Geriin daalgavar

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Geriin daalgavar

  1. 1. Гэрийн даалгавар1Äàðààõ çóðãààñ òýãø ºíöºãò ãóðâàëæíû ºíöã¿¿ä áîëîí òàëóóäûã íýðëý . A B CÊîñèíóñ íü 12 – òýé òýíöýõ ºíöºã áàéãóóë.Èëýðõèéëëèéã õÿëáàð÷èë. tan2α + cos2α + sin2α =
  2. 2. cosα = 1112 áîë sinα= ? tanα=? cotα=?ABC òýãø ºíöºãò ãóðâàëæíû íýã ºíöºã íü 60° áà AB =43 áîë BC=? AC=?Гэрийн гэрийн даалгавар2 Äàðààõ òýãø ºíöºãò ãóðâàëæíû õóâüä Ïèôàãîðûí òåîðåì áè÷.
  3. 3. A B C Ñèíóñ íü 22 - òýé òýíöýõ ºíöºã áàéãóóë .Èëýðõèéëëèéã õÿëáàð÷èë. cot2α +cotα · tanα=sinα = 610 áîë cosα=? tanα=? cotα= ?C òýãø ºíöºãòýé ABC ãóðâàëæíû ∠A = 30° áà AB = 12 áîë AC=?,BC=?Гэрийн даалгавар31510 · 2322- 572 +16 567 -11315 · 2528 èëýðõèéëëèéã õÿëáàð÷èë. 2 2à) y = x +2x -15 á) y = (2-x) (x + 6) â) y = -9+4x ôóíêöûí ãðàôèêèéã áàéãóóë.
  4. 4. 2 2x – (3à +2)x + à =0 òýãøèòãýëèéí ÿçãóóðóóä íü x1 áà x2 áºãººä x1= 9x2 õàìààðàëòàéáîë à òîî áà x1 , x2 –èéã îë.à) y = x2+2xx2+5x+6 á) y= x2-2x+84-x â) y=x2 – x+1x2-1 ôóíêöûí òîäîðõîéëîãäîõìóæèéã îë. -10 -3 -4 -1 -2 -1/9 -313 · 27 + (0.2) · 25 · 25 + (64 ) èëýðõèéëëèéã õÿëáàð÷èë.Õî¸ð àæèë÷èí õàìòðàí 4 öàã àæèëëàæ áàñ I àæèë÷èí 3.5 öàã íýìæ àæèëëàâàë 290äåòàëü ¿éëäâýðëýõ áàéâ.Õýðýâ òýä õàìòðàí 5öàã àæèëëàâàë ¿ëäñýí õýñãèéã IIàæèë÷èí 2öàã 30 ìèíóòàä ã¿éöýòãýíý.Àæèë÷èí öàã òóòàìä õýäýí äåòàëü ¿éëäâýðëýõâý?3 õºâã¿¿í 3 îõèíûã íýã ýãíýýíä çîãñîîõäîî îõèä áà õºâã¿¿äèéã ñàëààâ÷ëàí çîãñîîñîí áîëòýä õýäýí ÿíçààð çîãñîõ âý?
  5. 5. Òðàïåöûí ñóóðèóä 5:9 õàðüöààòàé , õàæóó òàëóóäûí íýã íü 16ñì .ͺ㺺 õàæóó òàëûí¿ðãýëæëýëòýé îãòëîëöóóëàõûí òóëä ýíý õàæóó òàëûã õè÷íýýí ¿ðãýëæë¿¿ëýõ âý?Öýãýýñ øóëóóíä ïåðïåíäèêóëÿð áà õî¸ð íàëóó òàòàâ.Õýðýâ íàëóóíóóä 41ñì áà 50ñì áàøóëóóí äýýðõ ïðîåêöóóä íü 3:1 õàðüöààòàé ïåðïåíäèêóëÿðûí óðòûã îë.Àäèë õàæóóò òýãø ºíöºãò ãóðâàëæèíä õî¸ð îðîé íü ãåïîòåíóç äýýð, õî¸ð îðîé íüêàòåòóóä äýýð îðøèõ òýãø ºíöºãò áàãòààâ.Ãóðâàëæíû ãèïîòåíóç 45ñì òýãø ºíöºãòèéíòàëóóäûí õàðüöàà 5:2 áîë òàëóóäûã îë.Òðàïåöûí õàæóó òàëóóäûã 6 òýíö¿¿ õýñýãò õóâààæ õóâààëòûí öýã¿¿äèéãäàéðóóëàí ñóóðüòàé ïàðàëëåëààð íºãºº õàæóó òàëòàé õýð÷ìýýð õîëáîâ.Õýðýâòðàïåöûí ñóóðèóä 10ñì 28 ñì áîë ýäãýýð õýð÷ì¿¿äèéí óðòûã îë.à ñóóðüòàé àäèë õàæóóò òýãø ºíöºãò ãóðâàëæíû õàæóó òàëûã îë.ACB ãóðâàëæíû òýãø ºíöãèéí îðîé C-ýýñ CD áèññåêòðèññ òàòàâ.Õýðýâ ∠CDB =105° ,AC=3 áîë DB – ã îë.Ãóðâàëæíû a áà â óðòòàé òàëóóäûí õîîðîíäîõ ºíöºã α áîëíî.α íü 45° ,60°, 90° ¿åäãóðàâäàõü òàëûã îë.ABCD òðàïåöûí B îðîéãîîñ õàæóó òàë CD –òýé ïàðàëëåëü øóëóóí òàòàõàä AD-ã Eöýãò îãòîëíî.ABE ãóðâàëæíû ïåðèìåòð 10äì ED=3äì áîë òðàïåöûí ïåðèìåòðèéã îë. 230ñì ñóóðüòàé 10ñì ºíäºðòýé ãóðâàëæèíä 63ñì òàëáàéòàé òýãø ºíöºãò áàãòàâ.Òýãøºíöºãòèéí òàëóóäûã îë.

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