図形の問題 解答編(OSC2012 Shimane LT資料)

2,500 views
2,450 views

Published on

Published in: Technology
0 Comments
0 Likes
Statistics
Notes
  • Be the first to comment

  • Be the first to like this

No Downloads
Views
Total views
2,500
On SlideShare
0
From Embeds
0
Number of Embeds
1,909
Actions
Shares
0
Downloads
2
Comments
0
Likes
0
Embeds 0
No embeds

No notes for slide

図形の問題 解答編(OSC2012 Shimane LT資料)

  1. 1. ∠ABCは何度? A 正方形 CB
  2. 2. ヒント A D 補助線を引いてみましょう CB E
  3. 3. ∠ABC=45° A D △ACD≡△CBEより AC=CB よって△ABCは二等辺三角形 ∠ACB=180°-∠ACD-∠BCE =180°-∠ACD-∠CAD =90° 二等辺三角形の底角は等しいので ∠ABC=∠BAC C ∴ ∠ABC=180°-∠BAC-∠ACD ∠ABC=180°-∠ABC-90° 2∠ABC=90° ∠ABC=45°B E
  4. 4. おしまい(^.^)/~~~

×