10.4 surface area of prisms & cylinders 2

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10.4 surface area of prisms & cylinders 2

  1. 1. Surface Area of Prisms & Cylinders Section 10.4 P. 542
  2. 2.  Find the SA GUIDED PRACTICECircle: A= 3.14 x 8 x 8= 200.96C= 3.14 x 2 x 8 = 50.24Rectangle: A= 50.24 x 20 = 1004.8200.96 + 200.96 +1004.8 = 1406.7 in2
  3. 3.  Cylinder: a 3-D figure with two congruent circles for bases. r h How can I find the length of this rectangle?
  4. 4.  Find the SA 3 14Circle: A = π r2A= 3.14 x 3 x 3= 28.26C=πx2xrC= 3.14 x 2 x 3 = 18.84Rectangle: A = b x hA= 18.84 x 14 = 263.7628.26 + 28.26 +263.76 = 320.28 = 320.3 units2
  5. 5. Homework Page 546 #14-16  You do not have to draw the nets, but you may draw them if it helps you find the surface area.

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