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# Kites team l2

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### Kites team l2

1. 1. Structure lecture2
2. 2. 1-Axial loads only 2-Loads applies at end points only 3- Elements are joined by pins only
3. 3. 1-Determine the force in each member of the truss ?         0 1 0 2 0 3 2 tan tan 3 tan 0 4 3 X X X Y Y Y A Y Y X X Y F A B P F A B M B L Ph B h B L B B                          
4. 4. 2-Determine the force in each member of the truss and indicate whether the the members are in tension or compression ? 1 1 2 2 2 2 3 2 3 22 2 0 0 0 0 ( ) 0 ( ) 0 ( ) X X X Y Y Y Y Y A Y Y F A P A P Ph F A B A B L Ph M Ph B L B L Ph Ph F F Tension L L F P F P Tension F L h L F F F Compression Lh L                                            
5. 5. 3-Determine the force in each member of the truss and indicate whether the the members are in tension or compression ? 0 600 0 400 400*3 600*4 *6 0 600 200 X X Y Y Y C Y Y Y F C N F A C M A A N C N                  
6. 6. At joint A At joint C At joint D 1 2 2 2 1 3 0 5 4 600 0 5 600*5 750 ( ) 4 3 750 450 ( ) 5 X Y F F F F F F N Compression F N Tension                                  4 5 0 600 ( ) 0 200 ( ) X Y F F N Compression F F N Compression             3 3 0 3 450 600 250 ( ) 5 XF F F N Tension             
7. 7. 4-Determine the force in each member of the truss and indicate whether the the members are in tension or compression ? At joint B At joint C At joint A 0 500 sin 45 0 707.1 ( ) 0 45 0 500 ( ) X BC BC Y BC BA BA F N F N F N Compression F F Cos N F F N Tension                 0 707.1 45 0 500 ( ) 0 707.1 45 0 500 X CA CA Y Y Y F F Cos N F N Tension F C Sin N C N                  0 500 0 500 0 500 0 500 X X X Y Y Y F N A A N F N A A N                
8. 8. * 1 1 3 2 1 1 3 2 2 2 2 22 2 2 2 2 2 1 3 1 3 0 0 0 0 0 ( ) 0 X Y Y Y C Y Y F P F F F Cos L P F F F h L F h D P F h L h L F P D h M D L P h F h P h D L F h                                              
9. 9. 6-Determine the force in each member of the truss and indicate whether the the members are in tension or compression ? 1 Method of joints : we willbegainbyanalzingthe equilibrium of joint D , and then proceed to analyze joints Cand D 1 tan 26.57 2 At joint D 0 600 26.57 0 1341.64 ( ) 0 X DC DC Y F F Sin F N Compression F                     / / 1341.64 26.57 0 1200 ( ) At joint C 0 26.57 0 0 0 1341.64 ( ) At joint E 0 900 45 0 1272.79 ( ) 0 1200 1272.79 45 0 DE DE X CE CE Y CB X EB EB Y EA EA Cos F F N Tension F F Cos F F F N Compression F F Sin F N Compression F Cos F F                                2100 ( ) Note , the equilibrium analysis of joint Acan be used to determine the components of supports reaction atA N Tension