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Power point latihan 2

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  • 1. A BCDEFGHCara membuat kubusBidang Alas ABCDBidang Atas EFGHBidang TegakABFE,BCGF,CDHG dan ADHERusuk Bid.Alas :AB,BC,CD,ADRusuk Bid.Atas :EF,FG,GH,HERusuk Bid.Tegak : AE,BF,CGdan DH.Bidang Diagonal :BDHF danACGE.Diagonal sisi:AC,BD,BG,CF,CH.DG,AH,DE,EG dan HFKUBUS
  • 2. A BCDEFGHLUAS PERMUKAAN KUBUSPerhatikan Kubus berikut :Misalkan panjangrusuk kubus =a,maka luaspermukaan kubus =6a
  • 3. A BCDEFGHVOLUME KUBUSPerhatikan Kubus berikut :Misalkan panjangrusuk kubus =a,maka Volume kubus= a3
  • 4. A BCDE FGHSoal-soal1.Pada kubus ABCD.EFGH, diketahuipanjang rusuk kubus 5 cm.Hitunglah a. Luas permuakaankubusb. Volume kubusJawab :a. Luas Permukaan kubusL = 6a= 6 x 5 cm= 30 cm2.b.Volume kubus = a3= 53= 125 cm35cm
  • 5. A BCDE FGHPQRS
  • 6. LIMASTA BCDO
  • 7. IRISAN LIMASTA BCDO
  • 8. BALOKA BCDEFGHCara membuat Balok1. Buat garis AB,AE, EFBF,CD,HG,DH,CG,AD,EH,BC dan FG.2.Diagonal sisi AC3.Diagonal ruang AG4.Buat garis BD dan FHsehingga terbentukbidang diagonal.4.Bidang alas ABCD5.Bidang atas EFGH
  • 9. LUAS PERMUKAAN BALOKA BCDEFGHpqrPerhatikan BalokABCD.EFGHJika AB=p, BC=l dan AE=tMakaLuas Permukaan Balok= 2 {(pxl)+(lxt)+(pxt)}.
  • 10. SOAL LATIHANA BCDE FGHDik :Panjang AB=10cmLebar BC = 8 cmTinggi AE= 6cmDit: Luas Permukaan BalokJawab:L.P.Balok = 2 ( p x lx t )= 2 ( 10x8x6 )= 2 (480)= 960 cm2Luas permukaan balok= 2 {(pxl)+(lxt)+(pxt)}= 2 ( p x l x t )10 cm8 cm6 cm
  • 11. VOLUME BALOKA BCDE FGHPanjang = ABLebar = BCTinggi = AEplt Jika AB = pBC = l dan AE = tVolume balok= p x l x t
  • 12. Soal latihanA BCDE FGHDikatahui balokABCD.EFGH,Panjang AB= 10cmLebar BC= 8cmTinggi AE= 6cmDitanya : volumebalok.pltVolume balok = p x l x t= 10 cm x 8 cm x 6 cm= 480 cm3

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