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Cuatro amigos presentation
 

Cuatro amigos presentation

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    Cuatro amigos presentation Cuatro amigos presentation Presentation Transcript

    • Cuatro amigos!By Janice, Pei Yu and KinseyFriday, 24 May, 13
    • ProblemFriday, 24 May, 13
    • SOLVEJ=5,10,15A=2M==>M<10(J=5)C=A/3 ==>A=12,18M>J==>J=5:M>5J<C ==>5<CMcannotbeover10.Aisanevennumberabove10.Factssofar:J=5A=12,18C=4,6-------------------------C>5C=66x2=12A=1818÷2=9M=9Friday, 24 May, 13
    • AnswersJuan’snumberis5Carlos’numberis6Maria’snumberis9Anna’snumberis18Friday, 24 May, 13