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Calc 1.1

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Preview of Calculus

Preview of Calculus

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  • Put in x^2 for f(x), 1for a, 2 for b
  • Slope is (4-1)/(2-1) = 3 (1,1) y – 1 = 3(x – 1) which becomes y = 3x – 3 + 1 which is y = 3x – 2
  • The secant line should closer to the slope line Look at website and slide point closer Show tangent line and secant line at same time
  • Switch to e-instruction and shade in rectangles

Calc 1.1 Calc 1.1 Presentation Transcript

  • Section 1.1 A Preview of Calculus What is it good for, anyway? Look at p. 43 - 44 for some examples
  • Calculus makes the concepts of precalculus DYNAMIC! PRECALCULUS LIMITING PROCESS CALCULUS
  • There are two big questions in Calculus! What is the equation of the tangent line that touches a curve at a particular point? What is the area underneath a curve?
  • To get the equation of a tangent line, we must know a point and a slope. How do we find the slope at a given point?
  • We can find slope if we know two points!
  • We can define slope for lines, how can that carry over to curves?
    • We can approximate the slope of a curve at a given point by finding the slope of a secant line using that point and one close by.
    • Look at figure 1.2 on p. 45 in book.
  • P(c, f(c)) is the point of tangency. Q(c+ Δ x, f(c+ Δ x)) is nearby point
  • What is the slope of the secant line? or
  • Here is a great site to see what is happening!
    • http://www.math.psu.edu/dlittle/java/calculus/secantlines.html
    • What did you come up with for slope?
    • What is the point of tangency?
    • What is the equation of the tangent line? Hint: Remember point slope formula for an equation of a line: Given slope m and point (x 1 , y 1 ):
    • (y – y 1 ) = m(x – x 1 )
    • If you got even closer to the point by letting Δ x get really small, what would happen?
  • How do you find area under a curve? Fig. 1.3, p.46
  • Let’s divide it into rectangles that approximate the area!
  • So, how wide are the rectangles? How tall are they? If we divide into 4 rectangles, the width would be The height would be the y-value at the left or right side of rectangle, or interval.
  • Rect. 1 Rect 2 Rect 3 Rect 4 Width .25 .25 .25 .25 Height f( )= f( )= f( )= f( )= Area = W ٠ H
  • If rectangles formed from right of interval: .25 ٠ 0 + .25 ٠ .0625 + .25 ٠ .25 + .25 ٠ .5625 = 0 + .01563 + .0625 + .14063 = .21876 If rectangles formed from left of interval: .25 ٠ .0625 + .25 ٠ .25 + .25 ٠ .5625 + .25 ٠ 1 = .01563 + .0625 + .14063 + .25 = .46876 The first is an underestimate, the second is an overestimate. The actual value is 0.3333…
  • What would happen if we increased the number of rectangles? http://www.math.psu.edu/dlittle/java/calculus/area.html p. 47/ 1-9 odd