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# Break and continue statement in C

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Explanation of break and continue statements in C language.

Explanation of break and continue statements in C language.

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• 1. Break and Continue statement
• 2. Break Statement
• 3. June Result Re-valuation Result December Result Normal Study Period Study Period if subject is cleared in the revaluation process
• 4. #include<stdio.h> #include<conio.h> main() { ………………………………. ………………………………. ………………………………. while(condition) { ……………. ……………. If condition becomes true if(condition) break; ……………. ……………. ……………. increment or decrement; } …………………………………. …………………………………. …………………………………. getch(); }
• 5. Prime Number . , , , , ….! , , , , , , , : , ….!
• 6. #include<stdio.h> #include<conio.h> void main() { int num, i; clrscr(); printf(“Enter Numbert”); scanf(“%d”, &num); i = 2; while(i < num – 1) { if(num % i == 0) { printf(“Numbers is not primen”); break; } i++; } if(i == num) printf(“Number is primen”); getch(); }
• 7. Enter Number Number is prime _ 5
• 8. Enter Number Number is prime _ 37
• 9. Enter Number Number is Not prime Number is prime _ 25
• 10. Enter Number Number is Not prime _ 25
• 11. #include<stdio.h> #include<conio.h> void main() { int num, i; clrscr(); printf(“Enter Numbert”); scanf(“%d”, &num); i = 2; while(i < num – 1) { if(num % i == 0) { printf(“Numbers is not primen”); break; } i++; } if(i == num) printf(“Number is primen”); getch(); } 25 num 2 i
• 12. Continue statement for(i = 1; i < 10; i++) { do this; If condition is do this; true if(condition) continue; do this; If condition is do this; false }
• 13. 5 10 15 20 25 30 35 40 45 50 _
• 14. #include<stdio.h> #include<conio.h> void main() { int j; clrscr(); for(j=1; j<=50; j++) { if(j % 5 != 0) continue; printf(“%dn”, j); } getch(); } When j is not divisible by 5