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GOKUL ACADEMY OF SCIENCE
                                 15, Near Gajanan High School, New Subhedar Lay-out, Nagpur-24
                                                 Ph.No.0712-2743707 & 6466067

Date :06-01-2012                       Gokul Retrospection sheet 04          Std :XII - State
                                                   ( G.R.S. -04)


Biology
Q.1 Ultrafilteration                                                                       (M-02)

Q.2 Tubular Secretion(Renal Secretion)                                                     (M-02)

Q.3 Explain role of kidney in osmoregulation.                                              (M-04)

Chemistry
Q.1    What is the action of the following on phenol

        i) dil HNO3 at R.T.

        ii) con. HNO3 at 373 k

       iii) H2 SO4 at R.T.

       iv) H2 SO4 at 373 k.

Physics
Q.1    Write expression for variation of g With depth and latitude.

Q.2    What is communication satellite?

Mathematics
Q.1    cot 4050 · tan( - 4950 ) – tan 5850· cot (-4950) = 0

Q.2    sec 8400 · cot ( - 945) + sin 6000 · tan (-6900) = 3/2

Q.3    sin (900 + A) _    sin(1800 – A ) + tan (270 + A)
        cos ( - A )         sin ( - A )    cot ( - A )

Q.4    cosec(900 – A ) · sin (1800 – A) cot( 3600 – A)
        sec (1800 + A) · tan(900 + A) · sin (-A)


                                                                Go Cool For Exam
                                                                .

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  • 1. GOKUL ACADEMY OF SCIENCE 15, Near Gajanan High School, New Subhedar Lay-out, Nagpur-24 Ph.No.0712-2743707 & 6466067 Date :06-01-2012 Gokul Retrospection sheet 04 Std :XII - State ( G.R.S. -04) Biology Q.1 Ultrafilteration (M-02) Q.2 Tubular Secretion(Renal Secretion) (M-02) Q.3 Explain role of kidney in osmoregulation. (M-04) Chemistry Q.1 What is the action of the following on phenol i) dil HNO3 at R.T. ii) con. HNO3 at 373 k iii) H2 SO4 at R.T. iv) H2 SO4 at 373 k. Physics Q.1 Write expression for variation of g With depth and latitude. Q.2 What is communication satellite? Mathematics Q.1 cot 4050 · tan( - 4950 ) – tan 5850· cot (-4950) = 0 Q.2 sec 8400 · cot ( - 945) + sin 6000 · tan (-6900) = 3/2 Q.3 sin (900 + A) _ sin(1800 – A ) + tan (270 + A) cos ( - A ) sin ( - A ) cot ( - A ) Q.4 cosec(900 – A ) · sin (1800 – A) cot( 3600 – A) sec (1800 + A) · tan(900 + A) · sin (-A) Go Cool For Exam .