fracciones

1. ROMAN CORRALES MENDOZA
1
3
+ 1
2
= 2+3
6
= 5
6
1
2
+ 3
8
= 8+6
16
= 14
16
6
7
+ 1
9
= 54+7
63
= 61
63
11
17
+ 1
3
= 33+17
51
= 50
51
1
2
− 1
3
= 3−2
6
= 1
6
2
6
− 1
9
= 18−6
54
= 12
54
7
8
− 1
10
= 70−8
80
= 62
80
5
4
− 3
9
= 45−12
36
= 33
36
1
5
푥 1
6
= 1
30
1
2
푥 1
3
= 1
6

2. ROMAN CORRALES MENDOZA
2
5
푥 2
6
= 4
30
3
8
푥 1
2
= 3
16
1
8
÷ 1
4
= 4
8
1
7
÷ 1
3
= 3
7
1
3
÷ 1
2
= 2
3
6
9
÷ 1
3
= 18
9