Your SlideShare is downloading. ×
P2  Solid Geometry
Upcoming SlideShare
Loading in...5
×

Thanks for flagging this SlideShare!

Oops! An error has occurred.

×
Saving this for later? Get the SlideShare app to save on your phone or tablet. Read anywhere, anytime – even offline.
Text the download link to your phone
Standard text messaging rates apply

P2 Solid Geometry

1,737
views

Published on

Published in: Technology, Education

0 Comments
0 Likes
Statistics
Notes
  • Be the first to comment

  • Be the first to like this

No Downloads
Views
Total Views
1,737
On Slideshare
0
From Embeds
0
Number of Embeds
0
Actions
Shares
0
Downloads
128
Comments
0
Likes
0
Embeds 0
No embeds

Report content
Flagged as inappropriate Flag as inappropriate
Flag as inappropriate

Select your reason for flagging this presentation as inappropriate.

Cancel
No notes for slide

Transcript

  • 1. ppr maths nbk Solid geometry 1.Diagram 1 shows a solid formed by joining a cone and a cylinder. 4 cm Diagram 1 The diameter of the cylinder and the diameter of the base of the cone are both 7 cm. The volume of the solid is 231 cm².By using π = 22 , calculate the height, in cm, of the cone. 7 Answer: 2.Diagram 2 shows a solid cone with radius 9 cm and height 14 cm. A cylinder with radius 3 cm and height 7 cm is taken out of the solid. Diagram 2 Calculate the volume,in cm³,of the remaining solid. (Use π = 22 ) 7
  • 2. ppr maths nbk 3.Diagram 3 shows a cylinder. The shaded area with the shape of a hemisphere of radius 3 cm was removed. 7 cm Diagram 3 Find the volume , in cm³ , of the remaining solid. ( Use π = 22) 7 4.Diagram 4 shows a solid formed by joining a cone and a hemisphere. The diameter of the hemisphere is 10 cm and the slant height is 13 cm. Diagram 4 Calculate the volume , in cm³, of the solid
  • 3. ppr maths nbk 5.Diagram 5,shows a container for storing bread consists of a cuboid and a quadrant of a cylinder. U V 30 cm W 15 cm Q R 20 cm 7cm Calculate the volume, in cm³ , of the container . ( Use π = 22 ) 7
  • 4. ppr maths nbk ANSWER (DAIGNOSTIC TEST) 1. height = 6 2. volume = 990 3. volume = 141.43 4. volume = 576.19 5. volume = 10155
  • 5. ppr maths nbk

×