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Algebra Substitution With Positive Numbers

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Algebra Substitution With Positive Numbers

1. 1. Image Source: http://photos.northofboston.com
2. 2. In Basketball we can have certain set positions onthe court, and substitute player names into thesepositions.This gives us one unique team who will play for usduring the match. Image Source: http://photos.lasvegassun.com (See next Slide for example).
3. 3. RufasLeroy Tyrone Willy Wally
4. 4. We could choose a different team with somedifferent player names, and this would give us adifferent result. Our Team Positions chart sets up where we cansubstitute our players, and we can pick severaldifferent names to substitute into this chart.In Algebra, we have an “Expression” that tells uswhat different variable letters we have available tosubstitute numbers into.The Algebra Expression is like our “Panthers”team Basketball Positions Chart.It sets up what we can substitute our values into.
5. 5. Here is a basic substitution question:Evaluate the expression h + 5 for h = 3 .(“Evaluate” means work out the number answer)The steps for evaluating are as follows: Write down the Algebraic Expression Replace the letter with the number value Work out the final number answer. (Continued on next slide)
6. 6. Evaluate the expression h + 5, for h = 3The expression is: h + 5We need to replace the “h” with 3This makes: 3+5which equals: 8 (Continued on next slide)
7. 7. Evaluate the expression h + 5, for h = 3We set this out in our math workbook as like this: h + 5 (h=3) =3+5 =8
8. 8. Evaluate the expression 2y + 7, for y = 4We need to replace the “y” with the number 4. 2y + 7 (y = 4) = 24 + 7 = 31 2y means 2 multiplied by y - We have made an error. 
9. 9. Evaluate the expression 2y + 7, for y = 4 2y + 7 (y = 4) 2y means 2 x y = 2 (4) + 7 = 8 +7 = 15
10. 10. Evaluate 3a - 2b, for a = 10 and b = 4 3a – 2b (a = 10 b = 4) = 3(10) – 2(4) = 30 – 8 = 22
11. 11. Evaluate a / 2b + c, for a = 10 b = 1 c = 4 a / 2b + c (a = 10 b = 1 c = 4) = 10 / 2(1) + 4 = 10 / 2 + 4 (Divide before Adding) = 5 + 4 = 9
12. 12. Evaluate a(ab + c), for a = 2 b = 3 c = 5 a ( ab + c ) (a = 2 b = 3 c = 5) = 2 ( 2(3) + 5 ) (Do inside first) =2( 6 + 5) (Keep doing Inside) =2( 11 ) = 2 x 11 = 22
13. 13. Complete the following table using therule: y = 3x - 1 x y We need to use the expression 3x - 1 to work out each y value. 2 4 Eg. For x = 2 6 3x – 1 8 = 3(2) – 1 = 6 – 1 = 5 (See next Slide)
14. 14. Complete the following table using therule: y = 3x - 1 x Working Out Steps y 2 y = 3x -1 = 3(2) – 1 = 6-1 = 5 5 4 y = 3x -1 = 3(4) – 1 = 12-1 = 11 11 6 y = 3x -1 = 3(6) – 1 = 18-1 = 17 17 8 y = 3x -1 = 3(8) – 1 = 24-1 = 23 23