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Engineering mathematics
Engineering mathematics
you have also written the same thing
whe you divide the right side by (e^x) you will get the answer written in the book. As e^(2x) / e^x = e^x. I hope you get this
This is the answer I get...
y' = [sinx - (e^2x) * y] / e^x
To get e^x over to the left side of the eqn you need to divide both sides by e^x
Can someone explain?
THANKS :o)
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