• Save
Sistemas
Upcoming SlideShare
Loading in...5
×
 

Sistemas

on

  • 458 views

 

Statistics

Views

Total Views
458
Views on SlideShare
458
Embed Views
0

Actions

Likes
0
Downloads
0
Comments
0

0 Embeds 0

No embeds

Accessibility

Categories

Upload Details

Uploaded via as Adobe PDF

Usage Rights

© All Rights Reserved

Report content

Flagged as inappropriate Flag as inappropriate
Flag as inappropriate

Select your reason for flagging this presentation as inappropriate.

Cancel
  • Full Name Full Name Comment goes here.
    Are you sure you want to
    Your message goes here
    Processing…
Post Comment
Edit your comment

Sistemas Sistemas Document Transcript

  • 11111110101010010001111100101110010101110010110001110100110111101000110100000101001011001010010101011001111111010101000101110100110101001100101001010101010101010001100100101010010110001101011000110101101010000101100101010011010010100101001100011010011100001101001010100011011001IP AddressingandSubnettingWorkbookVersion 1.5Student Name:
  • IP Address ClassesClass A 1 – 127 (Network 127 is reserved for loopback and internal testing)Leading bit pattern 0 00000000.00000000.00000000.00000000Class B 128 – 191 Leading bit pattern 10 10000000.00000000.00000000.00000000Class C 192 – 223 Leading bit pattern 110 11000000.00000000.00000000.00000000Class D 224 – 239 (Reserved for multicast)Class E 240 – 255 (Reserved for experimental, used for research)Private Address SpaceClass A 10.0.0.0 to 10.255.255.255Class B 172.16.0.0 to 172.31.255.255Class C 192.168.0.0 to 192.168.255.255Default Subnet MasksClass A 255.0.0.0Class B 255.255.0.0Class C 255.255.255.0Network . Host . Host . HostNetwork . Network . Host . HostNetwork . Network . Network . HostInside CoverProduced by: Robb Jonesjonesr@careertech.netFrederick County Career & Technology CenterCisco NetworkingAcademyFrederick County Public SchoolsFrederick, Maryland, USASpecial Thanks to Melvin Baker and Jim Dorschfor taking the time to check this workbook for errors,and to everyone who has sent in suggestions to improve the series.Workbooks included in the series:IPAddressing and Subnetting WorkbooksACLs - Access Lists WorkbooksVLSM Variable-Length Subnet Mask IWorkbooks
  • Binary To Decimal Conversion128 64 32 16 8 4 2 1 Answers Scratch Area1 0 0 1 0 0 1 0 1460 1 1 1 0 1 1 1 1191 1 1 1 1 1 1 11 1 0 0 0 1 0 11 1 1 1 0 1 1 00 0 0 1 0 0 1 11 0 0 0 0 0 0 10 0 1 1 0 0 0 10 1 1 1 1 0 0 01 1 1 1 0 0 0 00 0 1 1 1 0 1 10 0 0 0 0 1 1 1000110111010101001101111111110000010000001010101001111100000001111101101110000001281621466432164211191 View slide
  • Decimal To Binary Conversion128 64 32 16 8 4 2 1 = 255 Scratch Area_________________________________________ 238_________________________________________ 34_________________________________________ 123_________________________________________ 50_________________________________________ 255_________________________________________ 200_________________________________________ 10_________________________________________ 138_________________________________________ 1_________________________________________ 13_________________________________________ 250_________________________________________ 107_________________________________________ 224_________________________________________ 114_________________________________________ 192_________________________________________ 172_________________________________________ 100_________________________________________ 119_________________________________________ 57_________________________________________ 98_________________________________________ 179_________________________________________ 2238-128110-6446-3214-86-42-201 1 1 0 1 1 1 0 34-322-200 0 1 0 0 0 1 0Use all 8 bits for each problem2 View slide
  • Address Class IdentificationAddress Class10.250.1.1 _____150.10.15.0 _____192.14.2.0 _____148.17.9.1 _____193.42.1.1 _____126.8.156.0 _____220.200.23.1 _____230.230.45.58 _____177.100.18.4 _____119.18.45.0 _____249.240.80.78 _____199.155.77.56 _____117.89.56.45 _____215.45.45.0 _____199.200.15.0 _____95.0.21.90 _____33.0.0.0 _____158.98.80.0 _____219.21.56.0 _____AB3
  • Network & Host IdentificationCircle the network portionof these addresses:177.100.18.4119.18.45.0209.240.80.78199.155.77.56117.89.56.45215.45.45.0192.200.15.095.0.21.9033.0.0.0158.98.80.0217.21.56.010.250.1.1150.10.15.0192.14.2.0148.17.9.1193.42.1.1126.8.156.0220.200.23.1Circle the host portion ofthese addresses:10.15.123.50171.2.199.31198.125.87.177223.250.200.22217.45.222.45126.201.54.231191.41.35.112155.25.169.227192.15.155.2123.102.45.254148.17.9.155100.25.1.1195.0.21.9825.250.135.46171.102.77.7755.250.5.5218.155.230.1410.250.1.14
  • 5Network AddressesUsing the IP address and subnet mask shown write out the network address:188.10.18.2 _____________________________255.255.0.010.10.48.80 _____________________________255.255.255.0192.149.24.191 _____________________________255.255.255.0150.203.23.19 _____________________________255.255.0.010.10.10.10 _____________________________255.0.0.0186.13.23.110 _____________________________255.255.255.0223.69.230.250 _____________________________255.255.0.0200.120.135.15 _____________________________255.255.255.027.125.200.151 _____________________________255.0.0.0199.20.150.35 _____________________________255.255.255.0191.55.165.135 _____________________________255.255.255.028.212.250.254 _____________________________255.255.0.0188 . 10 . 0 . 010 . 10 . 48 . 0
  • Host AddressesUsing the IP address and subnet mask shown write out the host address:188.10.18.2 _____________________________255.255.0.010.10.48.80 _____________________________255.255.255.0222.49.49.11 _____________________________255.255.255.0128.23.230.19 _____________________________255.255.0.010.10.10.10 _____________________________255.0.0.0200.113.123.11 _____________________________255.255.255.0223.169.23.20 _____________________________255.255.0.0203.20.35.215 _____________________________255.255.255.0117.15.2.51 _____________________________255.0.0.0199.120.15.135 _____________________________255.255.255.0191.55.165.135 _____________________________255.255.255.048.21.25.54 _____________________________255.255.0.00 . 0 . 18 . 20 . 0 . 0 . 806
  • Default Subnet MasksWrite the correct default subnet mask for each of the following addresses:177.100.18.4 _____________________________119.18.45.0 _____________________________191.249.234.191 _____________________________223.23.223.109 _____________________________10.10.250.1 _____________________________126.123.23.1 _____________________________223.69.230.250 _____________________________192.12.35.105 _____________________________77.251.200.51 _____________________________189.210.50.1 _____________________________88.45.65.35 _____________________________128.212.250.254 _____________________________193.100.77.83 _____________________________125.125.250.1 _____________________________1.1.10.50 _____________________________220.90.130.45 _____________________________134.125.34.9 _____________________________95.250.91.99 _____________________________255 . 255 . 0 . 0255 . 0 . 0 . 07
  • ANDING WithDefault subnet masksEvery IP address must be accompanied by a subnet mask. By now you should be able to lookat an IP address and tell what class it is. Unfortunately your computer doesn’t think that way.For your computer to determine the network and subnet portion of an IP address it must“AND” the IP address with the subnet mask.Default Subnet Masks:Class A 255.0.0.0Class B 255.255.0.0Class C 255.255.255.0ANDING Equations:1 AND 1 = 11 AND 0 = 00 AND 1 = 00 AND 0 = 0Sample:What you see...IPAddress: 192 . 100 . 10 . 33What you can figure out in your head...Address Class: CNetwork Portion: 192 . 100 . 10 . 33Host Portion: 192 . 100 . 10 . 33In order for you computer to get the same information it mustAND the IP address withthe subnet mask in binary.ANDING with the default subnet mask allows your computer to figure out the networkportion of the address.1 1 0 0 0 0 0 0 . 0 1 1 0 0 1 0 0 . 0 0 0 0 1 0 1 0 . 0 0 1 0 0 0 0 11 1 1 1 1 1 1 1 . 0 1 1 1 1 1 1 1 . 1 1 1 1 1 1 1 1 . 0 0 0 0 0 0 0 01 1 0 0 0 0 0 0 . 0 1 1 0 0 1 0 0 . 0 0 0 0 1 0 1 0 . 0 0 0 0 0 0 0 0(255 . 255 . 255 . 0)(192 . 100 . 10 . 33)(192 . 100 . 10 . 0)Network HostIP Address:Default Subnet Mask:AND:8
  • ANDING WithCustom subnet masksWhen you take a single network such as 192.100.10.0 and divide it into five smaller networks(192.100.10.16, 192.100.10.32, 192.100.10.48, 192.100.10.64, 192.100.10.80) the outsideworld still sees the network as 192.100.10.0, but the internal computers and routers see fivesmaller subnetworks. Each independent of the other. This can only be accomplished by usinga custom subnet mask. Acustom subnet mask borrows bits from the host portion of theaddress to create a subnetwork address between the network and host portions of an IPaddress. In this example each range has 14 usable addresses in it. The computer must stillAND the IP address against the custom subnet mask to see what the network portion is andwhich subnetwork it belongs to.IPAddress: 192 . 100 . 10 . 0Custom Subnet Mask: 255.255.255.240Address Ranges: 192.10.10.0 to 192.100.10.15192.100.10.16 to 192.100.10.31192.100.10.32 to 192.100.10.47 (Range in the sample below)192.100.10.48 to 192.100.10.63192.100.10.64 to 192.100.10.79192.100.10.80 to 192.100.10.95192.100.10.96 to 192.100.10.111192.100.10.112 to 192.100.10.127192.100.10.128 to 192.100.10.143192.100.10.144 to 192.100.10.159192.100.10.160 to 192.100.10.175192.100.10.176 to 192.100.10.191192.100.10.192 to 192.100.10.207192.100.10.208 to 192.100.10.223192.100.10.224 to 192.100.10.239192.100.10.240 to 192.100.10.255In the next set of problems you will determine the necessary information to determine thecorrect subnet mask for a variety of IP addresses.1 1 0 0 0 0 0 0 . 0 1 1 0 0 1 0 0 . 0 0 0 0 1 0 1 0 . 0 0 1 0 0 0 0 11 1 1 1 1 1 1 1 . 0 1 1 1 1 1 1 1 . 1 1 1 1 1 1 1 1 . 1 1 1 1 0 0 0 01 1 0 0 0 0 0 0 . 0 1 1 0 0 1 0 0 . 0 0 0 0 1 0 1 0 . 0 0 1 0 0 0 0 0(255 . 255 . 255 . 240)(192 . 100 . 10 . 33)(192 . 100 . 10 . 32)Four bits borrowed from the hostportion of the address for thecustom subnet mask.TheANDING process of the four borrowed bitsshows which range of IP addresses thisparticular address will fall into.SubNetwork HostNetworkIPAddress:Custom Subnet Mask:AND:9
  • How to determine the number of subnets and thenumber of hosts per subnetTwo formulas can provide this basic information:Number of subnets = 2 (Second subnet formula: Number of subnets = 2 - 2)Number of hosts per subnet = 2 - 2Both formulas calculate the number of hosts or subnets based on the number of binary bitsused. For example if you borrow three bits from the host portion of the address use thenumber of subnets formula to determine the total number of subnets gained by borrowing thethree bits. This would be 2 or 2 x 2 x 2 = 8 subnetsTo determine the number of hosts per subnet you would take the number of binary bits used inthe host portion and apply this to the number of hosts per subnet formula If five bits are in thehost portion of the address this would be 2 or 2 x 2 x 2 x 2 x 2 = 32 hosts.When dealing with the number of hosts per subnet you have to subtract two addresses fromthe range. The first address in every range is the subnet number. The last address in everyrange is the broadcast address. These two addresses cannot be assigned to any device inthe network which is why you have to subtract two addresses to find the number of usableaddresses in each range.For example if two bits are borrowed for the network portion of the address you can easilydetermine the number of subnets and hosts per subnets using the two formulas.h3ss510195. 223 . 50 . 0 0 0 0 0 0 0 0195. 223 . 50 . 0 0 0 0 0 0 0 0195. 223 . 50 . 0 0 0 0 0 0 0 0195. 223 . 50 . 0 0 0 0 0 0 0 0195. 223 . 50 . 0 0 0 0 0 0 0 0The number of subnetscreated by borrowing 2bits is 2 or 2 x 2 = 4subnets.2The number of hosts created byleaving 6 bits is 2 - 2 or2 x 2 x 2 x 2 x 2 x 2 = 64 - 2 = 62usable hosts per subnet.6What about that second subnet formula:Number of subnets = 2 - 2In some instances the first and last subnet range of addresses are reserved. This is similar tothe first and last host addresses in each range of addreses.The first range of addresses is the zero subnet. The subnet number for the zero subnet isalso the subnet number for the classful subnet address.The last range of addresses is the broadcast subnet. The broadcast address for the lastsubnet in the broadcast subnet is the same as the classful broadcast address.s
  • 11195. 223 . 50 . 0 0 0 0 0 0 0 0195. 223 . 50 . 0 0 0 0 0 0 0 0195. 223 . 50 . 0 0 0 0 0 0 0 0195. 223 . 50 . 0 0 0 0 0 0 0 0195. 223 . 50 . 0 0 0 0 0 0 0 0195.223.50.0195.223.50.64195.223.50.128195.223.50.192195.223.50.63195.223.50.127195.223.50.191195.223.50.255(Invalid range)(Invalid range)totototo(0)(1)(2)(3)Class C Address unsubnetted:195. 223 . 50 . 0195. 223 . 50 . 0195. 223 . 50 . 0195. 223 . 50 . 0195. 223 . 50 . 0195.223.50.0 to 195.223.50.255Class C Address subnetted (2 bits borrowed):Notice that the subnet andbroadcast addresses match.Use the 2 - 2 formula and don’t use thezero and broadcast ranges if...Classful routing is usedRIP version 1 is usedThe no ip subnet zero command isconfigured on your routerUse the 2 formula and use the zero andbroadcast ranges if...Classless routing or VLSM is usedRIP version 2, EIGRP, or OSPF is usedThe ip subnet zero command isconfigured on your router (default setting)No other clues are givenWhen to use which formula to determine the number of subnetss sThe primary reason the the zero and broadcast subnets were not used had to do pirmarily withthe broadcast addresses. If you send a broadcast to 195.223.255 are you sending it to all 255addresses in the classful C address or just the 62 usable addresses in the broadcast range?The CCNA and CCENT certification exams may have questions which will require you todetermine which formula to use, and whehter or not you can use the first and last subnets. Usethe chart below to help decide.Bottom line for the CCNA exams; if a question does not give you any clues as to whether or notto allow these two subnets, assume you can use them.This workbook has you use the number of subnets = 2 formula.s
  • Custom Subnet MasksProblem 1Number of needed subnetsNumber of needed usable hostsNetwork AddressAddress classDefault subnet maskCustom subnet maskTotal number of subnetsTotal number of host addressesNumber of usable addressesNumber of bits borrowed1414192.10.10.0____________________________________________________________________________________________________________________________________________________192 . 10 . 10 . 0 0 0 0 0 0 0 0192 . 10 . 10 . 0 0 0 0 0 0 0 0192 . 10 . 10 . 0 0 0 0 0 0 0 0192 . 10 . 10 . 0 0 0 0 0 0 0 0192 . 10 . 10 . 0 0 0 0 0 0 0 0128 64 32 16 8 4 2 1 - Binary valuesNumber ofSubnets - 2 4 8 16 32 64 128 256Number of256 128 64 32 16 8 4 2 - HostsShow your work for Problem 1 in the space below.Add the binary valuenumbers to the left of the line tocreate the custom subnet mask.C255 . 255 . 255 . 0255 . 255 . 255 . 2401616144Observe the total number ofhosts.Subtract 2 for the number ofusable hosts.16-214121286432+16240
  • 13Custom Subnet MasksProblem 2Number of needed subnetsNumber of needed usable hostsNetwork AddressAddress classDefault subnet maskCustom subnet maskTotal number of subnetsTotal number of host addressesNumber of usable addressesNumber of bits borrowed100060165.100.0.0____________________________________________________________________________________________________________________________________________________165 . 100 . 0 0 0 0 0 0 0 0 . 0 0 0 0 0 0 0 0165 . 100 . 0 0 0 0 0 0 0 0 . 0 0 0 0 0 0 0 0165 . 100 . 0 0 0 0 0 0 0 0 . 0 0 0 0 0 0 0 0165 . 100 . 0 0 0 0 0 0 0 0 . 0 0 0 0 0 0 0 0165 . 100 . 0 0 0 0 0 0 0 0 . 0 0 0 0 0 0 0 0128 64 32 16 8 4 2 1Number ofSubnets - 2 4 8 16 32 64 128 256.. 256 128 64 32 16 8 4 2Show your work for Problem 2 in the space below.Add the binary valuenumbers to the left of the line tocreate the custom subnet mask.B255 . 255 . 0 . 0255 . 255 . 255 . 1921,024646210Observe the total number ofhosts.Subtract 2 for the number ofusable hosts.64-262128643216842+1255128 64 32 16 8 4 2 1 .....512Binary values -Number ofHosts -128+64192102420484,0968,19216,38432,76865,5365121,0242,0484,0968,19216,38432,76865,536
  • Custom Subnet MasksProblem 3Network AddressAddress classDefault subnet maskCustom subnet maskTotal number of subnetsTotal number of host addressesNumber of usable addressesNumber of bits borrowed148.75.0.0 /26____________________________________________________________________________________________________________________________________________________Show your work for Problem 3 in the space below.B255 . 255 . 0 . 0255 . 255 . 255 . 1921,024646210/26 indicates the total number ofbits used for the network andsubnetwork portion of theaddress. All bits remaining belongto the host portion of the address.148 . 75 . 0 0 0 0 0 0 0 0 . 0 0 0 0 0 0 0 0148 . 75 . 0 0 0 0 0 0 0 0 . 0 0 0 0 0 0 0 0148 . 75 . 0 0 0 0 0 0 0 0 . 0 0 0 0 0 0 0 0148 . 75 . 0 0 0 0 0 0 0 0 . 0 0 0 0 0 0 0 0148 . 75 . 0 0 0 0 0 0 0 0 . 0 0 0 0 0 0 0 0128 64 32 16 8 4 2 1Number ofSubnets - 2 4 8 16 32 64 128 256.. 256 128 64 32 16 8 4 2Add the binary valuenumbers to the left of the line tocreate the custom subnet mask.1024-21,022Observe the total number ofhosts.Subtract 2 for the number ofusable hosts.64-262Subtract 2 for the total number ofsubnets to get the usable number ofsubnets.128643216842+1255128 64 32 16 8 4 2 1 .....512Binary values -Number ofHosts -128+64192102420484,0968,19216,38432,76865,5365121,0242,0484,0968,19216,38432,76865,53614
  • Custom Subnet MasksProblem 4Number of needed subnetsNumber of needed usable hostsNetwork AddressAddress classDefault subnet maskCustom subnet maskTotal number of subnetsTotal number of host addressesNumber of usable addressesNumber of bits borrowed630210.100.56.0_________________________________________________________________________________________________________________________________________________210 . 100 . 56 . 0 0 0 0 0 0 0 0210 . 100 . 56 . 0 0 0 0 0 0 0 0210 . 100 . 56 . 0 0 0 0 0 0 0 0210 . 100 . 56 . 0 0 0 0 0 0 0 0210 . 100 . 56 . 0 0 0 0 0 0 0 0128 64 32 16 8 4 2 1 - Binary valuesNumber ofSubnets - 2 4 8 16 32 64 128 256Number of256 128 64 32 16 8 4 2 - HostsShow your work for Problem 4 in the space below.15
  • 16Custom Subnet MasksProblem 5Number of needed subnetsNumber of needed usable hostsNetwork AddressAddress classDefault subnet maskCustom subnet maskTotal number of subnetsTotal number of host addressesNumber of usable addressesNumber of bits borrowed630195.85.8.0_________________________________________________________________________________________________________________________________________________195 . 85 . 8 . 0 0 0 0 0 0 0 0195 . 85 . 8 . 0 0 0 0 0 0 0 0195 . 85 . 8 . 0 0 0 0 0 0 0 0195 . 85 . 8 . 0 0 0 0 0 0 0 0195 . 85 . 8 . 0 0 0 0 0 0 0 0128 64 32 16 8 4 2 1 - Binary valuesNumber ofSubnets - 2 4 8 16 32 64 128 256Number of256 128 64 32 16 8 4 2 - HostsShow your work for Problem 5 in the space below.
  • 17Custom Subnet MasksProblem 6Number of needed subnetsNumber of needed usable hostsNetwork AddressAddress classDefault subnet maskCustom subnet maskTotal number of subnetsTotal number of host addressesNumber of usable addressesNumber of bits borrowed126131,070118.0.0.0_________________________________________________________________________________________________________________________________________________Show your work for Problem 6 in the space below.118. 0 0 0 0 0 0 0 0 . 0 0 0 0 0 0 0 0 . 0 0 0 0 0 0 0 0118. 0 0 0 0 0 0 0 0 . 0 0 0 0 0 0 0 0 . 0 0 0 0 0 0 0 0118. 0 0 0 0 0 0 0 0 . 0 0 0 0 0 0 0 0 . 0 0 0 0 0 0 0 0118. 0 0 0 0 0 0 0 0 . 0 0 0 0 0 0 0 0 . 0 0 0 0 0 0 0 0118. 0 0 0 0 0 0 0 0 . 0 0 0 0 0 0 0 0 . 0 0 0 0 0 0 0 0Number ofSubnets - 2 4 8 16 32 64 128 256 .. 256 128 64 32 16 8 4 2Binary values -128 64 32 16 8 4 2 1 ..... 128 64 32 16 8 4 2 1 ..... 128 64 32 16 8 4 2 1Number ofHosts-5121,0242,0484,0968,19216,38432,76865,536131,072262,144524,2881,048,5762,097,1524,194,304.5121,0242,0484,0968,19216,38432,76865,536131,072262,144524,2881,048,5762,097,1524,194,304
  • 18Custom Subnet MasksProblem 7Number of needed subnetsNumber of needed usable hostsNetwork AddressAddress classDefault subnet maskCustom subnet maskTotal number of subnetsTotal number of host addressesNumber of usable addressesNumber of bits borrowed200015178.100.0.0____________________________________________________________________________________________________________________________________________________Show your work for Problem 7 in the space below.178 . 100 . 0 0 0 0 0 0 0 0 . 0 0 0 0 0 0 0 0178 . 100 . 0 0 0 0 0 0 0 0 . 0 0 0 0 0 0 0 0178 . 100 . 0 0 0 0 0 0 0 0 . 0 0 0 0 0 0 0 0178 . 100 . 0 0 0 0 0 0 0 0 . 0 0 0 0 0 0 0 0178 . 100 . 0 0 0 0 0 0 0 0 . 0 0 0 0 0 0 0 0128 64 32 16 8 4 2 1Number ofSubnets - 2 4 8 16 32 64 128 256.. 256 128 64 32 16 8 4 2128 64 32 16 8 4 2 1 .....512Binary values -Number ofHosts -102420484,0968,19216,38432,76865,5365121,0242,0484,0968,19216,38432,76865,536
  • 19Custom Subnet MasksProblem 8Number of needed subnetsNumber of needed usable hostsNetwork AddressAddress classDefault subnet maskCustom subnet maskTotal number of subnetsTotal number of host addressesNumber of usable addressesNumber of bits borrowed345200.175.14.0_________________________________________________________________________________________________________________________________________________Show your work for Problem 8 in the space below.
  • Custom Subnet MasksProblem 9Number of needed subnetsNumber of needed usable hostsNetwork AddressAddress classDefault subnet maskCustom subnet maskTotal number of subnetsTotal number of host addressesNumber of usable addressesNumber of bits borrowed601,000128.77.0.0_________________________________________________________________________________________________________________________________________________Show your work for Problem 9 in the space below.20
  • Custom Subnet MasksProblem 10Number of needed usable hostsNetwork AddressAddress classDefault subnet maskCustom subnet maskTotal number of subnetsTotal number of host addressesNumber of usable addressesNumber of bits borrowed60198.100.10.0_________________________________________________________________________________________________________________________________________________Show your work for Problem 10 in the space below.21
  • Custom Subnet MasksProblem 11Number of needed subnetsNetwork AddressAddress classDefault subnet maskCustom subnet maskTotal number of subnetsTotal number of host addressesNumber of usable addressesNumber of bits borrowed250101.0.0.0_________________________________________________________________________________________________________________________________________________Show your work for Problem 11 in the space below.22
  • Custom Subnet MasksProblem 12Number of needed subnetsNetwork AddressAddress classDefault subnet maskCustom subnet maskTotal number of subnetsTotal number of host addressesNumber of usable addressesNumber of bits borrowed5218.35.50.0_________________________________________________________________________________________________________________________________________________Show your work for Problem 12 in the space below.23
  • Custom Subnet MasksProblem 13Number of needed usable hostsNetwork AddressAddress classDefault subnet maskCustom subnet maskTotal number of subnetsTotal number of host addressesNumber of usable addressesNumber of bits borrowed25218.35.50.0_________________________________________________________________________________________________________________________________________________Show your work for Problem 13 in the space below.24
  • Custom Subnet MasksProblem 14Number of needed subnetsNetwork AddressAddress classDefault subnet maskCustom subnet maskTotal number of subnetsTotal number of host addressesNumber of usable addressesNumber of bits borrowed10172.59.0.0_________________________________________________________________________________________________________________________________________________Show your work for Problem 14 in the space below.25
  • Custom Subnet MasksProblem 15Number of needed usable hostsNetwork AddressAddress classDefault subnet maskCustom subnet maskTotal number of subnetsTotal number of host addressesNumber of usable addressesNumber of bits borrowed50172.59.0.0_________________________________________________________________________________________________________________________________________________Show your work for Problem 15 in the space below.26
  • Custom Subnet MasksProblem 16Number of needed usable hostsNetwork AddressAddress classDefault subnet maskCustom subnet maskTotal number of subnetsTotal number of host addressesNumber of usable addressesNumber of bits borrowed2923.0.0.0_________________________________________________________________________________________________________________________________________________Show your work for Problem 16 in the space below.27
  • _____________________________________________________________________________________________________________________________________192.10.10.48 to 192.10.10.63192 . 10 . 10 . 112192 . 10 . 10 . 207192.10.10.129 to 192.10.10.14228SubnettingProblem 1Number of needed subnetsNumber of needed usable hostsNetwork AddressAddress classDefault subnet maskCustom subnet maskTotal number of subnetsTotal number of host addressesNumber of usable addressesNumber of bits borrowed1414192.10.10.0____________________________________________________________________________________________________________________________________________________C255 . 255 . 255 . 0255 . 255 . 255 . 2401616144What is the 4thsubnet range?What is the subnet numberfor the 8th subnet?What is the subnetbroadcast address forthe 13th subnet?What are the assignableaddresses for the 9thsubnet?
  • Show your work for Problem 1 in the space below.192.10.10.0 to 192.10.10.15192.10.10.16 to 192.10.10.31192.10.10.32 to 192.10.10.47192.10.10.48 to 192.10.10.63192.10.10.64 to 192.10.10.79192.10.10.80 to 192.10.10.95192.10.10.96 to 192.10.10.111192.10.10.112 to 192.10.10.127192.10.10.128 to 192.10.10.143192.10.10.144 to 192.10.10.159192.10.10.160 to 192.10.10.175192.10.10.176 to 192.10.10.191192.10.10.192 to 192.10.10.207192.10.10.208 to 192.10.10.223192.10.10.224 to 192.10.10.239192.10.10.240 to 192.10.10.255192. 10 . 10 . 0 0 0 0 0 0 0 0192. 10 . 10 . 0 0 0 0 0 0 0 0192. 10 . 10 . 0 0 0 0 0 0 0 0192. 10 . 10 . 0 0 0 0 0 0 0 0192. 10 . 10 . 0 0 0 0 0 0 0 0128 64 32 16 8 4 2 1 - Binary valuesNumber ofSubnets - 2 4 8 162 4 8 162 4 8 162 4 8 162 4 8 16 32 64 128 256Number of256 128 64 32 16 8 4 2 - Hosts16-21416-2141286432+16240The binary value of the last bit borrowed is the range. In thisproblem the range is 16.The first address in each subnet range is the subnet number.The last address in each subnet range is the subnet broadcastaddress.Custom subnetmaskUsable hostsUsable subnets290101010101010101001100110011001100001111000011110000000011111111(0)(1)(2)(3)(4)(5)(6)(7)(8)(9)(10)(11)(12)(13)(14)(15)
  • _____________________________________________________________________________________________________________________________________165.100.3.128 to 165.100.3.191165 . 100 . 1 . 64165 . 100 . 1 . 127165.100.2.1 to 165.100.0.6230SubnettingProblem 2Number of needed subnetsNumber of needed usable hostsNetwork AddressAddress classDefault subnet maskCustom subnet maskTotal number of subnetsTotal number of host addressesNumber of usable addressesNumber of bits borrowed100060165.100.0.0____________________________________________________________________________________________________________________________________________________B255 . 255 . 0 . 0255 . 255 . 255 . 1921,024646210What is the 15thsubnet range?What is the subnet numberfor the 6th subnet?What is the subnetbroadcast address forthe 6th subnet?What are the assignableaddresses for the 9thsubnet?
  • 165.100.00000000.00000000165.100.00000000.00000000165.100.00000000.00000000165.100.00000000.00000000165.100.00000000.00000000165.100.0.0to165.100.0.63165.100.0.64to165.100.0.127165.100.0.128to165.100.0.191165.100.0.192to165.100.0.255165.100.1.0to165.100.1.63165.100.1.64to165.100.1.127165.100.1.128to165.100.1.191165.100.1.192to165.100.1.255165.100.2.0to165.100.0.63165.100.2.64to165.100.0.127165.100.2.128to165.100.0.191165.100.2.192to165.100.0.255165.100.3.0to165.100.3.63165.100.3.64to165.100.3.127165.100.3.128to165.100.3.191165.100.3.192to165.100.3.255Downto165.100.255.128to165.100.255.191165.100.255.192to165.100.255.255Thebinaryvalueofthelastbitborrowedistherange.Inthisproblemtherangeis64.Thefirstaddressineachsubnetrangeisthesubnetnumber.Thelastaddressineachsubnetrangeisthesubnetbroadcastaddress.3164-262Usablehosts128643216842+1255128+64192CustomsubnetmaskShow your work for Problem 2 in the space below.1286432168421NumberofSubnets-248163264128256..2561286432168421286432168421.....512Binaryvalues-NumberofHosts-102420484,0968,19216,38432,76865,5365121,0242,0484,0968,19216,38432,76865,5360101010101010101011100110011001111111100001111111111111111...............(0)(1)(2)(3)(4)(5)(6)(7)(8)(9)(10)(11)(12)(13)(14)(15)111111111111(1022)(1023)
  • _____________________________________________________________________________________________________________________________________32SubnettingProblem 3Number of needed subnetsNetwork AddressAddress classDefault subnet maskCustom subnet maskTotal number of subnetsTotal number of host addressesNumber of usable addressesNumber of bits borrowed2195.223.50.0____________________________________________________________________________________________________________________________________________________What is the 3rdsubnet range?What is the subnet numberfor the 2nd subnet?What is the subnetbroadcast address forthe 1st subnet?What are the assignableaddresses for the 3rdsubnet?
  • Show your work for Problem 3 in the space below.33128 64 32 16 8 4 2 1 - Binary valuesNumber ofSubnets - 2 4 8 162 4 8 162 4 8 162 4 8 162 4 8 16 32 64 128 256Number of256 128 64 32 16 8 4 2 - Hosts195. 223 . 50 . 0 0 0 0 0 0 0 0195. 223 . 50 . 0 0 0 0 0 0 0 0195. 223 . 50 . 0 0 0 0 0 0 0 0195. 223 . 50 . 0 0 0 0 0 0 0 0195. 223 . 50 . 0 0 0 0 0 0 0 0
  • _____________________________________________________________________________________________________________________________________34SubnettingProblem 4Number of needed subnetsNetwork AddressAddress classDefault subnet maskCustom subnet maskTotal number of subnetsTotal number of host addressesNumber of usable addressesNumber of bits borrowed750190.35.0.0____________________________________________________________________________________________________________________________________________________What is the 15thsubnet range?What is the subnet numberfor the 13th subnet?What is the subnetbroadcast address forthe 10th subnet?What are the assignableaddresses for the 6thsubnet?
  • Show your work for Problem 4 in the space below.35
  • _____________________________________________________________________________________________________________________________________36SubnettingProblem 5Number of needed usable hostsNetwork AddressAddress classDefault subnet maskCustom subnet maskTotal number of subnetsTotal number of host addressesNumber of usable addressesNumber of bits borrowed6126.0.0.0_________________________________________________________________________________________________________________________________________________What is the 2ndsubnet range?What is the subnet numberfor the 5th subnet?What is the subnetbroadcast address forthe 7th subnet?What are the assignableaddresses for the 10thsubnet?
  • Show your work for Problem 5 in the space below.37
  • _____________________________________________________________________________________________________________________________________38SubnettingProblem 6Number of needed subnetsNetwork AddressAddress classDefault subnet maskCustom subnet maskTotal number of subnetsTotal number of host addressesNumber of usable addressesNumber of bits borrowed10192.70.10.0____________________________________________________________________________________________________________________________________________________What is the 9thsubnet range?What is the subnet numberfor the 4th subnet?What is the subnetbroadcast address forthe 12th subnet?What are the assignableaddresses for the 10thsubnet?
  • Show your work for Problem 6 in the space below.39
  • 40SubnettingProblem 7Network AddressAddress classDefault subnet maskCustom subnet maskTotal number of subnetsTotal number of host addressesNumber of usable addressesNumber of bits borrowed10.0.0.0 /16____________________________________________________________________________________________________________________________________________________What is the 11thsubnet range?What is the subnet numberfor the 6th subnet?What is the subnetbroadcast address forthe 2nd subnet?What are the assignableaddresses for the 9thsubnet?_____________________________________________________________________________________________________________________________________
  • Show your work for Problem 7 in the space below.41
  • _____________________________________________________________________________________________________________________________________42SubnettingProblem 8Number of needed subnetsNetwork AddressAddress classDefault subnet maskCustom subnet maskTotal number of subnetsTotal number of host addressesNumber of usable addressesNumber of bits borrowed5172.50.0.0____________________________________________________________________________________________________________________________________________________What is the 4thsubnet range?What is the subnet numberfor the 5th subnet?What is the subnetbroadcast address forthe 6th subnet?What are the assignableaddresses for the 3rdsubnet?
  • Show your work for Problem 8 in the space below.43
  • _____________________________________________________________________________________________________________________________________44SubnettingProblem 9Number of needed usable hostsNetwork AddressAddress classDefault subnet maskCustom subnet maskTotal number of subnetsTotal number of host addressesNumber of usable addressesNumber of bits borrowed28172.50.0.0____________________________________________________________________________________________________________________________________________________What is the 2ndsubnet range?What is the subnet numberfor the 10th subnet?What is the subnet broadcastaddress forthe 4th subnet?What are the assignableaddresses for the 6thsubnet?
  • Show your work for Problem 9 in the space below.45
  • _____________________________________________________________________________________________________________________________________46SubnettingProblem 10Number of needed subnetsNetwork AddressAddress classDefault subnet maskCustom subnet maskTotal number of subnetsTotal number of host addressesNumber of usable addressesNumber of bits borrowed45220.100.100.0____________________________________________________________________________________________________________________________________________________What is the 5thsubnet range?What is the subnet numberfor the 4th subnet?What is the subnetbroadcast address forthe 13th subnet?What are the assignableaddresses for the 12thsubnet?
  • Show your work for Problem 10 in the space below.47
  • _____________________________________________________________________________________________________________________________________48SubnettingProblem 11Number of needed usable hostsNetwork AddressAddress classDefault subnet maskCustom subnet maskTotal number of subnetsTotal number of host addressesNumber of usable addressesNumber of bits borrowed8,000135.70.0.0____________________________________________________________________________________________________________________________________________________What is the 6thsubnet range?What is the subnet numberfor the 7th subnet?What is the subnetbroadcast address forthe 3rd subnet?What are the assignableaddresses for the 5thsubnet?
  • Show your work for Problem 11 in the space below.49
  • _____________________________________________________________________________________________________________________________________50SubnettingProblem 12Number of needed usable hostsNetwork AddressAddress classDefault subnet maskCustom subnet maskTotal number of subnetsTotal number of host addressesNumber of usable addressesNumber of bits borrowed45198.125.50.0____________________________________________________________________________________________________________________________________________________What is the 2ndsubnet range?What is the subnet numberfor the 2nd subnet?What is the subnetbroadcast address forthe 4th subnet?What are the assignableaddresses for the 3rdsubnet?
  • Show your work for Problem 12 in the space below.51
  • _____________________________________________________________________________________________________________________________________52SubnettingProblem 13Network AddressAddress classDefault subnet maskCustom subnet maskTotal number of subnetsTotal number of host addressesNumber of usable addressesNumber of bits borrowed165.200.0.0 /26____________________________________________________________________________________________________________________________________________________What is the 10thsubnet range?What is the subnet numberfor the 11th subnet?What is the subnetbroadcast address forthe 1023rd subnet?What are the assignableaddresses for the 1022ndsubnet?
  • Show your work for Problem 13 in the space below.53
  • _____________________________________________________________________________________________________________________________________54SubnettingProblem 14Number of needed usable hostsNetwork AddressAddress classDefault subnet maskCustom subnet maskTotal number of subnetsTotal number of host addressesNumber of usable addressesNumber of bits borrowed16200.10.10.0____________________________________________________________________________________________________________________________________________________What is the 7thsubnet range?What is the subnet numberfor the 5th subnet?What is the subnetbroadcast address forthe 4th subnet?What are the assignableaddresses for the 6thsubnet?
  • Show your work for Problem 14 in the space below.55
  • 56SubnettingProblem 15Network AddressAddress classDefault subnet maskCustom subnet maskTotal number of subnetsTotal number of host addressesNumber of usable addressesNumber of bits borrowed93.0.0.0 19____________________________________________________________________________________________________________________________________________________What is the 15thsubnet range?What is the subnet numberfor the 9th subnet?What is the subnetbroadcast address forthe 7th subnet?What are the assignableaddresses for the 12thsubnet?_____________________________________________________________________________________________________________________________________
  • Show your work for Problem 15 in the space below.57
  • 58Practical Subnetting 1F0/1F0/0S0/0/0 S0/0/1Router ARouter BBased on the information in the graphic shown, design a network addressing scheme that willsupply the minimum number of subnets, and allow enough extra subnets and hosts for100% growth in both areas. Circle each subnet on the graphic and answer the questionsbelow.Marketing24 HostsManagement15 HostsF0/0Reasearch60 HostsAddress classCustom subnet maskMinimum number of subnets neededExtra subnets required for 100% growthTotal number of subnets neededNumber of host addressesin the largest subnet groupNumber of addresses needed for100% growth in the largest subnetTotal number of addressneeded for the largest subnetIP address range for ResearchIP address range for MarketingIP address range for ManagementIP address range for Router Ato Router B serial connectionIP Address 172.16.0.0____________________________________________________________________________________________________________________________________________________________________________________________________________________________________(Round up to the next whole number)(Round up to the next whole number)Start with the first subnet and arrange your sub-networks from the largest group to the smallest.B255.255.224.04486060120++==172.16.0.0 to 172.31.255172.16.32.0 to 172.63.255172.16.64.0 to 172.95.255172.16.96.0 to 172.127.255
  • 59Show your work for Practical Subnetting 1 in the space below.172.16.00000000.00000000172.16.00000000.00000000172.16.00000000.00000000172.16.00000000.00000000172.16.00000000.000000001286432168421NumberofSubnets-248163264128256..2561286432168421286432168421.....512Binaryvalues-NumberofHosts-102420484,0968,19216,38432,76865,5365121,0242,0484,0968,19216,38432,76865,536010101011100111111172.16.0.0172.16.32.0172.16.64.0172.16.96.0172.16.128.0172.16.160.0172.16.192.0172.16.224.0totototototototo172.16.31.255172.16.63.255172.16.95.255172.16.127.255172.16.159.255172.16.191.255172.16.223.255172.16.255.255(0)(1)(2)(3)(4)(5)(6)(7)60x1.0604x1.04
  • 60Practical Subnetting 2F0/0S0/0/0S0/0/1Router ABased on the information in the graphic shown, design a network addressing scheme that willsupply the minimum number of hosts per subnet, and allow enough extra subnets andhosts for 30% growth in all areas. Circle each subnet on the graphic and answer the questionsbelow.Science Lab10 HostsTech Ed Lab20 HostsF0/0Address classCustom subnet maskMinimum number of subnets neededExtra subnets required for 30% growthTotal number of subnets neededNumber of host addressesin the largest subnet groupNumber of addresses needed for30% growth in the largest subnetTotal number of addressneeded for the largest subnetIP address range for Tech EdIP address range for EnglishIP address range for ScienceIP address range for Router Ato Router B serial connectionIP address range for Router Ato Router B serial connectionIP Address 135.126.0.0_________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________(Round up to the next whole number)(Round up to the next whole number)Router BS0/0/1Router CEnglish Department15 HostsF0/1F0/1S0/0/0Start with the first subnet and arrange your sub-networks from the largest group to the smallest.++==52720626B255.255.255.224135.126.0.0 to 135.126.0.31135.126.0.32 to 135.126.0.63135.126.0.64 to 135.126.0.95135.126.0.96 to 135.126.0.127135.126.0.128 to 135.126.0.159
  • 61Show your work for Problem 2 in the space below.135.126.00000000.00000000135.126.00000000.00000000135.126.00000000.00000000135.126.00000000.00000000135.126.00000000.000000001286432168421NumberofSubnets-248163264128256..2561286432168421286432168421.....512Binaryvalues-NumberofHosts-102420484,0968,19216,38432,76865,5365121,0242,0484,0968,19216,38432,76865,53601010101010101011100110011001111110000111111111111.........135.126.0.0135.126.0.32135.126.0.64135.126.0.96135.126.0.128135.126.0.160135.126.0.192135.126.0.224135.126.1.0135.126.1.32135.126.1.64135.126.1.96135.126.1.128135.126.1.160135.126.1.192135.1261.224totototototototototototototototo135.126.0.31135.126.0.63135.126.0.95135.126.0.127135.126.0.159135.126.0.191135.126.0.223135.126.0.255135.126.1.31135.126.1.63135.126.1.95135.126.1.127135.126.1.159135.126.1.191135.126.1.223135.126.1.255(0)(1)(2)(3)(4)(5)(6)(7)(8)(9)(10)(11)(12)(13)(14)(15)5x.31.5(Roundupto2)20x.36
  • 62Practical Subnetting 3Based on the information in the graphic shown, design a classfull network addressing schemethat will supply the minimum number of hosts per subnet, and allow enough extra subnetsand hosts for 25% growth in all areas. Circle each subnet on the graphic and answer thequestions below.Address classCustom subnet maskMinimum number of subnets neededExtra subnets required for 25% growthTotal number of subnets neededNumber of host addressesin the largest subnet groupNumber of addresses needed for25% growth in the largest subnetTotal number of addressneeded for the largest subnetIP address range for SalesIP address range for MarketingIP address range for AdministrativeIP address range for Router Ato Router B serial connection____________________________________________________________________________________________________________________________________________________________________________________________________________________________________(Round up to the next whole number)(Round up to the next whole number)Start with the first subnet and arrange your sub-networks from the largest group to the smallest.++==F0/0Administrative30 HostsSales185 HostsF0/0IP Address 172.16.0.0S0/0/1Marketing50 HostsF0/1 S0/0/0Router ARouter B
  • 63Show your work for Problem 3 in the space below.
  • 64Practical Subnetting 4F0/0 S0/0/0S0/0/1Router ABased on the information in the graphic shown, design a network addressing scheme that willsupply the minimum number of subnets, and allow enough extra subnets and hosts for 70%growth in all areas. Circle each subnet on the graphic and answer the questions below.Dallas150 Hosts New York325 HostsF0/0Address classCustom subnet maskMinimum number of subnets neededExtra subnets required for 70% growthTotal number of subnets neededNumber of host addressesin the largest subnet groupNumber of addresses needed for70% growth in the largest subnetTotal number of addressneeded for the largest subnetIP address range for New YorkIP address range for Washington D. C.IP address range for DallasIP address range for Router Ato Router B serial connectionIP address range for Router Ato Router C serial connectionIP Address 135.126.0.0_________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________(Round up to the next whole number)(Round up to the next whole number)Router BS0/0/1Router C F0/0F0/1S0/0/0Start with the first subnet and arrange your sub-networks from the largest group to the smallest.++==Washington D.C.220 Hosts
  • 65Show your work for Problem 4 in the space below.
  • 66Practical Subnetting 5Based on the information in the graphic shown, design a network addressing scheme that willsupply the minimum number of hosts per subnet, and allow enough extra subnets andhosts for 100% growth in all areas. Circle each subnet on the graphic and answer thequestions below.Address classCustom subnet maskMinimum number of subnets neededExtra subnets required for 100% growthTotal number of subnets neededNumber of host addressesin the largest subnet groupNumber of addresses needed for100% growth in the largest subnetTotal number of addressneeded for the largest subnetIP address range for Router F0/0 PortIP address range for Router F0/1 Port__________________________________________________________________________________________________________________________________________________________________________(Round up to the next whole number)(Round up to the next whole number)Start with the first subnet and arrange your sub-networks from the largest group to the smallest.++==F0/0Science Room10 HostsTech Ed Lab18 HostsEnglish classroom15 HostsF0/1Art Classroom12 HostsIP Address 210.15.10.0
  • 67Show your work for Problem 5 in the space below.
  • 68Practical Subnetting 6Based on the information in the graphic shown, design a network addressing scheme that willsupply the minimum number of subnets, and allow enough extra subnets and hosts for 20%growth in all areas. Circle each subnet on the graphic and answer the questions below.Address classCustom subnet maskMinimum number of subnets neededExtra subnets required for 20% growthTotal number of subnets neededIP address range for TechnologyIP address range for ScienceIP address range for Arts & DramaIP Address range AdministrationIP address range for Router Ato Router B serial connectionIP address range for Router Ato Router C serial connectionIP address range for Router Bto Router C serial connectionIP Address 10.0.0.0________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________(Round up to the next whole number)Start with the first subnet and arrange your sub-networks from the largest group to the smallest.+=F0/0S0/0/1Router AAdministration35 HostsTechnologyBuilding320 HostsF0/0Router BS0/0/1Router CF0/1F0/1S0/0/0Science Building225 HostsS0/0/0S0/0/1S0/0/0Art & Drama75 Hosts
  • 69Show your work for Problem 6 in the space below.
  • 70Practical Subnetting 7Based on the information in the graphic shown, design a network addressing scheme that willsupply the minimum number of hosts per subnet, and allow enough extra subnets andhosts for 125% growth in all areas. Circle each subnet on the graphic and answer thequestions below.Address classCustom subnet maskMinimum number of subnets neededExtra subnets required for 125% growthTotal number of subnets neededNumber of host addressesin the largest subnet groupNumber of addresses needed for125% growth in the largest subnetTotal number of addressneeded for the largest subnetIP address range for Router A Port F0/0IP address range for ResearchIP address range for DeploymentIP address range for Router Ato Router B serial connection____________________________________________________________________________________________________________________________________________________________________________________________________________________________________(Round up to the next whole number)(Round up to the next whole number)Start with the first subnet and arrange your sub-networks from the largest group to the smallest.++==Marketing75 HostsIP Address 177.135.0.0Administration33 Hosts Sales255 HostsResearch135 HostsF0/0S0/0/0 F0/0F0/1S0/0/0Router ARouter BDeployment63 Hosts
  • 71Show your work for Problem 7 in the space below.
  • 72Practical Subnetting 8F0/0 S0/0/0S0/0/1Router ABased on the information in the graphic shown, design a network addressing scheme that willsupply the minimum number subnets, and allow enough extra subnets and hosts for 85%growth in all areas. Circle each subnet on the graphic and answer the questions below.New York8 HostsF0/0Address classCustom subnet maskMinimum number of subnets neededExtra subnets required for 85% growthTotal number of subnets neededNumber of host addressesin the largest subnet groupNumber of addresses needed for85% growth in the largest subnetTotal number of addressneeded for the largest subnetIP address range for Router A F0/0IP address range for New YorkIP address range for Router Ato Router B serial connectionIP Address 192.168.1.0_______________________________________________________________________________________________________________________________________________________________________________________________________(Round up to the next whole number)(Round up to the next whole number)Router BF0/1Start with the first subnet and arrange your sub-networks from the largest group to the smallest.++==Boston5 HostsResearch & Development8 Hosts
  • 73Show your work for Problem 8 in the space below.
  • Practical Subnetting 9F0/0S0/0/0S0/0/1Router ABased on the information in the graphic shown, design a network addressing scheme that willsupply the minimum number of hosts per subnet, and allow enough extra subnets andhosts for 15% growth in all areas. Circle each subnet on the graphic and answer the questionsbelow.Dallas1500 HostsF0/0Address classCustom subnet maskMinimum number of subnets neededExtra subnets required for 15% growthTotal number of subnets neededNumber of host addressesin the largest subnet groupNumber of addresses needed for15% growth in the largest subnetTotal number of addressneeded for the largest subnetIP address range for Ft. WorthIP address range for DallasIP address range for Router Ato Router B serial connectionIP address range for Router Ato Router C serial connectionIP address range for Router Cto Router D serial connectionIP Address 148.55.0.0_________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________(Round up to the next whole number)(Round up to the next whole number)Router BS0/0/1Router CF0/1S0/0/0Start with the first subnet and arrange your sub-networks from the largest group to the smallest.++==Router D S0/0/0S0/0/174Ft. Worth2300 Hosts
  • 75Show your work for Problem 9 in the space below.
  • 76Practical Subnetting 10Based on the information in the graphic shown, design a network addressing scheme that willsupply the minimum number of subnets, and allow enough extra subnets and hosts for110% growth in all areas. Circle each subnet on the graphic and answer the questions below.Address classCustom subnet maskMinimum number of subnets neededExtra subnets required for 110% growthTotal number of subnets neededNumber of host addressesin the largest subnet groupNumber of addresses needed for110% growth in the largest subnetTotal number of addressneeded for the largest subnetIP address range for Sales/ManagemntIP address range for MarketingIP address range for ResearchIP address range for Router Ato Router B serial connectionIP Address 172.16.0.0____________________________________________________________________________________________________________________________________________________________________________________________________________________________________(Round up to the next whole number)(Round up to the next whole number)Start with the first subnet and arrange your sub-networks from the largest group to the smallest.++==F0/0S0/0/0S0/0/1Router AF0/0Router BF0/1Sales115 HostsManagement25 HostsResearch35 HostsMarketing56 Hosts
  • 77Show your work for Problem 10 in the space below.
  • Valid and Non-Valid IP AddressesUsing the material in this workbook identify which of the addresses below are correct andusable. If they are not usable addresses explain why.IP Address: 0.230.190.192 ________________________________Subnet Mask: 255.0.0.0 ________________________________IP Address: 192.10.10.1 ________________________________Subnet Mask: 255.255.255.0 ________________________________IP Address: 245.150.190.10 ________________________________Subnet Mask: 255.255.255.0 ________________________________IP Address: 135.70.191.255 ________________________________Subnet Mask: 255.255.254.0 ________________________________IP Address: 127.100.100.10 ________________________________Subnet Mask: 255.0.0.0 ________________________________IP Address: 93.0.128.1 ________________________________Subnet Mask: 255.255.224.0 ________________________________IP Address: 200.10.10.128 ________________________________Subnet Mask: 255.255.255.224 ________________________________IP Address: 165.100.255.189 ________________________________Subnet Mask: 255.255.255.192 ________________________________IP Address: 190.35.0.10 ________________________________Subnet Mask: 255.255.255.192 ________________________________IP Address: 218.35.50.195 ________________________________Subnet Mask: 255.255.0.0 ________________________________IP Address: 200.10.10.175 /22 ________________________________________________________________IP Address: 135.70.255.255 ________________________________Subnet Mask: 255.255.224.0 ________________________________The network ID cannot be 0.OK78Reference Pages 28-29Reference Page Inside Front CoverReference Pages 48-49Reference Pages 54-55Reference Page Inside Front CoverReference Page Inside Front CoverReference Pages 54-55 and/or Inside Front CoverReference Pages 56-57Reference Pages Inside Front CoverReference Pages 34-35Reference Pages 30-31Reference Pages 48-49
  • 0-127128-2550-34-78-1112-1516-1920-2324-2728-3132-3536-3940-4344-4748-5152-5556-5960-6364-6768-7172-7576-7980-8384-8788-9192-9596-99100-103104-107108-111112-115116-119120-123124-127128-131132-135136-139140-143144-147148-151152-155156-159160-163164-167168-171172-175176-179180-183184-187188-191192-195196-199200-203204-207208-211212-215216-219220-223224-227228-231232-235236-239240-243244-247248-251252-255/308+8+8+6255.255.255.2524 Hosts/298+8+8+5255.255.255.2488 Hosts/288+8+8+4255.255.255.24016 Hosts/278+8+8+3255.255.255.22432 Hosts/268+8+8+2255.255.255.19264 Hosts/258+8+8+1255.255.255.128128 Hosts/248+8+8255.255.255.0256 Hosts0-78-1516-2324-3132-3940-4748-5556-6364-7172-7980-8788-9596-103104-111112-119120-127128-135136-143144-151152-15916-167168-175176-183184-191192-199200-207208-215216-223224-231232-239240-247248-2550-1516-3132-4748-6364-7980-9596-111112-127128-143144-159160-175176-191192-207208-223224-239240-2550-6364-127128-191192-2550-255IP Address Breakdown79
  • /24255.255.255.0256 Hosts1 SubnetStart with a square. The whole squareis a single subnet comprised of 256addresses.Visualizing Subnets UsingThe Box MethodThe box method is the simplest way to visualize the breakdown ofsubnets and addresses into smaller sizes./25255.255.255.128128 Hosts2 Subnets/26255.255.255.19264 Hosts4 Subnets80Split the box in half and you get twosubnets with 128 addresses,Divide the box into quarters and youget four subnets with 64 addresses,
  • 81/27255.255.255.22432 Hosts8 SubnetsSplit each individual square and youget eight subnets with 32 addresses,/30255.255.255.2524 Hosts64 Subnets/29255.255.255.2488 Hosts32 Subnets/28255.255.255.24016 Hosts16 SubnetsSplit the boxes in half again and youget sixteen subnets with sixteenaddresses,The next split gives you thirty twosubnets with eight addresses,The last split gives sixty four subnetswith four addresses each,
  • 82# of BitsBorrowed012345678910111213141516171819202122SubnetMask255.0.0.0255.128.0.0255.192.0.0255.224.0.0255.240.0.0255.248.0.0255.252.0.0255.254.0.0255.255.0.0255.255.128.0255.255.192.0255.255.224.0255.255.240.0255.255.248.0255.255.252.0255.255.254.0255.255.255.0255.255.255.128255.255.255.192255.255.255.224255.255.255.240255.255.255.248255.255.255.252Total # ofSubnets12481632641282565121,0242,0484,0968,19216,38432,76865,536131,072262,144524,2881,048,5762,097,1524,194,304Total # ofHosts16,777,2168,388,6084,194,3042,097,1521,048,576524,288262,144131,07265,53632,76816,3848,1924,0962,0481,02451225612864321684Usable # ofHosts16,777,2148,388,6064,194,3022,097,1501,048,574524,286262,142131,07065,53432,76616,3828,1904,0942,0461,02251025412662301462# of BitsBorrowed01234567891011121314SubnetMask255.255.0.0255.255.128.0255.255.192.0255.255.224.0255.255.240.0255.255.248.0255.255.252.0255.255.254.0255.255.255.0255.255.255.128255.255.255.192255.255.255.224255.255.255.240255.255.255.248255.255.255.252Total # ofSubnets12481632641282565121,0242,0484,0968,19216,384Total # ofHosts65,53632,76816,3848,1924,0962,0481,02451225612864321684Usable # ofHosts65,53432,76616,3828,1904,0942,0461,02251025412662301462Class C Addressing Guide# of BitsBorrowed0123456SubnetMask255.255.255.0255.255.255.128255.255.255.192255.255.255.224255.255.255.240255.255.255.248255.255.255.252Total # ofSubnets1248163264Total # ofHosts25612864321684Usable # ofHosts25412662301462CIDR/8/9/10/11/12/13/14/15/16/17/18/19/20/21/22/23/24/25/26/27/28/29/30CIDR/16/17/18/19/20/21/22/23/24/25/26/27/28/29/30CIDR/24/25/26/27/28/29/30Class B Addressing GuideClass A Addressing Guide__________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________
  • Inside Cover