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Inverse matrix (part 3)
 

Inverse matrix (part 3)

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    Inverse matrix (part 3) Inverse matrix (part 3) Presentation Transcript

    • Inverse Matrix (Part 3)
      Gauss-Jordan Elimination
    • Given:
      1 0 1
      0 2 1
      1 1 1
      1 0 0
      0 1 0
      0 0 1
    • 3rd row minus 1st row
      1 0 1
      0 2 1
      1 1 1
      1 0 0
      0 1 0
      0 0 1
      1 0 1
      0 2 1
      0 1 0
      1 0 0
      0 1 0
      -1 0 1
      Answer
    • Swap the 3rd row and 2nd row
      1 0 1
      0 2 1
      0 1 0
      1 0 0
      0 1 0
      -1 0 1
      1 0 1
      0 1 0
      0 2 1
      1 0 0
      -1 0 1
      0 1 0
    • 3rd row minus 2 x 2nd row
      1 0 1
      0 1 0
      0 2 1
      1 0 0
      -1 0 1
      0 1 0
      1 0 1
      0 1 0
      0 0 1
      1 0 0
      -1 0 1
      2 1 -2
      Answer
    • 1st row minus 3rd row
      1 0 1
      0 1 0
      0 0 1
      1 0 0
      -1 0 1
      2 1 -2
      1 0 0
      0 1 0
      0 0 1
      -1 -1 2
      -1 0 1
      2 1 -2
      Answer
    • Final Answer:
      1 0 0
      0 1 0
      0 0 1
      -1 -1 2
      -1 0 1
      2 1 -2
      Inverse
      Matrix
      Identity Matrix
    • THANK YOU FOR LISTENING! 