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# Ejercicio 211 del libro de baldor

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### Ejercicio 211 del libro de baldor

1. 1. Ejercicio 211 del libro de Baldor .( + ) =( ) + 6( ) (2 ) + 15( ) (2 ) + 20( ) (2 ) + 15( ) (2 ) + 6( )(2 ) + (2 ) = +6 (2 ) + 15 (4 ) + 20 (8 ) + 15 (16 ) + 6 (32 ) + 64 = = + + + + + + .( − " ) =(2# ) + 5(2# ) (−3\$ ) + 10(2# ) (−3\$ ) + 10(2# ) (−3\$ ) + 5(2# )(−3\$ ) +(−3\$ ) =32#%& + 5(16# )(−3\$ ) + 10(8# )(9\$ ) + 10(4# )(−27\$* ) + 5(2# )(81\$% )−243\$% =32#%& + 80# (−3\$ ) + 80# (9\$ ) + 40# (−27\$* ) + 10# (81\$% )−243\$% = + = − " +, " − + " ++ " − " . (- + . ) =(/ ) + 6(/ ) (0 ) + 15(/ ) (0 ) + 20(/ ) (0 ) + 15(/ ) (0 ) + 6(/ )(0 ) + (0 ) =/ % + 6(/ %& )(0 ) + 15(/ )(0 ) + 20(/ )(0 * ) + 15(/ )(0% ) + 6(/ )(0% ) + (0 % ) = =- + - . + -+ . + - . + - . + - . +. +4.- ( - ., ), =4.-(3)3 + (3) (-0 3 ) + (3) (−0 3 ) + (3) (−0 3 ) + (3) (−0 3 ) + (3) (−0 3 ) + (3) (−0 3 )+ (−0 3 )3 =(3)3 + 7 (3) (−0 3 ) + 21(3) (−0 3 ) + 35(3) (−0 3 ) + 35(3) (−0 3 ) + 21(3) (−0 3 )+ 7(3) (−0 3) + (−0 3)3 =R= 2187 – 5103 ., + 5103 5103. −2835 2835. 2835 945. + 945 + − 189 189. 21. + 21 −.
2. 2. 5.-5.- ( - − . ) =(2/ ) + (2/ ) (−30 ) + (2/ ) (−30 ) + (2/ ) (−30 ) + (2/ ) (−30 ) + (2/ )(−30 ) + (−3y ) =(2/ ) + 6(2/ ) (−30 ) + 15(2/ ) (−30 ) + 20(2/ ) (−30 ) + 15(2/ ) (−30 )+ 6(2/ ) (−30 ) + (−3y ) = + 64-R= 64 − , - . + 2160 .+ − 2160- - . + 4860 - . − - . 729. + 7296.-6.- ( - + . ) =% % % % %( 7 ) + ( / ) (0 ) + ( 7 ) (8 ) + ( 7 ) (8 ) + ( 7 )(8 )+ (0 ) =% % % % %( 7 ) + 5( / ) (0 ) + 10( 7 ) (8 ) + 10( 7 ) (8 ) + 5( 7 )(8 ) + (0 ) =R= 9 + 9+ : + 9 : + 9 : + 9 : +: ;,. ( − <) = = = = = = =( ) - ( ) ( )+( ) ( ) -( ) ( ) +( ) ( ) - ( )( ) +( ) = > > > > > > = = = = = =( ) - 6 ( ) ( ) + 15( ) ( ) - 20( ) ( ) + 15( ) ( ) - 6( ) ( ) + ( ) = > > > > > > ; ; ; ; ; + ; , =, − ,< + < − < + < − < + <+. ( − - )+ =(1) - (1)3 (x) + (1) (x4)2- (1) (x4)3+ (1) (x4)4- (1) (x4)5+ (1) (x4)6- (1)(x4)7+ (x4)8 =(1) - 8(1)3 (x) + 28(1) (x4)2- 56(1) (x4)3+ 70(1) (x4)4- 56(1) (x4)5+ 28(1) (x4)6-8(1)(x4)7+ (x4)8 = =1 – 8x4 + 28x8 – 56x12 + 70x16 – 56x20 + 28x24 – 8x28 + x32 1 .( - )7 = - .
3. 3. ( )7 – ( )6 ( )+( ) ( )2 – ( )4 ( )3 + ( )3 ( )4 – ( ) 2 ( )5 + ( ) ( )6 – @ @ A @ A @ A @ A @ A @ A( )7= A( ) 7 – 7( ) 6 ( ) + 21( ) ( )2 – 35( )4 ( )3 + 35( )3 ( )4 – 21( ) 2 ( )5 + @ @ A @ A @ A @ A @ A7( )( )6 – ( )7= @ A A + , , , +,B= - + − + − + − +,9 , 9 : 9 : 9 : 9 : +9 : 9: +: , 210.10. ( - ), m 2 2 # 2 # 2 # 2 #( ), − 7( ) ( ) + 21( ) (− ) − 35( ) (− ) − 35( ) (− ) # # 2 # 2 # 2 # 2 2 # 2 # #+21( ) (− ) − 7( )(− ) − (− )3 = # 2 # 2 2 + + + ,R= , − + −, + − + − + + . (- + ")+(/ ) + 8(/ )3(3#\$) + 28(/ ) (#\$) + 56(/ ) (#\$) + 70(/ ) (#\$) +56(/ ) (#\$) + 28(/ ) (#\$) + 8(/ )(#\$)3 + (#\$) =/ + 8/ % #\$ + 28(/% )(# \$ ) + 56(/% )(# \$ ) + 70(/ % )(# \$ )+56(/ * )(# \$ ) + 28(/ )(# \$ ) + 8(/ )(#3 \$3) + (# \$ ) = + =- + +- " + +- " + - " +, - " + - " , , + ++ +- " + +- " + " <12.- (3− )12.- (3 >D >D >D >D >D(3)* − 9(3) (− ) + 36(3)3 (− ) − 84(3) (− ) + 126(3) (− ) − 126(3) (− ) + >D >D >D >D84(3) (− ) − 36(3) ( )3 + 9(3) (− ) − (− )* = >D >E >F >G >HI >HD >HE19683 − 59049 + 78732 * − 61236 3 + 30618 % −10206 + 2268 3 * − 324 %3 + 27>HF >HG % − %* =
4. 4. + + +R= 19683 − 19683 + 8748 − 2268 + 378 – 42 + − , + − +13.- (1−13.- (1 9 ) % % % % %(1)%& − 10(1)* (− ) + 45(1) (− ) − 120(1)3 (− ) + 210(1) (− ) − 252(1) (− ) + J J J J J % % % % %210 (1) (− J) − 120 (1) (− J)3 + 45(1) (− J) − 10(1) (− J)* + (− J)%& = % % % % % % % % % %1 − 10 + 45 D − 120 + 210 − 252 L + 210 F − 120 M + 45 G − 10 N + = J J JK JE J J J J J JHIR= 1 − 9 +9 − 9 + 9 − 9 + 9 − 9, + 9+ − 9 + 9 .O − " P =(2# ) + 6(2# ) (−5\$ ) + 15(2# ) (−5\$ ) + 20(2# ) (−5\$ ) + 15(2# ) (−5\$ ) +6(2# )(−5\$ ) + (−5\$ )64#% + 6(32#%& )(−5\$ ) + 15(16# )(25\$%& ) + 20(8# )(−125\$% ) + 15(4# )(625\$ & ) +6(2# )(−3125\$ ) + 15625\$ & + = − " + " − " + , " − , " + " - .( − ), = @ @ @ @ @43 + 7( ) Q− R + 21(%) (− ) + 35( ) (− ) + 35( ) (− ) + 21( ) (− ) + % % % % @ @7( )(− ) + (− )3 % @ @ %& @% @ &16384 + 7(4096) Q− R + 21(1024) Q% R + 35(256) Q− R + 35(64) Q R+ @ @ & @21(16) Q− R + 7(4) Q R−% %& &* - - ,- - = + −, +- + - − - + − + − +