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Module 5 topic 2 2nd

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  • 1. Module 5 Topic 2
    More – Parallel and Perpendicular Slopes
  • 2. Example 1
    Write the equation of a line in slope-intercept form that is parallel to y = -4x + 3 and passes through (8, -8).
    y = -4x + 3 the slope is -4 so the perpendicular slope is 1/4.
    y = mx + b
    -8 = 1/4(8) + b
    -8 = 2 + b
    -10 = b
    y = 1/4x - 10
  • 3. Example 2
    Similar Problem: Write the equation of a line in slope-intercept form that is parallel to 3x + y = 9 and passes through (0, 4).
    3x + y = 9 (solve for y).
    y = -3x + 9 slope is -3 so the parallel slope is also -3.
    y = mx + b
    4 = -3(0) + b
    4 = b
    y = -3x + 4
  • 4. Example 3
    Similar Problem: Write the equation of a line in slope-intercept form that is perpendicular to y = -3/4 x + 3 and passes through (18, -6).
    y = -3/4 x + 3 slope is -3/4 so the perpendicular slope is 4/3
    y = mx + b
    -6 = (4/3)(18) + b
    -6 = 24 + b
    -30 = b
    y = 4/3 x - 30
  • 5. Example 4
    Similar Problem: Write the equation of a line in slope-intercept form that is perpendicular to 4x + 3y = 12 and passes through the point (5, 0).
    4x + 3y = 12 (solve for y)
    3y = -4x + 12
    y = -4/3 x + 4 slope is -4/3 so the perpendicular slope is 3/4
    y = mx + b
    0 = (3/4)(5) + b
    0 = 15/4 + b
    -15/4 = b
    y = 3/4 x - 15/4