Quadratics Portfolio Powerpoint

Solving Quadratic Equations An explanation by Molly Murphy

Forms of Quadratics
Standard Form
ƒ(x) = ax² + bx + c
Vertex Form
ƒ(x) = a(x - h)² + k
Intercept Form
ƒ(x) = a(x - p)(x - q)

Role of “a” in quadratics
If a>0 the parabola opens up
If a<0 the parabola opens down
Graph is narrow if |a|>1
Graph is wide if |a|<1

Standard Form (finding vertex)
The vertex is (-b/2a , ƒ(-b/2a))
The axis of symmetry is the vertical line going through the vertex. It is written algebraically as x=-b/2a (because –b/2a is the x-coordinate of the vertex)

Standard Form (max. and min.)
The vertex is the parabola’s maximum or minimum value.
If the parabola opens up it has a minimum. If it opens down it has a maximum.

Standard Form (role of c)
“c” is the y-intercept of the parabola. The point (0 , c) is on the parabola.

Graphing in Standard form
Example: ƒ(x) = 2x² + 4x + 1
Find the x-coordinate of the vertex
-b/2a = -4/2(2) = -4/4= -1
Plug that number back into the function to find the y-coordinate
2(-1)²+4(-1)+1 = -2²-4+1 = 2-4+1 = -1
The vertex is (-1 , -1)
Make a chart with other values on either “side” of the x-coordinate of the vertex. Plug the x values into the function to get the y values.
7 1 -1 1 7 Y 1 0 -1 -2 -3 X

Continued
Plot the points on the graph and draw parabola.
Check with graphing calculator.
(-3 , 7) (1, 7) (0 , 1) (-2 , 1) (-1 , -1)

Vertex Form (finding vertex)
ƒ(x) = a(x - h)² + k
The vertex is (h , k)
The vertex is (0 , 1) So h=0 and k=1

Graphing in Vertex Form
ƒ(x) = 2(x + 1)² - 1
We already know the vertex is (-1 , -1)
Make a chart of x and y values. Plug the x values into the equation and solve to get the y values.
7 1 -1 1 7 Y 1 0 -1 -2 -3 X

Continued
Plot the vertex and other points on the graph. Draw parabola.
Check with graphing calculator.
(-3 , 7) (1 , 7) (-2 , 1) (0 , 1) (-1 , -1)

Intercept Form (finding vertex)
ƒ(x) = a(x – p)(x – q)
For the x-coordinate of the vertex, average p and q (p+q)/2. For the y-coordinate of the vertex, plug that value back into the function. ƒ((p+q)/2).

Graphing in Intercept Form
ƒ(x) = a(x – p)(x – q)
The x-intercepts are p and q.
ƒ(x) = 2(x + 3)(x + 1)
Plot the vertex (-3+-1)/2 = -4/2 = -2
y = 2(-2+3)(-2+1) = -2 the vertex is (-2 , -2)
Next plot the x-intercepts (0 , -3) and (0 , -1)
Draw in parabola.

Continued
Check with a graphing calculator.
(0 , -1) (0 , -3) (-2 , -2)

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Quadratics Portfolio Powerpoint

by algebra2werner on Mar 25, 2010

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