Series ac circuit

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Academic Presentation Based on Series AC circuit

Academic Presentation Based on Series AC circuit

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  • 1. WELCOME
  • 2. GROUP 11 Robiul Awal Robi Abdul Wahid Abu Jauad Khan Aliv 11105092 11105197 11105137
  • 3. Presentation Going On …  Series Ac Circuit  R-L Series Circuit  R-C Series Circuit  R-L-C Series Circuit
  • 4. RL Series Circuit
  • 5. RL Series Circuit • The total voltage in a series RL circuit is given by this equation: • VT = total voltage VR = voltage across resistor R VL = voltage across inductor L  The total voltage is NOT equal to the sum of the voltages across the resistor and inductor  The sum of voltages is always greater than the sum of the voltages across the resistive and inductive components
  • 6. ANALYSIS of RL Calculate the value of XL: XL = 2∏fL Calculate the Equation  Alternating total impedance: • v = vm sin ωt  IT = VT / Z • i = Im sin ( ωt – ф )  VR = RIR , VL = XLIR  Calculate the total phase angle for the circuit: ф = tan-1(XL/ R)
  • 7. RC Series Circuit
  • 8. Analysis of RC • The total voltage in a series RC  circuit is givenCEquation Here VR=IR , V =IXthis equation: Alternating by C  Impedence:sin ωt • v=v m • i = Im sin ( ωt + ф )  phase angle: Ø=tan-1XC/R
  • 9. RLC Series Circuit
  • 10. ANALYSIS of RLC CONDITION  V2series = V2R + (VL - VC)2  If XL>XC : Now VR = IR, VL = IXL = IωL and VC = IXC= I/ωC. Phase angle Ǿ is positive Substituting and taking the common factor I gives: Circuit is Positive  If XC>XL : Phase (XL - XC 2 Zseries2 = R2 +angle)Ǿ is Negative Circuit is Negative The angle by which the voltage leads the current is φ = tan-1 ((VL - VC)/VR) Substituting VR = IR, VL = IXL = IωL VC = IXC= I/ωC gives:
  • 11. Special Case XL=XC Circuit is purely resistive Phase angle Ǿ=0
  • 12. SOURCES • http://forum.allaboutcircuits.com/blog.php • http://www.allaboutcircuits.com/vol_1/index. html • Book: V.K Mehta
  • 13. QUESTION SESSION
  • 14. • Contact: 01672462007 • Country : Bangladesh