 C. 12 z 3 + z 2 + 9 z + 10 D. 12 z 3 + 17 z 2 + 21 z + 10 A. Find (3 z + 2)(4 z 2 + 3 z + 5).
  119. 119. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>Lesson 6 CYP4 A. 12 x 4 – 9 x 3 – 6 x 2 B. 7 x 3 – x – 1 C. 12 x 4 – x 3 – 8 x 2 – 7 x – 2 D. – x 2 + 5 x + 3 B. Find (3 x 2 + 2 x + 1)(4 x 2 – 3 x – 2).
  120. 120. End of Lesson 6
  121. 121. Lesson 7 Menu Five-Minute Check (over Lesson 7-6) Main Ideas and Vocabulary Key Concept: Square of a Sum Example 1: Square of a Sum Key Concept: Square of a Difference Example 2: Square of a Difference Example 3: Real-World Example Key Concept: Product of a Sum and a Difference Example 4: Product of a Sum and a Difference
  122. 122. Lesson 7 MI/Vocab <ul><li>difference of two squares </li></ul><ul><li>Find squares of sums and differences. </li></ul><ul><li>Find the product of a sum and a difference. </li></ul>
  123. 123. Key Concept 7-7a
  124. 124. Lesson 7 Ex1 Square of a Sum Find (7 z + 2) 2 . ( a + b ) 2 = a 2 + 2 a b + b 2 ( 7 z + 2 ) 2 = ( 7 z ) 2 + 2( 7 z )( 2 ) + ( 2 ) 2 a = 7 z and b = 2 Answer: = 49 z 2 + 28 z 2 + 4 Simplify.
  125. 125. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>Lesson 7 CYP1 A. 9 x 2 + 4 B. 9 x 2 + 6 x + 4 C. 9 x + 4 D. 9 x 2 + 12 x + 4 Find (3 x + 2) 2 .
  126. 126. Key Concept 7-7b
  127. 127. Lesson 7 Ex2 Square of a Difference Find (3 c – 4) 2 . ( a – b ) 2 = a 2 – 2 a b + b 2 ( 3 c – 4 ) 2 = ( 3 c ) 2 – 2( 3 c )( 4 ) + ( 4 ) 2 a = 3 c and b = 4 Answer: = 9 c 2 – 24 c + 16 Simplify.
  128. 128. Lesson 7 CYP2 <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>A. 4 m 2 + 9 B. 4 m 2 – 9 C. 4 m 2 – 6 m + 9 D. 4 m 2 – 12 m + 9 Find (2 m – 3) 2 .
  129. 129. Lesson 7 Ex3 GEOMETRY Write an expression that represents the area of a square that has a side length of 2 x + 12 units. The formula for the area of a square is A = s 2 . Answer: The area of the square is 4 x 2 + 48 x + 144 square units. A = s 2 Area of a square A = ( 2 x + 12 ) 2 s = (2 x + 12) A = ( 2 x ) 2 + 2( 2 x )( 12 ) + ( 12 ) 2 a = 2 x and b = 12 A = 4 x 2 + 48 x + 144 Simplify.
  130. 130. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>Lesson 7 CYP3 A. 9 x 2 – 24 x + 16 units 2 B. 9 x 2 + 16 units 2 C. 9 x 2 – 16 units 2 D. 9 x 2 – 12 x + 16 units 2 GEOMETRY Write an expression that represents the area of a square that has a side length of (3 x – 4) units.
  131. 131. Key Concept 7-7c Animation: Product of a Sum and a Difference
  132. 132. Lesson 7 Ex4 Find (9 d + 4)(9 d – 4). ( a + b )( a – b ) = a 2 – b 2 ( 9 d + 4 )( 9 d – 4 ) = ( 9 d ) 2 – ( 4 ) 2 a = 9 d and b = 4 Answer: = 81 d 2 – 16 Simplify. Product of a Sum and a Difference
  133. 133. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>Lesson 7 CYP4 A. 9 y 2 + 4 B. 6 y 2 – 4 C. 6 y 2 + 4 D. 9 y 2 – 4 Find (3 y + 2)(3 y – 2).
  134. 134. End of Lesson 7
  135. 135. CR Menu Five-Minute Checks Image Bank Math Tools Animation Menu Exploring Polynomials Multiplying and Dividing Monomials Polynomials
  136. 136. 5Min Menu Lesson 7-1 (over Chapter 6) Lesson 7-2 (over Lesson 7-1) Lesson 7-3 (over Lesson 7-2) Lesson 7-4 (over Lesson 7-3) Lesson 7-5 (over Lesson 7-4) Lesson 7-6 (over Lesson 7-5) Lesson 7-7 (over Lesson 7-6)
  137. 137. IB 1 To use the images that are on the following three slides in your own presentation: 1. Exit this presentation. 2. Open a chapter presentation using a full installation of Microsoft ® PowerPoint ® in editing mode and scroll to the Image Bank slides. 3. Select an image, copy it, and paste it into your presentation.
  138. 138. IB 2
  139. 139. IB 3
  140. 140. IB 4
  141. 141. Animation Menu 7-4 Use Algebra Tiles 7-6 Multiplying Polynomials 7-7 Product of a Sum and a Difference
  142. 142. Animation 1
  143. 143. Animation 2
  144. 144. Animation 3
  145. 145. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>5Min 1-1 A. { x | x < –7} B. { x | x < 7} C. { x | x > –7} D. { x | x > 7} Solve the inequality –7 x < –9 x + 14. (over Chapter 6)
  146. 146. 5Min 1-2 <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>(over Chapter 6) A. B. C. { w | w –15} D. { w | w 15} Solve the inequality
  147. 147. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>5Min 1-3 Which of the following options shows the solution set of the inequality | 3 a – 2 | < 4, and a graph of the solution set? (over Chapter 6) A. B. C. D.
  148. 148. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>5Min 1-4 A. 5 n – 10 < 10; n < 4 B. 5 n – 10 > 10; n > 4 C. 10 – 5 n > 10; n > 4 D. 10 – 5 n < 10; n < 4 Write an inequality for the statement, and then solve. Ten less than five times a number n is greater than ten. (over Chapter 6)
  149. 149. 5Min 1-5 <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>A. 16 nickels B. 14 nickels C. 12 nickels D. 10 nickels Lori had a quarter and some nickels in her pocket, but she had less than $0.80. What is the greatest number of nickels she could have had? (over Chapter 6)
  150. 150. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>5Min 1-6 A. (3, 3) B. (–3, 3) C. (4, 5) D. (2, –3) (over Chapter 6) Which point satisfies the system of inequalities x ≤ 3, y > x, and y ≥ 3?
  151. 151. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>5Min 2-1 A. Yes; the expression involves only one variable. B. Yes; the expression is the product of a number and variables. C. No; the expression is the product of a number and variables. D. No; the expression involves more than one term. Which option states whether the expression –5 x 2 is a monomial, and provides a reasonable explanation? (over Lesson 7-1)
  152. 152. 5Min 2-2 <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>A. Yes; the expression involves variables and no numbers. B. Yes; the expression is the difference between two powers of variables. C. No; the expression does not involve numbers D. No; the expression is the difference between two powers of variables. Which option states whether the expression x 3 – y 3 is a monomial, and provides a reasonable explanation? (over Lesson 7-1)
  153. 153. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>5Min 2-3 A. –3 a 5 b 6 B. –3 a 4 b 8 C. –3 a 3 b 6 D. –3 a 4 b 6 Simplify (3 ab 4 ) × (– a 4 b 2 ). (over Lesson 7-1)
  154. 154. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>5Min 2-4 A. 2 x 10 y 8 B. 2 x 25 y 16 C. 4 x 25 y 16 D. 4 x 10 y 8 Simplify (2 x 5 y 4 ) 2 . (over Lesson 7-1)
  155. 155. 5Min 2-5 <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>A. 6 n 5 B. 6 n 3 C. 5 n 5 D. 5 n 6 Find the area of the parallelogram shown in the image. (over Lesson 7-1)
  156. 156. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>5Min 2-6 A. 2.375 B. 12.5 C. 13.5 D. 13.8 What is the value of 4 x 3 – 1 when x = 1.5? (over Lesson 7-1)
  157. 157. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>5Min 3-1 (over Lesson 7-2) A. B. C. 7 D. 49 Simplify . Assume that the denominator is not equal to zero.
  158. 158. 5Min 3-2 <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>(over Lesson 7-2) . Assume that the denominator is not equal to zero. A. B. C. D.
  159. 159. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>5Min 3-3 (over Lesson 7-2) A. B. C. D.
  160. 160. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>5Min 3-4 (over Lesson 7-2) A. B. C. D.
  161. 161. 5Min 3-5 <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>A. 2 to 1 B. 2 to 3 C. 1 to 1 D. 1 to 2 Refer to the figure. Find the ratio of the area of the square to the area of the triangle. (over Lesson 7-2)
  162. 162. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>5Min 3-6 Which expression has the least value? (over Lesson 7-2) A. B. C. D.
  163. 163. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>5Min 4-1 A. no B. yes; monomial C. yes; binomial D. yes; trinomial State whether the expression –8 is a polynomial. If the expression is a polynomial, identify it as a monomial , a binomial , or a trinomial . (over Lesson 7-3)
  164. 164. 5Min 4-2 <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>A. no B. yes; monomial C. yes; binomial D. yes; trinomial (over Lesson 7-3) State whether the expression is a polynomial. If the expression is a polynomial, identify it as a monomial , a binomial , or a trinomial .
  165. 165. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>5Min 4-3 Refer to the figure. Write a polynomial to represent the area of the shaded region. (over Lesson 7-3) A. x 2 ab B. C. D. x 2 – ab
  166. 166. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>5Min 4-4 A. 2 B. 3 C. 4 D. 5 What is the degree of the polynomial 5 ab 3 + 4 a 2 b + 3 b 5 – 2? (over Lesson 7-3)
  167. 167. 5Min 4-5 <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>A. M > N B. N > M C. M = N = 0 D. M = N = 1 If 0 < x < 1, M = x 3 – x 2 + 1, and N = x 2 – x 3 + 1, which statement is true? (over Lesson 7-3)
  168. 168. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>5Min 5-1 A. 2 a 2 – 3 a + 7 b 2 B. 2 a 2 + 3 a + 8 b 2 C. 2 a 2 – 9 a + 8 b 2 D. 2 a 2 + 3 a + 7 b 2 Simplify (6 a + 7 b 2 ) + (2 a 2 – 3 a + b 2 ). (over Lesson 7-4)
  169. 169. 5Min 5-2 <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>A. 5 x 2 – 4 x – 3 B. 5 x 2 + 4 x – 3 C. 4 x 2 + 4 x – 3 D. 4 x 2 – 4 x – 3 Simplify (5 x 2 – 3) – ( x 2 + 4 x ). (over Lesson 7-4)
  170. 170. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>5Min 5-3 A. 3 x 2 + 11 x – 10 B. 3 x 2 – 5 x – 6 C. 3 x 2 – 5 x – 10 D. 3 x 2 + 10 x – 11 Simplify (6 x 2 + 2 x – 9) – (3 x 2 – 8 x + 2) + ( x + 1). (over Lesson 7-4)
  171. 171. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>5Min 5-4 A. 5 x 2 + x + 3 B. x 2 + 3 x – 4 y – 3 C. x 2 + x + 3 D. 5 x 2 + 3 x – 2 y + 3 Refer to the figure. If P is the perimeter of the triangle and the measures of the two sides are given, find the measure of the third side of the triangle. (over Lesson 7-4)
  172. 172. 5Min 5-5 <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>A. 5 x 2 + 12 x + 9 B. 3 x 2 – 2 x + 13 C. –3 x 2 + 2 x – 9 D. –5 x 2 – 12 x + 13 Which of the following polynomials was added to x 2 + 7 x – 2 to get a sum of –4 x 2 – 5 x + 11? (over Lesson 7-4)
  173. 173. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>5Min 6-1 A. –3 w 3 – 21 w – 27 B. –3 w 3 – 21 w + 27 C. –3 w 3 + 21 w 2 – 27 w D. –3 w 3 – 21 w 2 + 27 w Find –3 w ( w 2 + 7 w – 9). (over Lesson 7-5)
  174. 174. 5Min 6-2 <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>(over Lesson 7-5) A. B. C. D. Find .
  175. 175. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>5Min 6-3 A. 15 a 2 b – 7 ab + 1 B. 15 a 3 b – 7 ab + 1 C. 15 a 3 b + 12 a 2 b + 4 ab + 2 a D. 15 a 3 b – 3 a 2 b – 4 ab + 2 a Simplify 3 ab (5 a 2 – a – 2) + 2 a ( b + 1). (over Lesson 7-5)
  176. 176. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>5Min 6-4 Solve the equation 3(2 c – 3) – 1 = –4(2 c +1) + 8 . (over Lesson 7-5) A. B. –1 C. 1 D.
  177. 177. 5Min 6-5 <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>Solve the equation 5(9 w + 2) = 3(8 w – 7) + 17 . (over Lesson 7-5) A. B. C. D.
  178. 178. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>5Min 6-6 A. 10 x ( x + 1) B. 100 x ( x + 1) C. 100 x 2 + 1 D. 10 x (10 x + 1) If x is any whole number, which of the following is an expression for the product of two consecutive multiples of 10? (over Lesson 7-5)
  179. 179. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>5Min 7-1 A. a 2 + 3 a – 18 B. a 2 – 3 a – 18 C. a 2 – 3 a D. a 2 – 18 Find ( a + 6)( a – 3). (over Lesson 7-6)
  180. 180. 5Min 7-2 <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>A. 6 w 2 + 35 B. 6 w 2 + 29 w C. 6 w 2 + 29 w + 35 D. 6 w 2 + 15 w + 49 Find (3 w + 7)(2 w + 5). (over Lesson 7-6)
  181. 181. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>5Min 7-3 A. 25 b 3 – 19 b – 6 B. 25 b 3 – 19 b + 6 C. 25 b 3 – b + 6 D. 25 b 3 + 15 b 2 – 10 b – 3 Find (5 b – 3)(5 b 2 + 3 b – 2). (over Lesson 7-6)
  182. 182. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>5Min 7-4 Write an expression to represent the area of the figure. (over Lesson 7-6) A. 3 a 3 – 9 a 2 + 2 a – 3 units 2 B. 3 a 3 – 9 a 2 + 2 a units 2 C. 6 a 3 – 9 a 2 + 2 a – 3 units 2 D. 6 a 3 – 3 units 2
  183. 183. 5Min 7-5 <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>Write an expression to represent the area of the figure. (over Lesson 7-6) A. 48 k 3 + 46 k 2 + k + 5 units 2 B. 48 k 3 + 34 k 2 – k + 5 units 2 C. 48 k 3 + 39 k 2 + k + 5 units 2 D. 48 k 3 + 34 k 2 + k + 5 units 2
  184. 184. <ul><li>A </li></ul><ul><li>B </li></ul><ul><li>C </li></ul><ul><li>D </li></ul>5Min 7-6 A. 3 B. 3 x – 5 C. 6 x + 3 D. 5 Simplify ( x + 2)( x + 2) – ( x – 1)( x – 1). (over Lesson 7-6)
  185. 185. End of Custom Shows This slide is intentionally blank.

×