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Trigo Ratios
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Transcript

  • 1. I would like to give credit to the following people below for the wonderful PowerPoint presentation. Thank you very much, Ms. Garcia Moy Yee Ping 3 Szeto Kwok Fai 2 Chau Ping 1
  • 2. Trigonometry ( 三角幾何 ) means “ Triangle” and “Measurement” Introduction Trigonometric Ratios
  • 3. Adjacent , Opposite Side and Hypotenuse of a Right Angle Triangle .
  • 4. Adjacent side Opposite side hypotenuse 
  • 5. hypotenuse Adjacent side Opposite side 
  • 6. Three Types Trigonometric Ratios
    • There are 3 kinds of trigonometric ratios we will learn.
      • sine ratio
      • cosine ratio
      • tangent ratio
  • 7. Sine Ratios
    • Definition of Sine Ratio.
    • Application of Sine Ratio.
  • 8.
    • Definition of Sine Ratio .
    1 If the hypotenuse equals to 1 Sin  =  Opposite sides
  • 9.
    • Definition of Sine Ratio .
    For any right-angled triangle Sin  =  Opposite side hypotenuses
  • 10. Exercise 1 In the figure, find sin  Sin  = Opposite Side hypotenuses = 4 7  = 34.85  (corr to 2 d.p.)  4 7
  • 11. Exercise 2 11 In the figure, find y Sin35  = Opposite Side hypotenuses y 11 y = 6.31 (corr to 2.d.p.) 35 ° y Sin35  = y = 11 sin35 
  • 12. Cosine Ratios
    • Definition of Cosine.
    • Relation of Cosine to the sides of right angle triangle.
  • 13.
    • Definition of Cosine Ratio .
    1 If the hypotenuse equals to 1 Cos  =  Adjacent Side
  • 14.
    • Definition of Cosine Ratio .
    For any right-angled triangle Cos  =  hypotenuses Adjacent Side
  • 15. Exercise 3  3 8 In the figure, find cos  cos  = adjacent Side hypotenuses = 3 8  = 67.98  (corr to 2 d.p.)
  • 16. Exercise 4 6 In the figure, find x Cos 42  = Adjacent Side hypotenuses 6 x x = 8.07 (corr to 2.d.p.) 42 ° x Cos 42  = x = 6 Cos 42 
  • 17. Tangent Ratios
    • Definition of Tangent.
    • Relation of Tangent to the sides of right angle triangle.
  • 18.
    • Definition of Tangent Ratio.
    For any right-angled triangle tan  =  Adjacent Side Opposite Side
  • 19. Exercise 5  3 5 In the figure, find tan  tan  = adjacent Side Opposite side = 3 5  = 78.69  (corr to 2 d.p.)
  • 20. Exercise 6 z 5 In the figure, find z tan 22  = adjacent Side Opposite side 5 z z = 12.38 (corr to 2 d.p.) 22  tan 22  = 5 tan 22  z =
  • 21. Conclusion Make Sure that the triangle is right-angled
  • 22. The END