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# Module 4 topic 1 2nd

## by Annie cox on Oct 02, 2011

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Even more Coordinate Planes - Midpoint - Relations and Functions

Even more Coordinate Planes - Midpoint - Relations and Functions

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## Module 4 topic 1 2ndPresentation Transcript

• More – Coordinate Plane, Midpoint, and Relations and Functions
Module 4 Topic 1
• Example 1
Remember that the quadrants are I, II, III, or IV.
Quadrant I = (positive x-value, positive y-value)
Quadrant II = (negative x-value, positive y-value)
Quadrant III = (negative x-value, negative y-value)
Quadrant IV = (positive x-value, negative y-value)
• Example 2
Similar Problem: Find the coordinates of the midpoint of M(-3, 0) and N(-7, -5).
Midpoint is the average of the x-values and the average of the y-values.
Midpoint = (x2 + x1) ÷ 2 , (y2 + y1) ÷ 2
Midpoint = (-7 + -3) ÷ 2 , (-5 + 0) ÷ 2
Midpoint = -10 ÷ 2 , -5 ÷ 2
Midpoint = -5, -2.5 so we write it as an ordered pair (-5, -2.5)
• Example 3
Similar Problem: Use the following relation to answer questions 7 - 9.
{(2, 4), (7, 8), (-5, 4), (-2, -8), (0, 0)}
Is the relation a function?
Yes - because the x-values do not repeat!
• Example 4
Similar Problem: Use the following relation to answer questions 7 - 9.
{(2, 4), (7, 8), (-5, 4), (-2, -8), (0, 0)}
State the domain of the relation.
Domain = all x-values of the relation
2, 7, -5, -2, 0 but let's put these in order so we have
-5, -2, 0, 2, 7
• Example 5
Similar Problem: Use the following relation to answer questions 7 - 9.
{(2, 4), (7, 8), (-5, 4), (-2, -8), (0, 0)}
State the range of the relation.
Range = all y-values of the relation
4, 7, 4, -8, 0 but let's put these in order so we have
-8, 0, 4, 4, 7 and let's not repeat any so we have -8, 0 , 4, 7
• Example 6
Similar Problem: If f(x) = 3x + 6, find f(-4).
Plug in -4 for x in the function 3x + 6
3(-4) + 6
-12 + 6
-6