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# Physics in sport 2

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### Transcript

• 1. STARTER – label the forces on a car
• 2. Tight Corners 2 Physics in Sport
• 3. Learning Intentions  Identify vertical and horizontal forces on a vehicle moving at constant velocity  Explain that when a vehicle travels around a banked curve the horizontal component of the normal force provides the centripetal force.  Derive and use tanθ=v2/rg for banked curves.
• 4. Italian Job
• 5. Forces on a moving vehicle (at a constant speed) FN Horizontally Vertically FN1 FN2 FR FD Tell me about the forces Express in maths W
• 6. Forces on a car when cornering 2 v F m r  Centripetal forces are from friction between the road an the tyres of the car  Resistive and driving forces are not shown
• 7. Coefficient of Friction  The friction between a moving vehicle/person and the ground is determined by a number of factors.  Weight  Surface contact  Surface conditions etc.  The reaction force “available” for friction is referred to as the coefficient of friction.  Ff= friction force (N)  FN= Normal (reaction) force (N)  μf= coefficient of friction 𝐹𝑓 = 𝜇 𝑓 𝐹 𝑁
• 8. Centripetal Force Calculation 150 kg 1. Calculate the centripetal force acting on this motor racer. 2. Find the coefficient of friction. 835N 0.57