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Module 5 topic 2   2nd
 

Module 5 topic 2 2nd

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    Module 5 topic 2   2nd Module 5 topic 2 2nd Presentation Transcript

    • Module 5 Topic 2
      More – Parallel and Perpendicular Slopes
    • Example 1
      Write the equation of a line in slope-intercept form that is parallel to y = -4x + 3 and passes through (8, -8).
      y = -4x + 3 the slope is -4 so the perpendicular slope is 1/4.
      y = mx + b
      -8 = 1/4(8) + b
      -8 = 2 + b
      -10 = b
      y = 1/4x - 10
    • Example 2
      Similar Problem: Write the equation of a line in slope-intercept form that is parallel to 3x + y = 9 and passes through (0, 4).
      3x + y = 9 (solve for y).
      y = -3x + 9 slope is -3 so the parallel slope is also -3.
      y = mx + b
      4 = -3(0) + b
      4 = b
      y = -3x + 4
    • Example 3
      Similar Problem: Write the equation of a line in slope-intercept form that is perpendicular to y = -3/4 x + 3 and passes through (18, -6).
      y = -3/4 x + 3 slope is -3/4 so the perpendicular slope is 4/3
      y = mx + b
      -6 = (4/3)(18) + b
      -6 = 24 + b
      -30 = b
      y = 4/3 x - 30
    • Example 4
      Similar Problem: Write the equation of a line in slope-intercept form that is perpendicular to 4x + 3y = 12 and passes through the point (5, 0).
      4x + 3y = 12 (solve for y)
      3y = -4x + 12
      y = -4/3 x + 4 slope is -4/3 so the perpendicular slope is 3/4
      y = mx + b
      0 = (3/4)(5) + b
      0 = 15/4 + b
      -15/4 = b
      y = 3/4 x - 15/4