11/29/11

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11/29/11

  1. 1. 11/29 A/B DayLEQ: Why is Potassium (K) more similar toBeryllium (Be) than it is to Sodium (Na)?1. What is the difference between an ion and an isotope?2. What is a valence electron?3. What is seafloor spreading?4. At what type of boundary do we find rift valleys?5. What is pangaea?
  2. 2. Today’s LEQ: Why is Potassium (K) more similar to Beryllium (Be) than it is to Sodium (Na)??By the end of today, you should be able to…1. Explain why some elements are more reactive than others2. Predict the activity of valence electrons3. Predict elements that will likely react with each other
  3. 3. Focus Vocabulary68. Valence Electron69. Reactivity70. Compound
  4. 4. Activating Strategy: STOP AND JOTMake a list of 5 traits or characteristics thatyou share with members of your family -your characteristics can be physical (like your height) OR something about your personalities Share Out
  5. 5. Ms. Lorant and her brother, Carter  Things we have in common: -similar hair color -both love to read -both went to the University of North Carolina -both athletic -both love chocolate- covered pretzels
  6. 6. Elements have families too!
  7. 7. REMEMBER…. VALENCE ELECTRONS: ELECTRONS IN THE OUTERMOST RING
  8. 8. Elements in the same GROUP have thesame number of VALENCE ELECTRONS
  9. 9. How many valence electrons do I have?Hydrogen:
  10. 10. How many valence electrons do I have?Lithium:
  11. 11. How many valence electrons do I have?Sodium:
  12. 12. Same group = same # of valence electrons
  13. 13. Match each element with an element with an EQUAL number of valence electrons!Rubidium (Rb) Bromine (Br)Fluorine (F) Silicon (Si)Oxygen (O) Sulfur (S)Francium (Fr) Chlorine (Cl) Iodine (I)
  14. 14. Hot Q: Which has more valenceelectrons: Boron or Neon?
  15. 15. Elements with a FULL ring ofelectrons are STABLE elements.
  16. 16. EOG Exit TicketHow can a scientist, using the periodic table, find an element with properties similar to another element? a) By comparing density b) By finding its periodic group c) By comparing malleability d) By comparing atomic weight

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