Electrons and Chemical Bonding spring 2013 day 3

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  • 1. You Will Need: 1. Pencil, Text Book- Periodic Table, Colored Pencils 2. Ionic & Covalent Bonding Pgs. 1-10 (Pick-up from bookshelf last week and Monday) 3. Log #3 – update with points
  • 2. You will need 100 3 x 5 cards 1. Print out Questions & Answers hyperlinked on Learning Point • Glue, Staple or Tape Questions on the Front and Answers on the back OR • You can write out the questions & answers 2. Due at the beginning of class on Friday 3. Quiz on Friday
  • 3. Forming Sodium Chloride http://www.youtube.com/watch?v=2mzDwgyk6QM Before (pg. 233) After Questions: 1)Why does Sodium become an Ion? 2)Is it Positive or Negative? Why? 3)Why does Chlorine become an Ion? 4)Is it Positive or Negative? Why? Questions: 1)Why do Sodium and Chlorine bond? 2)What is the overall charge of the compound? 3)Does NaCl have the same characteristics as Na and Cl? 4)What are some unique characteristics of NaCl?
  • 4. Molecule Illustration Explanation Electron Dot (Color Code each element) 1. What kind of bond does Hydrogen & Oxygen make? 2. How do you know? 3. Why does one Oxygen bond with two Hydrogen atoms? http://www.youtube.com/watch?v=ulyopnxjAZ8&feature=relmfu Drawing Lewis Dot Diagram Bonds P=8 N=8 P=1 N=0 P=1 N=0
  • 5. P=8 N=8 P=1 N=0 P=1 N=0 How do we determine the type of bond in a compound? • Identify class of elements • Same class usually covalent • Opposite class usually ionic • Calculate the electronegativity factor What is ELECTRONEGATIVITY? A measure of how much an element wants an electron How do you know the electronegativity factor of an element? Look it up (see next slide) What are the determining values for each type of bond? 0-0.4 = Non-polar covalent .41-2.0 = Polar covalent >2.0 = Ionic http://www.youtube.com/watch?v=7DjsD7Hcd9U
  • 6. http://www.tutor-homework.com/Chemistry_Help/electronegativity_table/electronegativity.html ELECTRONEGATIVITY VALUES 0-0.4 = Non-polar covalent .41-2.0 = Polar covalent >2.0 = Ionic
  • 7. Let’s try a couple: P=8 N=8 P=1 N=0 P=1 N=0 H2O Calculate the electronegativity factor H = 2.2 O = 3.44 3.44 – 2.2 = 1.24 NaCl 0-0.4 = Non-polar covalent .41-2.0 = Polar covalent >2.0 = Ionic Polar Covalent Ionic Na = .93 Cl = 3.16 3.16 - .93 = 2.23
  • 8. All the Answers to your REVIEW questions are on your notes. Remember to do a REVIEW and REFLECT on all 5 pages 10 sides. This is due at the beginning of class tomorrow.
  • 9. Homework: 1)Electrons and Chemical Bonding (5 pages 10 sides – Due Tomorrow Make sure to REVIEW and REFLECT on all pages 2)STAR Cards #61-101 – on 3x5 cards – Due Friday at the beginning of class
  • 10. Homework: 1)Electrons and Chemical Bonding (5 pages 10 sides – Due Tomorrow Make sure to REVIEW and REFLECT on all pages 2)STAR Cards #61-101 – on 3x5 cards – Due Friday at the beginning of class