5. From the following diagram make sure that you note down the joist data then work out the total load per joist
6.
7. Answer The formula for the Bending moment of a beam is …. Transpose the BM formula to find, d. Answer from standard sizes TN4 Work slowly through the following
8.
9. (Use b and d from before) The formula for calculating deflection due to a uniformly distributed load is: Answer Answer TN4 Use the nearest commercial size to find I then find ,d. Answer
12. The formula is Answer in cm TN3 I= 9504 from tables of values
13. Permissible deflection is 1/360 of 4 m = 11.1 cm. Therefore actual deflection of 0.835 cm is acceptable. Ref. BS 5950: Structural use of steelwork in building.
14.
15. (b) and (d) are incorporated into a geometric property of section, known as the radius of gyration (r). It can be calculated:- r = SQRT (1/A) where: I = (Inertia) -2nd moment of area A = cross sectional area Note: r,I and A are all listed in steel design tables, e.g.. BS4:1980.