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Academic Presentation Based on Series AC circuit

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- 1. WELCOME
- 2. GROUP 11 Robiul Awal Robi Abdul Wahid Abu Jauad Khan Aliv 11105092 11105197 11105137
- 3. Presentation Going On … Series Ac Circuit R-L Series Circuit R-C Series Circuit R-L-C Series Circuit
- 4. RL Series Circuit
- 5. RL Series Circuit • The total voltage in a series RL circuit is given by this equation: • VT = total voltage VR = voltage across resistor R VL = voltage across inductor L The total voltage is NOT equal to the sum of the voltages across the resistor and inductor The sum of voltages is always greater than the sum of the voltages across the resistive and inductive components
- 6. ANALYSIS of RL Calculate the value of XL: XL = 2∏fL Calculate the Equation Alternating total impedance: • v = vm sin ωt IT = VT / Z • i = Im sin ( ωt – ф ) VR = RIR , VL = XLIR Calculate the total phase angle for the circuit: ф = tan-1(XL/ R)
- 7. RC Series Circuit
- 8. Analysis of RC • The total voltage in a series RC circuit is givenCEquation Here VR=IR , V =IXthis equation: Alternating by C Impedence:sin ωt • v=v m • i = Im sin ( ωt + ф ) phase angle: Ø=tan-1XC/R
- 9. RLC Series Circuit
- 10. ANALYSIS of RLC CONDITION V2series = V2R + (VL - VC)2 If XL>XC : Now VR = IR, VL = IXL = IωL and VC = IXC= I/ωC. Phase angle Ǿ is positive Substituting and taking the common factor I gives: Circuit is Positive If XC>XL : Phase (XL - XC 2 Zseries2 = R2 +angle)Ǿ is Negative Circuit is Negative The angle by which the voltage leads the current is φ = tan-1 ((VL - VC)/VR) Substituting VR = IR, VL = IXL = IωL VC = IXC= I/ωC gives:
- 11. Special Case XL=XC Circuit is purely resistive Phase angle Ǿ=0
- 12. SOURCES • http://forum.allaboutcircuits.com/blog.php • http://www.allaboutcircuits.com/vol_1/index. html • Book: V.K Mehta
- 13. QUESTION SESSION
- 14. • Contact: 01672462007 • Country : Bangladesh

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