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Chapter 7
Systems of Equations &
     Inequalities
         P. 424
    Prerequisite Skills
• In this chapter, you will learn three
  different methods to solve a pair of linear
  equations simultaneously.

• We will also learn the difference between
  solving an equation and solving an
  inequality.
• Section 7.1 Solve Linear Systems by
  Graphing (Graph & Check Method)
•
  P. 427

 This is the first of three method to solve a
 linear system.
Linear System:
  A system of linear equations (or simply a
  linear system) consists of two or more
  linear equations in the same variables.

Example: x + 2y = 7
        3x – 2y = 5
The solution of a system of linear equations
 in two variables is an ordered pair that
 satisfies each equation in the system.
EXAMPLE 1        Check the intersection point

 Use the graph to solve the
 system. Then check your
 solution algebraically.

 x + 2y = 7       Equation 1

 3x – 2y = 5      Equation 2

 SOLUTION
 The lines appear to intersect at the point (3, 2).
 CHECK Substitute 3 for x and 2 for y in each equation.
     x + 2y = 7
            ?
   3 + 2(2) = 7
          7=7
EXAMPLE 1          Check the intersection point

     3x – 2y = 5
             ?
 3(3) – 2(2) = 5
           5=5

ANSWER

Because the ordered pair (3, 2) is a solution of each
equation, it is a solution of the system.
EXAMPLE 2      Use the graph-and-check method

Solve the linear system:
 –x + y = –7       Equation 1
 x + 4y = –8       Equation 2

SOLUTION
 STEP 1
 Graph both equations.
EXAMPLE 2        Use the graph-and-check method

 STEP 2
 Estimate the point of intersection. The two lines
 appear to intersect at (4, – 3).
 STEP 3
 Check whether (4, –3) is a solution by substituting 4 for
 x and –3 for y in each of the original equations.


 Equation 1                        Equation 2
       –x + y = –7                     x + 4y = –8
              ?                               ?
 –(4) + (–3) = –7                   4 + 4(–3) = –8
           –7 = –7                         –8 = –8
EXAMPLE 2      Use the graph-and-check method


 ANSWER
 Because (4, –3) is a solution of each equation, it is a
 solution of the linear system.
GUIDED PRACTICE graph-and-checkand 2
EXAMPLE 2  Use the for Examples 1 method

 Solve the linear system by graphing. Check your solution.

 3. x – y = 5
   3x + y = 3

 ANSWER
 (2, 3)
• Assignment: P. 430- 431
   Do # 1-5 orally together
• Write out / graph 8-10, 12-14, 18-20

• Remember to CHECK your solution in
  both equations.

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Solving Systems of Equations Graphically

  • 1. Chapter 7 Systems of Equations & Inequalities P. 424 Prerequisite Skills
  • 2. • In this chapter, you will learn three different methods to solve a pair of linear equations simultaneously. • We will also learn the difference between solving an equation and solving an inequality.
  • 3. • Section 7.1 Solve Linear Systems by Graphing (Graph & Check Method) • P. 427 This is the first of three method to solve a linear system.
  • 4. Linear System: A system of linear equations (or simply a linear system) consists of two or more linear equations in the same variables. Example: x + 2y = 7 3x – 2y = 5
  • 5. The solution of a system of linear equations in two variables is an ordered pair that satisfies each equation in the system.
  • 6. EXAMPLE 1 Check the intersection point Use the graph to solve the system. Then check your solution algebraically. x + 2y = 7 Equation 1 3x – 2y = 5 Equation 2 SOLUTION The lines appear to intersect at the point (3, 2). CHECK Substitute 3 for x and 2 for y in each equation. x + 2y = 7 ? 3 + 2(2) = 7 7=7
  • 7. EXAMPLE 1 Check the intersection point 3x – 2y = 5 ? 3(3) – 2(2) = 5 5=5 ANSWER Because the ordered pair (3, 2) is a solution of each equation, it is a solution of the system.
  • 8. EXAMPLE 2 Use the graph-and-check method Solve the linear system: –x + y = –7 Equation 1 x + 4y = –8 Equation 2 SOLUTION STEP 1 Graph both equations.
  • 9. EXAMPLE 2 Use the graph-and-check method STEP 2 Estimate the point of intersection. The two lines appear to intersect at (4, – 3). STEP 3 Check whether (4, –3) is a solution by substituting 4 for x and –3 for y in each of the original equations. Equation 1 Equation 2 –x + y = –7 x + 4y = –8 ? ? –(4) + (–3) = –7 4 + 4(–3) = –8 –7 = –7 –8 = –8
  • 10. EXAMPLE 2 Use the graph-and-check method ANSWER Because (4, –3) is a solution of each equation, it is a solution of the linear system.
  • 11. GUIDED PRACTICE graph-and-checkand 2 EXAMPLE 2 Use the for Examples 1 method Solve the linear system by graphing. Check your solution. 3. x – y = 5 3x + y = 3 ANSWER (2, 3)
  • 12. • Assignment: P. 430- 431 Do # 1-5 orally together • Write out / graph 8-10, 12-14, 18-20 • Remember to CHECK your solution in both equations.