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# Lecture 10.2b- Molar Volume & STP

## on Nov 11, 2009

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Section 10.2 lecture (part B) for Honors & Prep Chemistry

Section 10.2 lecture (part B) for Honors & Prep Chemistry

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• In each container, the volume occupied by the gas molecules is small compared with the container’s volume, so the molecules are not tightly packed. a) The molecules in this container are small. b) This container can accommodate the same number of larger molecules.
• This box, with a volume of 22.4 L, holds one mole of gas at STP.
• This box, with a volume of 22.4 L, holds one mole of gas at STP.
• The map shows the conversion factors needed to convert among volume, mass, and number of particles. Interpreting Diagrams How many conversion factors are needed to convert from the mass of a gas to the volume of a gas at STP?

## Lecture 10.2b- Molar Volume & STPPresentation Transcript

• Bellwork- Mole conversions
• 1. Gold is currently selling for \$23.77 per gram.
• a) How much would two moles of gold cost?
• b) How many atoms are in two moles of gold?
• 2. How many grams of Be(NO 3 ) 2 would contain 3.2 moles?
• The Mole–Volume Relationship
• Equal volumes of gases at the same temperature and pressure contain equal numbers of particles.
• The volume of a gas varies with temperature and pressure.
• The volume of a gas varies with temperature and pressure.
• Because of these variations, the volume of a gas is usually measured at a standard temperature and pressure.
• The volume of a gas varies with temperature and pressure.
• Because of these variations, the volume of a gas is usually measured at a standard temperature and pressure.
• Standard temperature and pressure (STP) means a temperature of 0°C and a pressure of 1 atm.
• At STP, 1 mol of any gas occupies a volume of 22.4 L.
• At STP, 1 mol of any gas occupies a volume of 22.4 L.
• The quantity 22.4 L is called the molar volume of a gas.
• 10.7
• 10.7 Write the given 0.60 mol
• 10.7 Write the given 0.60 mol 
• 10.7 Write the given 0.60 mol  1 mol
• 10.7 Write the given 0.60 mol  1 mol 22.4L
• 10.7 Write the given 0.60 mol  1 mol 22.4L Because the ? asks for volume at STP
• 10.7 Write the given 0.60 mol  1 mol 22.4L = 13.4L Because the ? asks for volume at STP
• How many moles are in 44.8 liters of oxygen gas (O 2 ) at STP?
• How many moles are in 44.8 liters of oxygen gas (O 2 ) at STP?
• It doesn’t matter what type of gas we have
• How many moles are in 44.8 liters of oxygen gas (O 2 ) at STP?
• It doesn’t matter what type of gas we have
• If a gas is at STP then 1 mole = 22.4L
• How many moles are in 44.8 liters of oxygen gas (O 2 ) at STP?
• It doesn’t matter what type of gas we have
• If a gas is at STP then 1 mole = 22.4L
• 44.8L
• How many moles are in 44.8 liters of oxygen gas (O 2 ) at STP?
• It doesn’t matter what type of gas we have
• If a gas is at STP then 1 mole = 22.4L
• 44.8L
• How many moles are in 44.8 liters of oxygen gas (O 2 ) at STP?
• It doesn’t matter what type of gas we have
• If a gas is at STP then 1 mole = 22.4L
• 44.8L
 22.4L
• How many moles are in 44.8 liters of oxygen gas (O 2 ) at STP?
• It doesn’t matter what type of gas we have
• If a gas is at STP then 1 mole = 22.4L
• 44.8L
 1 mol 22.4L
• How many moles are in 44.8 liters of oxygen gas (O 2 ) at STP?
• It doesn’t matter what type of gas we have
• If a gas is at STP then 1 mole = 22.4L
• 44.8L
 1 mol 22.4L = 2 moles