Inverse matrix (part 3)
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Inverse matrix (part 3) Presentation Transcript

  • 1. Inverse Matrix (Part 3)
    Gauss-Jordan Elimination
  • 2. Given:
    1 0 1
    0 2 1
    1 1 1
    1 0 0
    0 1 0
    0 0 1
  • 3. 3rd row minus 1st row
    1 0 1
    0 2 1
    1 1 1
    1 0 0
    0 1 0
    0 0 1
    1 0 1
    0 2 1
    0 1 0
    1 0 0
    0 1 0
    -1 0 1
    Answer
  • 4. Swap the 3rd row and 2nd row
    1 0 1
    0 2 1
    0 1 0
    1 0 0
    0 1 0
    -1 0 1
    1 0 1
    0 1 0
    0 2 1
    1 0 0
    -1 0 1
    0 1 0
  • 5. 3rd row minus 2 x 2nd row
    1 0 1
    0 1 0
    0 2 1
    1 0 0
    -1 0 1
    0 1 0
    1 0 1
    0 1 0
    0 0 1
    1 0 0
    -1 0 1
    2 1 -2
    Answer
  • 6. 1st row minus 3rd row
    1 0 1
    0 1 0
    0 0 1
    1 0 0
    -1 0 1
    2 1 -2
    1 0 0
    0 1 0
    0 0 1
    -1 -1 2
    -1 0 1
    2 1 -2
    Answer
  • 7. Final Answer:
    1 0 0
    0 1 0
    0 0 1
    -1 -1 2
    -1 0 1
    2 1 -2
    Inverse
    Matrix
    Identity Matrix
  • 8. THANK YOU FOR LISTENING! 